Mathematics High School

The ratio of the number of girls to the number of boys was 3 to 5 . of 2,520 were presented, how many were girls and how many were boys

Answers

Answer 1
girls to boys...3 to 5.....added = 8

3/8(2520) = 7560/8 = 945 girls <==
5/8(2520) = 12600/8 = 1575 boys <==
Answer 2

There were 945 girls and 1575 boys respectively.

What is the ratio of two quantities?

Suppose that we've got two quantities with measurements as 'a' and 'b'

Then, their ratio(ratio of a to b) a:b or a/b

We usually cancel out the common factors from both the numerator and the denominator of the fraction we obtained. The numerator is the upper quantity in the fraction and the denominator is the lower quantity in the fraction). Remember that the ratio should always be taken of quantities with the same unit of measurement. Also, the ratio is a unitless(no units) quantity.

We have been given that the ratio of the number of girls to the number of boys was 3 to 5.

The ratio girls to boys;

3 to 5

The Total = 8

The number of boys was 3 to 5 . of 2,520, Then;

3/8(2520) = 7560/8

girls = 945  

5/8(2520) = 12600/8

boys = 1575

Therefore, there were 945 girls and 1575 boys respectively.

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Related Questions

In two or more complete sentences, compare the number of x-intercepts in the graph of f(x) = x2 to the number of x-intercepts in the graph of g(x) = -(x-4)2. Be sure to include the transformations that occurred between the parent function f(x) and its image g(x).

Answers

There is only one x-intercept for f(x) and g(x), f(x) having a minimum value of zero and g(x) having a maximum value of zero. f(x)=0 when x=0, g(x)=0 when x=4.

g(x) is f(x) reflected about the about the x-axis and shifted to the right by 4 units. 
Since x^2 = 0 implies x = 0 with multiplicity 2, there is one x-intercept
Since -x^2-5 = 0 implies x = +-sqrt(5)i, there are no x-intercepts
Transformations:
Reflect f(x) in the x-axis,
then vertically shift the result down by 5 units,
to get g(x).

Consider the leading term of the polynomial function. What is the end behavior of the graph? Describe the end behavior and provide the leading term.
-3x^5 + 9x^4 + 5x^3 + 3

Answers

The leading term is -3x^5.  The end behavior of any function is the behavior that the highest powered term has as x approaches ±oo.

In this case because the highest order term is -3x^5, as x approaches -oo, y approaches +oo.  And as x approaches +oo, y approaches -oo.

enter an equation in slope-intercept form that describes a line that contains the points (4,1) and (4,2)

Answers

[tex]\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 4}}\quad ,&{{ 1}})\quad % (c,d) &({{ 4}}\quad ,&{{ 2}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{2-1}{4-4}\implies \cfrac{1}{0}\leftarrow unde fined[/tex]

so... the slope is undefined, the graph of it is just a vertical line, check the picture below, and that's the equation.

now... you can't quite put it in y = mx + b, or slope-intercept form, since it has no defined slope and it doesn't have an y-intercept either.

What percent of 210 is 70?

Answers

if we take 210 to be the 100%, what is 70 off of it in percentage then?

[tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 210&100\\ 70&x \end{array}\implies \cfrac{210}{70}=\cfrac{100}{x}\implies x=\cfrac{70\cdot 100}{210}[/tex]
percent means parts out of 100
so x%=x/100

'of' means multiply

so

what percent of 210 is 70 translates to
x/100 times 210=70
210x/100=70
21x/10=70
times 10 both sides
21x=700
divide both sides by 21
x=33.333333


33.33333333% of 210 is 70

HOW DO YOU MOVE A VARIABLE FROM ONE SIDE OF AN EQUATION TO ANOTHER? I need to know as I'm reviewing module 7 algebra and i want to know please

Answers

The easiest way to do this is to add or subtract the value of the variable.
For example in the equation 5+a=7, subtract a from both sides to get 5=7-a.
If the initial equation was 5-a=7, add from both sides (5=a+7).
Basically, if the initial value is negative, add its value to cancel to zero.
Do the opposite if the initial value is positive.

Point r is located at (3,0). point s is located at (0,-4). what is the equation of the line through these two points

Answers

(3,0)(0,-4)
slope = (-4 - 0) / (0 - 3) = -4/-3 = 4/3

y = mx + b
slope(m) = 4/3
(0,-4)....x = 0 and y = -4
now we sub and find b, the y int
-4 = 4/3(0) + b
-4 = b
so ur equation is : y = 4/3x - 4....or 4x - 3y = 12 <==

Redo, Answers please?

Answers

11) ?=12
10) ?=13
14) ?=13
11)

11+15+13 = 39

39 - 27 = 12

so 

answer
? = 12

10)

18 - 11 + 13 = 20

33 - 20 = 13

so 

answer

? = 13

14)

16+17+12=45

45 - 27 = 18

answer

? = 18

A carnival ride is in the shape of a wheel with a radius of 20 feet. The wheel has 16 cars attached to the center of the wheel. What is the central angle, arc length, and area of a sector between any two cars? Round answers to the nearest hundredth if applicable. You must show all work and calculations to receive credit.

Answers

Refer to the diagram shown below, which shows two of 16 equally-spaced cars attached to the center of the wheel.

The total central angle around the wheel is 2π.
Therefore the central angle between two cars is
(2π)/16 = π/8 = 0.39 radians (nearest hundredth)

The arc length between two cars is
s = (20 ft)*(π/8 radians) = 2.5π = 7.85 ft (nearest hundredth)

The area of a sector formed by two cars is
(1/16)*(π*20²) = 78.54 ft² (nearest hundredth)

Answers: (to the nearest hundredth)
Between two cars,
Central angle = 0.39 radians (or 71.4°)
Arc length = 7.85 ft
Area of a sector = 78.54 ft²


Refer to the diagram shown below, which shows two of 16 equally-spaced cars attached to the center of the wheel.

The total central angle around the wheel is 2π.

Therefore the central angle between two cars is

(2π)/16 = π/8 = 0.39 radians (nearest hundredth)

The arc length between two cars is

s = (20 ft)*(π/8 radians) = 2.5π = 7.85 ft (nearest hundredth)

The area of a sector formed by two cars is

(1/16)*(π*20²) = 78.54 ft² (nearest hundredth)

Answers: (to the nearest hundredth)

Between two cars,

Central angle = 0.39 radians (or 71.4°)

Arc length = 7.85 ft

Area of a sector = 78.54 ft²

How do I set up this equation and solve ?

Answers

angles in a triangle need to equal 180 degrees

 so x = 180 - 47 - 58

x = 180-105

 x= 75 degrees

If BC = 5 and CD = 26, find AC.

Answers

Answer:

[tex]AC=\sqrt{130}[/tex]

Step-by-step explanation:

AC is the geometric mean.  Solve it using this proportion:

[tex]\frac{BC}{AC}=\frac{AC}{CD}[/tex]

Now fill in the values we know:

[tex]\frac{5}{AC}=\frac{AC}{26}[/tex]

Cross multiply to get

[tex](AC)^2=130[/tex]

That means that

AC = [tex]\sqrt{130}[/tex], which, in decimal form is

AC = 11.40175425

In two or more complete sentences, compare the number of x-intercepts in the graph of f(x) = x2 to the number of x-intercepts in the graph of g(x) = -x2 -6. Be sure to include the transformations that occurred between the parent function f(x) and its image g(x).

Answers

f(x) has only one x-intercept when x=0

g(x)=-x^2-6

g(x)=-(x^2+6) so g(x) will have no x-intercepts as its maximum value will be -6.

g(x) is f(x) reflected about the x axis and shifted downwards by 6 units.

what is larger 0.0013 or 0.02

Answers

.02 because there are less 0's after the decimal place. 
0.02>0.0013 because if we compare the hundredth place of these two numbers, we could see that 0.02>0.00... As a result, 0.02 is larger than 0.0013. Hope it help!

Smallville’s town council has records of the town’s budget over a 10-year period. Create a best fit and model for the data. What does the model predict the town’s budget will be in the year 2011?

Answers

I found the missing image and choices.
If these were the missing choices:

A)$391,000

B)$417,000

C)$404,000

D)$411,000

My answer is D) $411,000 in 2011.

There is an average increase of 4% from the previous budget to arrive at the amount of the current year. 

2009 budget $381,700

381,700 * (1.04)² = 381,700 * 1.0816 = 412,846.72  only Choice D. is nearest to the amount

2000 budget $265,100

265,100 * (1.04)¹¹ = 265,100 * 1.540 = 408,254 only Choice D. is nearest to the amount.





Match the perfect square trinomials with their factors 4a2 + 4a + 1 (2 + a)(2 + a) 4a2 − 4a + 1 (2a + 1)(2a + 1) 4 − 4a + a2 (2a − 1)(2a − 1) 4 − 4a − a2 (2 − a)(2 − a) 4 + 4a + a2

Answers

4a2 + 4a + 1 = (2a +1)^2 = (2a + 1)(2a + 1)
4 − 4a + a2  = (2 - a)^2 = (2 − a)(2 − a)
4a2 − 4a + 1 = (2a -1)^2 = (2a − 1)(2a − 1)
4 + 4a + a2 = (2 + a)^2 = (2 + a)(2 + a) 

Write a possible function rule for the following sequence.

11, 15, 19, 23, 27, ...

a(n)=?

Answers

a(n) = 4(n - 1) + 11 is the equation because a(1) = 11 and the common difference (d) = 4. Then you just plug it into the arithmetic sequence formula which is a(n) = d(n - 1) + a(1). I hope this was helpful.
This is an arithmetic sequence because a common difference exists.  The common difference is a constant found when taking any term and subtracting the previous term from it.  In this case the common difference is 4, meaning that each term is 4 units greater than the previous term.  Any arithmetic sequence can be expressed as:

a(n)=a+d(n-1), a=initial term, d=common difference, n=term number

In this case we know a=11 and d=4 so

a(n)=11+4(n-1)  which can be simplified...

a(n)=11+4n-4

a(n)=4n+7

The population of a type of local frog can be found using an infinite geometric series where a one equals 84 and the common ratio is one over five find the sum of the infinite series that will be the upper limit of this population. 87,105,425, or this series is divergent

Answers

a=84 and r=1/5

Since r, the common ratio squared is less than one, the sum will converge to a limit.  Rule:  if  r^2<1 infinite series converges, otherwise it diverges.

Since the sum of any geometric sequence is:

s(n)=a(1-r^n)/(1-r)

And if r^2<1, (1-r^n) becomes 1-0=1 as n approaches infinity.

So whenever r^2<1 the sum of the infinite series is just:

s(n)=a/(1-r)

Since a=84 and r=1/5 this infinite series has a sum of:

s(n)=84/(1-1/5)

s(n)=84/(4/5)

s(n)=5(84)/4

s(n)=105

Find the area under the standard normal curve between z = -1.5 and z = 2.5

Answers

Final answer:

To area under the standard normal curve between z = -1.5 and z = 2.5 is 0.927

Explanation:

A standard normal curve, also known as the standard normal distribution, is a bell-shaped, symmetrical probability distribution with a mean of 0 and a standard deviation of 1. It serves as a reference for many statistical analyses and is often denoted as the Z-distribution.

To find the area under the standard normal curve between z = -1.5 and z = 2.5, we need to use the z-table. The z-score of -1.5 corresponds to an area of 0.0668 and the z-score of 2.5 corresponds to an area of 0.9938. To find the area between these two z-scores, we subtract the smaller area from the larger area:

= 0.9938 - 0.0668

= 0.927

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The area between these z-scores is 0.9270.

The area under the standard normal curve between z = -1.5 and z = 2.5 can be found using the z-table.

First, find the area to the left of

z = -1.5, which is 0.0668.

Next, find the area to the left of

z = 2.5, which is 0.9938.

Subtract these two values to get the area between z = -1.5 and z = 2.5 :

0.9938 - 0.0668

 = 0.9270.

Divide 35b^5 +20ab^3 +20a^2b^2 by 5b^2

Answers

Basically, you just divide each term in the equation by b^2.
So 35b^5 / b^2 = 35b^3, 30ab^3 / b^2 = 30ab, and 20a^2b^2 / b^2 = 20a^2.
So your final answer is 35b^3 + 30ab + 20a^2.

The vertical ______ of the function secant are determined by the points that are not in the domain.

Answers

The word that goes in the blank is asymptote.

3!3! = 362,880 81 36

Answers

3! = 3*2*1

3!3! = 3*2*1*3*2*1 =  6*6 = 36
The answers 36. Hope this helps.
3! ----) 3 . 2 . 1  ----------) 3!3! = 36

When 332 college students are randomly selected and surveyed, it is found that 113 own a car. find a 99% confidence interval for the true proportion of all college students who own a car?

Answers

Given:
n = 332, sample size
p = 113/332 = 0.3404, sample proportion
99% confidence interval

The confidence interval for the population is calculated from
[tex]p \pm z^{*} \sqrt{ \frac{p(1-p)}{n} } [/tex]
where z* = 2.58 for the 99% confidence level (from tables)..

[tex]2.58 \sqrt{ \frac{0.3404(1-0.3404)}{332} } =0.0671[/tex]
Therefore the 99% confidence interval is
(0.3404 - 0.0671, 0.3404 + 0.0671) = (0.2733, 0.4075)

Answer:
The 99% confidence interval is (0.273, 0.408) or (27%, 41%).
That is, between 27% and 41% of the students own cars.

if you subtract 23.47 km from 560.589 km, how many significant digits would your answer have?

Answers

560.589 - 23.47 is hmm 537.119  <---- 6 significant digits

alrite... looks good, however, when it comes to dealing with significant digits, for addition/subtraction, we go with the lowest significant amount for decimals, in this case,

560.589  <--- has 6 significant digits, accurate to the 1000th place
23.47     <--- has 4 significant digits, and is accurate to the 100th place

thus, our answer will have to be rounded up in 2 significant decimals, or 537.12
and that only has 5 significant digits, since is rounded up to the 100th place.

A particular metal alloy a has 20% iron and another alloy b contains 60% iron. how many kilograms of each alloy should be combined to create 80 kg of a 52% iron alloy?

Answers

Let t and s represent the masses of 20% and 60% alloys respectively.

t+s=80, s=80-t

(0.2t+0.6s)/80=0.52  multiply both sides by 80

0.2t+0.6s=41.6, now using s=80-t in this equation gives us:

0.2t+0.6(80-t)=41.6  perform indicated multiplication on left side

0.2t+48-0.6t=41.6  combine like terms on left side

-0.4t+48=41.6  subtract 48 from both sides

-0.4t=-6.4  divide both sides by -0.4

t=16, since s=80-t

s=64

So 16kg of 20% alloy is mixed with 64kg of 60% allow to make 80kg of a 52% alloy.

The circle given by x^2+y^2-4x-10=0 can be written in standard form like this: (x-h)^2+y^2=14. What is the value of h in this equation??

Answers

Answer: H=2

Step-by-step explanation:

we just need to complete the square for the x terms

gropu x terms

x^2-4x

take 1/2 of linear coefient and square it

-4/2=-2, (-2)^2=4

x^2-4x+4

factor

(x-2)^2

h=2

The value of h is 2.

Completing the square for the x terms by grouping x terms

x^2-4x

Taking 1/2 of linear coefficient and squaring it.

-4/2=-2, (-2)^2=4

x^2-4x+4

Factorizing the equation.

(x-2)^2

h=2.

What is an equation?

An equation is a mathematical statement this is made of two expressions related with the aid of an identical sign. As instance, 3x – 5 = 16 is an equation. To fix this equation, we get the value of the variable x as x = 7.

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How many cans of paint are needed to cover an area of 2,200 square units if one can of paint covers an area of 400 square units? 4 5 6 8?

Answers

In this case, one can of paint can covers an area of 400 square units. You are asked how much cans needed to cover an area of 2,200 square units.

Then you just need to divide 2,200 square units with 400 square units.
The equation will be : (2,200 square units / 400 square units) x 1 can=  4.5 cans
After you round up the result it would be 5 cans.

Answer: 5 cans

Simplify 5 − (−1).

a. 6
b. −6
c. 4
d. −4

Answers

Hi!

Subtracting a negative number is the same as adding a positive.

So instead of

5 - (-1)

We could write

5 + 1

5 + 1 = 6

The answer is 6.

Hope this helps! :)

Answer: it is  a

Step-by-step explanation: :) :v :B

4n-3<12 solve and please don't give me the answer just the equation

Answers

just as with an equation with an = sign, we want to isolate the variable, n.
So first bring -3 to the right hand side:

4n-3<12 => 4n < 12+3 => 4n < 15

Then divide by 4

4n/4 < 15/4 => n < 15/4

You can't simplify it beyond that.

Yana is using an indirect method to prove that segment DE is not parallel to segment BC in the triangle ABC shown below: A triangle ABC is shown. D is a point on side AB and E is a point on side AC. Points D and E are joined using a straight line. The length of AD is equal to 4, the length of DB is equal to 5, the length of AE is equal to 6 and the length of EC is equal to 7. She starts with the assumption that segment DE is parallel to segment BC. Which inequality will she use to contradict the assumption? 4:9 ≠ 6:13 4:9 ≠ 6:7 4:13 ≠ 6:9 4:5 ≠ 6:13

Answers

Please see attached file for the triangle’s figure:

 

Going with the image attached, if DE is parallel to BC
then
4: (4 + 5) = 6 : (6 + 7).

Therefore, the inequality that she will use to contradict the assumption is 4:9 ≠ 6:13.

To add, a relation that holds between two values when they are different in mathematics is called an inequality. A is not equal to b also means the notation a ≠ b.



Inequalities are governed by the following properties:

Transitivity
 Converse
 Addition and subtraction
 Multiplication and division
 Additive inverse
 Multiplicative inverse
Applying a function to both sides

Answer:

4:9 ≠ 6:13.

Step-by-step explanation:

Which of the following relations represent a function? {(1,-3),(-2,0),(1,4)} {(-2,0),(3,0),(-2,1)} {(3,-8),(-2,0),(4,1)} {(4,12),(4,13),(-4,14)}

Answers

that means no x repeats with a different y

example
(1,2) and (1,4) would not be a function

but (1,2) and (3,2) is


no firs tnumber repeats

first one, 1 repeats with -3 and 4
2nd one, -2 repeatts with 0 and 1
3rd one, no repeats
4th one, 4 repeats with 12, 13, 14

answer is 3rd one or
{(3,-8),(-2,0),(4,1)}
Final answer:

To determine if a relation is a function, check for repeated x-values. The relations that represent a function are {(1,-3),(-2,0),(1,4)} and {(3,-8),(-2,0),(4,1)}.

Explanation:

In order for a relation to represent a function, each input (x-value) must correspond to exactly one output (y-value). We can determine if a relation is a function by checking for any repeated x-values. If there are no repeated x-values, then the relation is a function. Let's apply this to the given relations:

The relation {(1,-3),(-2,0),(1,4)} represents a function because each x-value is unique.

The relation {(-2,0),(3,0),(-2,1)} does not represent a function because there is a repeated x-value (-2).

The relation {(3,-8),(-2,0),(4,1)} represents a function because each x-value is unique.

The relation {(4,12),(4,13),(-4,14)} does not represent a function because there is a repeated x-value (4).

So, the relations that represent a function are {(1,-3),(-2,0),(1,4)} and {(3,-8),(-2,0),(4,1)}.

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Which translation will change figure ABCD to figure A'B'C'D'?

A. 7 units left and 6 units up
B. 6 units left and 7 units up
C. 7 units left and 5 units up
D. 5 units left and 7 units up

Answers

answer is A. 7 units left and 6 units up
7 units left, 6 units up
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