Simplify √24

A 3√8

B 2√12

C 2√6

D 4√6

Answer:

A. 90° clockwise rotation around point A of pre-image JKL

Step-by-step explanation:

May I have brainliest please? :)

Final answer:

To represent the number of campers attending the camp, use the equation y = mx + c, where y represents the number of campers, m represents the rate of increase, x represents the number of years, and c represents the initial number of campers. Using the given information, solve for the rate of increase (m) and initial number of campers (c). Substitute the values in the equation to find the number of campers attending the camp right now.

Explanation:

To represent the number of campers attending the camp right now, we can use the equation: y = mx + c, where y represents the number of campers attending the camp, m represents the rate at which the number of campers increase, x represents the number of years since 2005, and c represents the initial number of campers in 2005.

From the information provided, we know that in 2005 there were 450 campers and five years later, in 2010, the number of campers rose to 750. We can use these two points to find the values of m and c.

Using the formula: (y2 - y1) / (x2 - x1) = m, we can calculate the value of m as: (750 - 450) / (2010 - 2005) = 60. Therefore, the rate of increase is 60 campers per year. Now, we can substitute the values of m and c in the equation to find the number of campers attending the camp right now. y = 60x + 450.

The linear equation representing the number of campers attending camp each year, starting from 2005 with 450 campers and increasing by 60 campers per year, is C = 450 + 60t, where C is the number of campers and t is the number of years after 2005.

In 2005, there were 450 campers at a camp. Five years later, the number of campers increased to 750. To represent the growth in the number of campers, we can write a linear equation. Assuming the number of campers increases at a constant rate each year, we first find the rate of increase.

Rate of increase per year = (Number of campers in 2010 - Number of campers in 2005) / (2010 - 2005)

Rate of increase per year = (750 - 450) / (5)

Rate of increase per year = 300 / 5 = 60 campers per year

Let's denote C as the number of campers and t as the number of years after 2005. The equation that represents the number of campers is:

C = 450 + 60t

This equation indicates that starting with 450 campers in 2005, every year there are 60 more campers attending the camp.

The cost function is a linear function that represents the relationship between the total cost and total output. The equation C(x) = $200 + $3600x/20 represents the cost function in this case.

The cost function is a linear function that represents the relationship between the total cost and total output. In this case, the fixed costs are $200 per day, meaning they do not depend on the output. The total costs per day, C(x), can be expressed as the sum of fixed costs and variable costs:

C(x) = FC + VC(x)

Given that the total costs are $3800 per day for a daily output of 20 boards, we can write the equation as:

$3800 = $200 + VC(20)

Now, we can solve for VC(20) to find the variable cost:

VC(20) = $3800 - $200 = $3600

Therefore, the cost function equation is C(x) = $200 + $3600x/20, where x represents the total output per day.

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In the given sets, the concept AB + BC = AC is used to create equations in terms of x. After each equation is solved, you can find the lengths of AB and BC by substituting the value of x into their respective original equations.

For this mathematics problem, you have to make use of the concept that the sum of the parts equals the whole. Specifically, this concept translates to the equation AB + BC = AC, as AC is the entire segment that encompasses both parts AB and BC.

For each of the sets you provided:

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Answer:

a

Step-by-step explanation:

Final answer:

Josephine will need at least 13 full weeks to start making a profit. The correct inequality that models this economic scenario is 550w > 4500 + 200w.

Explanation:

The minimum number of weeks it will take for Josephine to make a profit in her cosmetics business can be determined by setting up an inequality where the total earnings must be greater than the sum of the initial investment and the running costs. We define w as the number of weeks. Josephine earns $550 per week, so her earnings after w weeks are 550w. The initial investment is $4500 and the weekly expense is $200, so the total expenses after w weeks are 4500 + 200w. To make a profit, the earnings must be greater than the expenses:

550w > 4500 + 200w

To solve for w, we need to collect like terms:

550w - 200w > 4500

350w > 4500

Dividing both sides by 350:

w > 4500 / 350

w > 12.86

This means Josephine will need to work for at least 13 full weeks to make a profit.

Answer:

[tex]3\frac{5}{9}[/tex] cups of milk and [tex]\frac{1}{3}[/tex] cups of oil for 8 people .

Step-by-step explanation:

Cups of milk for 6 people = [tex]2 \frac{2}{3} =\frac{8}{3}[/tex]

Cups of milk for 1 people = [tex]\frac{\frac{8}{3}}{6}=\frac{4}{9}[/tex]

Cups of milk for 8 people = [tex]\frac{4}{9} \times 8= \frac{32}{9}[/tex]

Cups of oil for 6 people = [tex]\frac{1}{4}[/tex]

Cups of oil for 1 people = [tex]\frac{\frac{1}{4}}{6}= \frac{1}{24}[/tex]

Cups of oil for 8 people = [tex]\frac{8}{24}=\frac{1}{3}[/tex]

Hence [tex]3\frac{5}{9}[/tex] cups of milk and [tex]\frac{1}{3}[/tex] cups of oil for 8 people .

To find h'(x), differentiate the function h(x) = (cos x)/f(x) using the product rule.

To find h'(x), we need to differentiate the function h(x) = (cos x)/f(x).

First, let's find the derivative of cos x, which is -sin x.

Next, we need to find the derivative of f(x). Since f(π/3) = 3 and f '(π/3) = −7, we know the slope of the tangent line at x = π/3 is -7.

Using the product rule, we can now differentiate h(x) = (cos x)/f(x) as follows:

h'(x) = [f(x)(-sin x) - cos x(f '(x))]/[f(x)]^2

The correct answer is:C. 1,092 people per square mile

To calculate the population density of a state, we divide the total population by the total area. In this case, the state has 1,627,260 people living within 1,490 square miles. We perform the following calculation:

Population Density = Total Population / Total Area

Population Density = 1,627,260 people / 1,490 square miles

When we perform the division, we get approximately 1092.12 people per square mile. Rounding to the nearest whole number, we get a population density of 1,092 people per square mile.

Therefore, the correct answer is:C. 1,092 people per square mile

Answer:

The answer is b. 5 feet

Step-by-step explanation:

Answer:

A tangent is a line, ray, or line segment that intersects a circle at exactly one point (called the point of tangency) and contains no points inside the circle. A chord is a segment with both endpoints on a circle. Tangents intersect the circle at one point, while a chord intersects at two.

I've checked this answer, E counted it as correct. Hope this helped!!!

A tangent touches a circle at one point, while a chord connects any two points on the circle's circumference.

A tangent and a chord are both important concepts in geometry, but they have distinct characteristics.

A tangent is a line that intersects a circle at exactly one point, touching the circle's circumference at that point.

It never crosses the circle. Tangents are perpendicular to the radius that intersects the point of tangency.

On the other hand, a chord is a line segment connecting any two points on a circle's circumference. Unlike tangents, chords can intersect the circle at multiple points.

The diameter is a special case of a chord that passes through the center of the circle.

Hence,

Tangents touch a circle at one point, while chords connect two points on a circle's circumference.

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Answer:

Simultaneous Equation

Step-by-step explanation:

A bag contains 18 coins consisting of quarters and dimes. The total value of the coins is $2.85. Which system of equations can be used to determine the number of quarters, q, and the number of dimes, d, in the bag?

To get the number of dimes and the number of quarters q will definitely have to be by simultaneous equation

let the number of dimes be d

let the number of quarters be q

let the cost of quarters/ one  be Q

let the cost of dime/one be  D

q+d=18--------------1

Qq+Dd=2.85.........2

from equation 1

q=18-d

substituting the value of q into equation 2

Q(18-d)+Dd=2.85

if cost of quarters/ one  is given and the cost of dime/one is also given we can go ahead to find

q and d

In this mathematical problem involving a system of equations, we use the information provided about the total number of coins and their total value to form two equations: q + d = 18 and 0.25q + 0.10d = 2.85.

The subject of this question is Mathematics, specifically dealing with a system of equations. Given the problem, the system of equations can be formulated from the conditions that the student has 18 coins in total and their combined value is $2.85. These conditions give us two equations:

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The correct equation to model the rectangle's area where the length is 3 inches more than the width and the area is 70 square inches is W(W + 3) = 70, which simplifies to W^2 + 3W = 70.

The student is asking for the correct equation to model a rectangle's area where the length (L) is 3 inches more than the width (W), and the area is 70 square inches. To find an equation that models the situation, we need to express L in terms of W. Since L is 3 inches more than W, we can write L as W + 3. The area (A) of a rectangle is found by multiplying the length by the width, so A = L x W.

Therefore, the equation that models this situation is W(W + 3) = 70. To see why, let's insert the expression for L into the area formula:

A = L x W = (W + 3) x W

This simplifies to:

A = W^2 + 3W

Since we know the area A is 70 square inches, we substitute and get the equation:

W^2 + 3W = 70

Which is the correct model for the given situation.

Answer:

can confirm that the answer above is correct

hope yall have a nice day

Step-by-step explanation:

Answer:

inverse property

The graphs of the system of equations −5y=2x+3 and y=25x+4 are neither parallel nor perpendicular.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

The system of equations is:

 −5y=2x+3 and y=25x+4

The slope of parallel graphs is the same. The reciprocal slopes of a perpendicular are opposite.

These equations are neither because they have slopes of 25 and -2/5.

Thus, the graphs of the system of equations −5y=2x+3 and y=25x+4 are neither parallel nor perpendicular.

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Answer:

b

Step-by-step explanation:

Answer:

D) Group D

Step-by-step explanation:

A range: 38

B range: 48

C range: 40

D range: 51

The absolute maximum occurs at x = -1, where y = 5. The absolute minimum occurs at x = 1, where y = 1.

To find the absolute extrema of a function on a closed interval, we first need to find the critical points of the function within that interval. The critical points occur where the derivative of the function is equal to zero or does not exist.

In this case, the function is y = 3x^(2/3) - 2x, and the closed interval is [-1, 1].

We can find the derivative of the function:

y' = 2x^(-1/3) - 2

Setting the derivative equal to zero and solving for x:

2x^(-1/3) - 2 = 0

x^(-1/3) = 1

Raising both sides to the power of -3 gives:

x = 1

We found one critical point at x = 1. Now we need to check the endpoints of the closed interval, which are -1 and 1. Evaluating the function at these points:

y(-1) = 3(-1)^(2/3) - 2(-1) = 5

y(1) = 3(1)^(2/3) - 2(1) = 1

Therefore, the absolute maximum of the function occurs at x = -1, where y = 5, and the absolute minimum occurs at x = 1, where y = 1.

To write the inequality 'five less than a number is at least -28' in mathematical symbols, we need to assume the number is 'x' and express 'five less than a number' as 'x - 5'. We then represent 'at least -28' as '≥ -28'. By combining these expressions, we get the inequality x - 5 ≥ -28. To solve it, we add 5 to both sides to isolate the variable 'x' and obtain x ≥ -23.

To write the inequality, we need to translate the phrase 'five less than a number is at least -28' into mathematical symbols. Let's assume the number is represented by 'x'. 'Five less than a number' can be written as 'x - 5'. The phrase 'at least -28' means the number has to be greater than or equal to -28, which can be written as '≥ -28'.

Putting it together, the inequality is: x - 5 ≥ -28.

To solve this inequality, we can add 5 to both sides to isolate the variable 'x'. This gives us: x ≥ -28 + 5, which simplifies to x ≥ -23.

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By squaring both sides and solving for [tex]\(x\),[/tex] we find [tex]\(x = 4\)[/tex] as the solution, which is not extraneous upon substitution into the original equation.

To solve the equation [tex]\(\sqrt{2x + 1} = 3\),[/tex] we need to isolate[tex]\(x\).[/tex] Here's how:

1. Square both sides of the equation to eliminate the square root:

[tex]\[ (\sqrt{2x + 1})^2 = 3^2 \][/tex]

[tex]\[ 2x + 1 = 9 \][/tex]

2. Subtract 1 from both sides to isolate [tex]\(2x\)[/tex]:

[tex]\[ 2x = 9 - 1 \][/tex]

[tex]\[ 2x = 8 \][/tex]

3. Divide both sides by 2 to solve for [tex]\(x\)[/tex]:

[tex]\[ x = \frac{8}{2} \][/tex]

[tex]\[ x = 4 \][/tex]

Now, we have [tex]\(x = 4\)[/tex]. To determine if it's an extraneous solution, we need to check if it satisfies the original equation.

Substitute [tex]\(x = 4\)[/tex] into the original equation:

[tex]\[ \sqrt{2(4) + 1} = 3 \][/tex]

[tex]\[ \sqrt{9} = 3 \][/tex]

[tex]\[ 3 = 3 \][/tex]

Since the equation holds true, [tex]\(x = 4\)[/tex]is a valid solution, not an extraneous one.

Therefore, the solution to the equation [tex]\(\sqrt{2x + 1} = 3\) is \(x = 4\),[/tex]and it is not an extraneous solution.

Tree diagram can be used to represent the sample space. The correct option is option C.

In probability, a tree diagram can be used to represent the sample space. Tree diagrams represent a series of independent events or conditional probabilities.

As it is given that the coin is tossed three times, therefore, the number of stages in the tree diagram will be three, where each time the coin is tossed will result in either heads or tails.

Now, the tree diagram of the coins can be drawn as shown below.

Further, comparing it with our diagram, the only possible option is option c where the number of levels in the tree is three and each toss result in either heads or tails.

Hence, the correct option is option C.

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Answer:

7.2+x=19.5

x=19.5-7.2

x=12.2

your welcome

Step-by-step explanation:

To find the x-intercepts, set the trinomial equal to zero and solve for x. Substitute x = 0 to find the y-intercept.

To find the x-intercepts of a trinomial, you need to set the trinomial equal to zero and solve for x.

In the example given (x^2-10x+25), you would set the trinomial equal to zero as follows:

x^2-10x+25 = 0

Now, you can factor the trinomial or use the quadratic formula to solve for x. In this case, the trinomial can be factored as (x-5)(x-5) = 0.

So, the x-intercept is x = 5.

The y-intercept can be found by substituting x = 0 into the trinomial. In this case, when x = 0, the trinomial becomes y = 25.

So, the y-intercept is (0, 25).

Answer:

[tex]h(x)=2x^2+14x-60[/tex]

Step-by-step explanation:

This question can be solved by two methods

Method 1: Substitute x=3 and x=-10 in all the equations and determine which equals to zero (ie., check h(3)=0 and h(-10)=0 for all the equations)

Equation 1

[tex]h(x)=x^2-13x-30[/tex]

[tex]h(3)=3^2-13(3)-30[/tex]

[tex]h(3)=-60[/tex]

As h(3)≠0, Equation 1 is discounted

Equation 2

[tex]h(x)=x^2-7x-30[/tex]

[tex]h(3)=3^2-7(3)-30[/tex]

[tex]h(3)=-42[/tex]

As h(3)≠0, Equation 2 is discounted

Equation 3

[tex]h(x)=2x^2+26x-60[/tex]

[tex]h(3)=2(3)^2+26(3)-60[/tex]

[tex]h(3)=36[/tex]

As h(3)≠0, Equation 3 is discounted

Equation 4

[tex]h(x)=2x^2+14x-60[/tex]

[tex]h(3)=2(3)^2+14(3)-60[/tex]

[tex]h(3)=0[/tex]

[tex]h(x)=2x^2+14x-60[/tex]

[tex]h(-10)=2(-10)^2+14(-10)-60[/tex]

[tex]h(-10)=0[/tex]

As h(3)=0 and h(-10)=0, Equation 4 represents h(x)

Method 2: Solve to find the roots of each equation where h(x)=0 using the quadratic formula. Roots should be x=3,x=-10

The quadratic formula is:

[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]

where a, b and c are as below

[tex]h(x)=ax^2+bx+c=0[/tex]

Equation 1

[tex]h(x)=x^2-13x-30=0[/tex]

[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\frac{13\±\sqrt{(-13)^2-4(1)(-30)}}{2(1)}[/tex]

[tex]x=15,x=-2[/tex]

As roots are not x=3 and x=-10, Equation 1 is discounted

Equation 2

[tex]h(x)=x^2-7x-30[/tex]

[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\frac{-(-7)\±\sqrt{(-7)^2-4(1)(-30)}}{2(1)}[/tex]

[tex]x=10,x=-3[/tex]

As roots are not x=3 and x=-10, Equation 2 is discounted

Equation 3

[tex]h(x)=2x^2+26x-60[/tex]

[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\frac{-(26)\±\sqrt{(26)^2-4(2)(-60)}}{2(2)}[/tex]

[tex]x=2,x=-15[/tex]

As roots are not x=3 and x=-10, Equation 3 is discounted

Equation 4

[tex]h(x)=2x^2+14x-60[/tex]

[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\frac{-(14)\±\sqrt{(14)^2-4(2)(-60)}}{2(2)}[/tex]

[tex]x=3,x=-10[/tex]

As roots are x=3 and x=-10, Equation 4 represents h(x)