The light-collecting area of a 150-meter telescope would be 225 times greater than that of a 10-meter Keck telescope.
Explanation:In order to calculate the difference in light-collecting area between a 150-meter telescope and a 10-meter Keck telescope, we need to compare the areas of their mirrors. The area of a circle is determined by the square of its diameter. The Keck telescope has a mirror diameter of 10 meters, so its area is 100 square meters. The 150-meter telescope, on the other hand, would have an area of 22,500 square meters. Therefore, the light-collecting area of the 150-meter telescope would be 225 times greater than that of the 10-meter Keck telescope.
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The light-collecting area of a telescope is directly proportional to the square of its diameter. To compare the light-collecting areas of two telescopes, we need to calculate the ratio of their areas.
Explanation:The light-collecting area of a telescope is directly proportional to the square of its diameter. To compare the light-collecting areas of two telescopes, we need to calculate the ratio of their areas. The area of a circular telescope is given by the formula A = πr², where r is the radius (which is half the diameter). So, for the 10-meter Keck telescope, the radius would be 5 meters, and its area would be A=π × (5)² m². For the 150-meter telescope, the radius would be 75 meters, and its area would be A=π × (75)² m². To find how much greater the light-collecting area of the 150-meter telescope is, we need to calculate the ratio A150/A10.
A force has a magnitude of 575 newtons and points at an angle of 36.0 degrees below the positive x axis. What are the x scalar component and the y scalar component of the vector?
The magnitude of force F in x and y direction are 465.18 N adn 338 N respectively.
What is force ?
The ability to change shape, position, direction of a abject by an external mean is known as force in other words the push and pull of a body is also known as Force. It is a vector quantity and having unit in Newtons.
Here it is given that magnitude of force is 575 N and making an angle of 36 degree with x axis in counterclockwise direction as shown in figure below :
Now resolving Force F in x and y direction that is x component of F will be [tex]Fcos \theta[/tex] and y component will be [tex]Fsin \theta[/tex].
Now there magnitude will be :
[tex]\begin{aligned}Fcos\theta&= 575cos36^{o}=465.18 \text{\:N} \\ Fsin\theta&= 575sin36^{o}=465.18\approx 338\text{\:N}\end{aligned}[/tex]
It should be noted that [tex]Fsin \theta[/tex] is acting in negative y direction.
Therefore, the magnitude of force F in x and y direction are 465.18 N and 338 N respectively.
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What is the wavelength of radiation with a frequency of 1.50x10^13 hz?
We have that for the Question "What is the wavelength of radiation with a frequency of 1.50x10^13 hz? " it can be said that the wavelength of radiation with a frequency of 1.50x10^13 hz
[tex]\lambda=2*10^{-5}m[/tex]
From the question we are told
What is the wavelength of radiation with a frequency of 1.50x10^13 hz?
Generally the equation for the wavelength is mathematically given as
[tex]\lambda=\frac{V}{f}\\\\\lambda=\frac{3*10^8}{1.50x10^{13} }\\\\\lambda=2*10^{-5}[/tex]
Therefore
the wavelength of radiation with a frequency of 1.50x10^13 hz
[tex]\lambda=2*10^{-5}m[/tex]
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A speck of dust on a spinning dvd has a centripetal accelera- tion of 20 m/s2.
a. what is the acceleration of a different speck of dust that is twice as far from the center of the disk?
b. what would be the acceleration of the first speck of dust if the disk's angular velocity was doubled?
_____________ is increasing the temperatures of Earth’s oceans and atmosphere, leading to more intense storms of all types, including hurricanes. Nutrient depletion Urbanization Desertification Global Warming
ASAP PLEASE HELP , Ill give you what you want
A rightward-moving truck skids to a stop from a very high speed with its wheels locked. What are the forces applied?
Force due to gravity
normal force
magnetic force
air resistance
force of friction
tension
spring force
applied forces
Starting from rest, a solid sphere rolls without slipping down an incline plane. at the bottom of the incline, what does the angular velocity of the sphere depend upon? check all that apply. check all that apply. the angular velocity depends upon the length of the incline. the angular velocity depends upon the mass of the sphere. the angular velocity depends upon the radius of the sphere. the angular velocity depends upon the height of the incline
A solid spherical rolls down an inclined plane from rest without slipping. The radius of the sphere affects the angular velocity.
What do you mean by angular velocity?
Angular velocity is the speed at which an object rotates or revolves around an axis or alters the angle between two bodies.
The angle between a line on one body and a line on the other in the illustration serves as a representation of this displacement.
The length of the inclination affects the angular velocity. The mass of the sphere affects the angular velocity.
Thus, A solid spherical rolls down an inclined plane from rest without slipping. The radius of the sphere affects the angular velocity.
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Final answer:
The angular velocity of a solid sphere rolling without slipping down an incline depends on the sphere's radius and the incline's height, but not on the sphere's mass or the length of the incline.
Explanation:
When a solid sphere rolls without slipping down an incline, its angular velocity at the bottom depends on several factors. These factors include the radius of the sphere, the height of the incline, but not directly upon the mass of the sphere or the length of the incline (assuming it is long enough for the sphere to reach its maximum velocity due to gravity). The height of the incline determines the potential energy at the start, which converts into kinetic energy at the bottom. From the kinetic energy, we can find the linear velocity, and consequently the angular velocity, which is inversely proportional to the radius of the sphere.
The mass of the sphere does not directly affect angular velocity because both gravitational potential energy and rotational kinetic energy depend on mass in a way that it cancels out when calculating velocity. Similarly, the specific length of the incline does not determine the angular velocity at the bottom; rather, it is the vertical height that dictates the potential energy available for conversion to kinetic energy.
A 1.0-kilogram ball is dropped from the roof of a building 40. meters tall. What is the approximate time of fall? [Neglect air resistance.]
How to determine the resultant velocity from horizontal and vertical velocity?
Where is the highest electronegativity found?
The highest electronegativity is found in fluorine, located at the upper right corner of the periodic table with a value of 4.0.
Explanation:The highest electronegativity is found at the upper right corner of the periodic table, with fluorine having the highest electronegativity value. According to the Pauling scale, developed by the Nobel Prize-winning chemist Linus Pauling, fluorine has an electronegativity value of 4.0, which is the highest of all elements. The periodic trends indicate that electronegativity values increase as you move from left to right across a period and decrease as you move from top to bottom down a group. Therefore, nonmetals, particularly halogens like fluorine, are usually the elements with high electronegativities.
A rock at rest has weight 138 n. what is the weight of the rock when it is accelerating downward at 3.5 m/s2?
The weight of the rock when it is accelerating downward at 3.5 m/s² can be calculated using the formula Weight = Mass * Acceleration due to gravity.
Explanation:The weight of an object is equal to its mass multiplied by the acceleration due to gravity. In this case, the weight of the rock when it is at rest is 138 N. Since the rock is accelerating downward at 3.5 m/s², the weight can be calculated using the formula:
Weight = Mass × Acceleration due to gravity
Let's assume the mass of the rock is 'm'. The acceleration due to gravity is approximately 9.8 m/s² on Earth. So, when the rock is accelerating downward at 3.5 m/s², its weight can be calculated as:
Weight = m × 3.5 m/s²
Help physics! 1. Was the object at rest during the time interval labeled "B"?
Yes
No
2. Was the object accelerating during the time interval labeled "B"?
Yes
No
Answer:
Q1: No
Q2: No
Explanation:
the slope of velocity time graph gives the value of acceleration.
In section B
the graph is parallel to X axis, it means it is moving with constant velocity. Here the slope of graph in section B is zero.
Q1: Object is moving with constant velocity
Q2: The acceleration is zero
The acceleration due to gravity on planet X is one fifth that on the surface of the earth. If it takes 4.1 s for an object to fall a certain distance from rest on earth, how long would it take to fall the same distance on planet X? Answer in units of s.
The kinematic we find the time it takes for the body to fall on the planet X is 9.17 s
Given parameters
Acceleration on planet x a = 1/5 g The time of fall on the Earth t = 4.1 sTo find
The fall time on planet X
Kinematics studies the movement of the carpus, establishing relationships between their position, speed and acceleration.
For this exercise we must solve it in parts:
1st part. We look for the distance that the body on the ground in the Earth
y = v₀ t - ½ g t²
Where y and, y₀ are the final and initial height, respectively, g the ground clearance and t the time
where as the body is released its initial velocity is zero
y- y₀ = - ½ g t²
Δy = - ½ 9.8 4.1²
Δy = - 82.4 m
2nd part. This same distance is the one that travels on planet X, we look for time
y - y₀ = - ½ a t²
indicates that the acceleration on planet X is
a = 1/5 g
we substitute
Δy = - ½ (1/5 g) t²
t = [tex]\sqrt{\frac{10 \ \Delta y}{g} }[/tex]
t = [tex]\sqrt{\frac{10 \ 82.4 }{9.8} }[/tex]Ra 10 82.4 / 9.8
t = 9.17 s
In conclusion using kinematics we find the time it takes for the body to fall on planet x is 9.17 s
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What does the statement what does the statement 10 m/s to the north describe
Answer:
10 m/s to the north shows the velocity of an object.
Explanation:
The statement ''10 m/s to the north'' shows the velocity of an object. We know that velocity is a vector quantity and speed is scalar.
In the given statement 10 m/s shows the speed of an object while north shows the direction of motion. We can say that,
Speed + direction = velocity
Hence, the given statement shows the velocity of an object.