The tip of a 15-inch wiper blade wipes a path that is 36 inches long. What is the angle of rotation of the blade in radians to the nearest tenth?
2.4 radians
1.2 radians
2.8 radians
0.4 radians

Answers

Answer 1
The length of the arc is a fraction of the circumference of the circle depending on the length of the radius and the intercepted angle. This can be calculated through the equation,

                    L = (2πr) x (θ /360)

where L is the length of arc, r is the radius, and θ is the intercepted angle in terms of degrees. 

Substituting the known values to the equation,

                   36 = (2π)(15)  x (θ / 360)

We translate the equation to find the value of θ,

                               θ = (36)(360) / 2π(15)

The value of θ is equal to 137.51°

This can be coverted to radians through the equation below,

                              θ (in radians) = 137.51° x (2π rad / 360°) = 2.4 rad

Related Questions

Solve 2x2 + 20x = −38.
a. −5 ± square root 14
b.−5 ± square root 51
c. −5 ±square root 6
d.−5 ± square root 13

Answers

2x^2+20x=-38  divide both sides by 2

x^2+10x=-19, halve the linear coefficient, square it, than add that value to both sides of the equation, in this case add (10/2)^2=25...

x^2+10x+25=6  now the left side is a perfect square

(x+5)^2=6  take the square root of both sides

x+5=±√6  subtract 5 from both sides

x=-5±√6    (so answer c.)

Answer:

c

Step-by-step explanation:

−5 ±square root 6

How do you simplify this problem?

Answers

1+tan^2(x) = sec^2(x)

sec^2(x) = 1/cos^2(x)

csc(-x) / 1/cos^2(x) =

cos^2(x) csc(-x)

Solve log660 – log630. A. 5 B. log62 C. 2 D. log630

Answers

Its Log (660/ 630), so Id go with Log62, B. 

Answer:

Option B - [tex]\log_6 60-\log_6 30=\log_6 (2)[/tex]                

Step-by-step explanation:

Given : Expression [tex]\log_6 60-\log_6 30[/tex]

To find : Solve the given expression?

Solution :

Step 1 - Write the expression

[tex]\log_6 60-\log_6 30[/tex]

Step 2 - Applying logarithmic property, [tex]\log a-\log b=\log(\frac{a}{b})[/tex]

[tex]\log_6 60-\log_6 30=\log_6 (\frac{60}{30})[/tex]

Bases are same.

Step 3 - Solve

[tex]\log_6 60-\log_6 30=\log_6 (2)[/tex]

Therefore, The solution of expression is

[tex]\log_6 60-\log_6 30=\log_6 (2)[/tex]

So, Option B is correct.

(30 points) Enter numbers to write 0.000328 in scientific notation.

Answers

[tex]0.000328= \cfrac{3.28}{10,000}=3.28*10^{-4} [/tex]

Which lines can you conclude are parallel given that m14 + m2 = 180? Justify your conclusion with a theorem.

Answers

Line a is parallel to line b by the Converse of the Same-Side Exterior Angles Theorem

because m<14 and m<2 are in lines a and b and they aren't corresponding angles

Answer:

Option 2 is correct.

Step-by-step explanation:

Given the diagram and also the condition  m∠14 + m∠2 = 180°

we have to tell which lines are parallel.

By the theorem of exterior angles

Same-side exterior angles which are formed outside of the parallel lines and on same side of transversal line.

The theorem states that when parallel lines are cut by a transversal line, the sum of the same-side exterior angles is 180° i.e these are supplementary.

∴ Lines a and b are are parallel by converse of same side exterior angle theorem.

Which number line represents all of the values of x for the equation x2 = 36?

Answers

x^2 = 36
x=-6 and x = 6

answer
-6 and 6 are values of x on number line

yes thats the corrects answer -6 and 6 on the number line.

Look at the formula for finding distance.

D=RT

Which of the following is the formula to find time (t)?

ANSWERS:
A-T=DR
B-T=R/D
C-T=D/R
D-T=D-R


Answers

C Should be your answer

What is the value of x in the equation 2(x – 3) + 9 = 3(x + 1) + x?

x =

Answers

it means the same:

2x - 6 + 9 = 3x + 3 + x
2x +3 = 4x + 3
2x - 4x = 3 - 3
-2x = 0
x = 0/(-2) = 0

Answer:
x = 0

How many roots does y+x^2-6x+9 have?
A. One
B. Two
C. Zero
D. Three

Answers

Zero unless that y is a misprint

James is four years younger than Austin. If 2 times James age is increased by the square of austins age, the result is 28. Find the 2 ages. Use an algebraic solution

Answers

Let the age of Austin be a, then the age of James is a-4.

"
If 2 times James age is increased by the square of Austins age, the result is 28."

means: [tex]2(a-4)+ a^{2} =28[/tex]

rearrange the quadratic equation and solve it:

[tex]a^{2}+2(a-4)-28=0[/tex]

[tex]a^{2}+2a-8-28=0[/tex]

[tex]a^{2}+2a-36=0[/tex]

add and subtract 1 to complete the square:

[tex]a^{2}+2a+1-1-36=0[/tex]

[tex](a+1)^{2} =37[/tex]

a+1=root 37 = 6 (approximately), so a=5 

or a+1=root 37 = -6 (approximately), so a=-7, which is not possible

The age of Austin is 5, and the age of James is 1.


Find f(x) and g(x) so that the function can be described as y = f(g(x)). y = eight divided by square root of quantity two x plus four.

Answers

[tex]\bf y=f[\ g(x)\ ]=\cfrac{8}{\sqrt{2x+4}}\\\\ -------------------------------\\\\ \begin{cases} f(x)=\cfrac{8}{\sqrt{x}}\\\\ g(x)=2x+4 \end{cases}\qquad f[\ \underline{g(x)}\ ]=\cfrac{8}{\sqrt{\underline{g(x)}}}\implies f[\ \underline{g(x)}\ ]=\cfrac{8}{\sqrt{\underline{2x+4}}}[/tex]

The distance of saturn from the sun is 1507 million kilometers express this distance in standard form

Answers

1.507 * 10 ^6 i would guess so

Let $s$ be the set of points with polar coordinates $(r,\theta)$ such that $ 2 \le r \le 6$ and $\frac{\pi}{3} \le \theta \le \frac{5 \pi}{6} $. find the area of $s$.

Answers

The area defined by
2 ≤ r ≤ 6 and π/3 ≤ θ ≤ (5π)/6 is shown in the figure below.

An element of area is
dA = r dr dθ

Therefore the total area is
[tex]A=\int _{ \frac{ \pi }{3}} ^{ \frac{5 \pi }{6} } \,d\theta \int_{2}^{6} \,rdr \\ A= [ \frac{5 \pi }{6}- \frac{ \pi }{3}]*[ \frac{6^{2}}{2} - \frac{2^{2}}{2}] = 8 \pi [/tex]

Answer: 8π

The value of y varies jointly with the values of x and z. When x=4 and z=9, the value of y is 360. What is the value of y when x=5 and z=12?

Answers

y = k * z , where k is any constant
x=4, z=9 , y=360

360 = k (4)(9)
360 = 36 k
k = 360/36
k = 10

y = 10 * z

when x=5 and z = 12
y = 10 (5)(12)
y = 600

Given the vertices of ∆ABC are A (2,5), B (4,6) and C (3,1), find the vertices following each of the
transformations FROM THE ORIGINAL vertices:

a. Rx-axis
b. Ry = 3
c. T<-2,5>
d. T<3,-6>
e. r(90◦, o)

Answers

The triangle ABC is shown in the diagram below

Part a)
R(x-axis) is the reflection of triangle ABC on the x-axis. The new coordinates is given as A' (2, -5), B' (4, -6), and C' (3, -1)

Part b) 
R(y=3) is the reflection of triangle ABC on the line with equation y=3.
The new coordinates are A' (2, 1), B' (4, 0), and C' (3, 5)

Part c)
T(-2, 5) is the translation of triangle ABC two units left and five units up. The new coordinates are A'(0, 10), B' (2, 11), and C'(1, 6)

Part d)
T(3, -6) is the translation of triangle ABC three units right and six units down. The new coordinates are A'(5, -1), B'(7, 0), and C'(6, -5)

Part e)
r(90°, 0) is the rotation of triangle ABC on the origin by 90° clockwise. The new coordinates are A'(5, -2), B'(6, -4) and C'(1 -3)


A cell phone company charges a basic rate of $19.99 per month for 300 minutes of local usage. Any local usage over 300 minutes is charged at $.10 per minute. All long distance calls are charged at $.25 per minute. Write and simplify an expression that gives the total monthly bill if x is the number of local minutes and y is the number of long distance minutes. Evaluate the expression if local usage totals 375 minutes and long distance usage totals 54 minutes.

Answers

total = 19.99 + 0.10(x-300) + 0.25y

x = 375

y=54

total = 19.99 +0.10(375-300) +0.25(54)

total = 19.99 + 0.10(75) + 0.25(54)

total = 19.99 + 7.50 + 13.50

total = $40.99

The total monthly bill is $40.99 for 375 local minutes and 54 long distance minutes, given the cell phone company's rates.

The total monthly bill can be expressed as the sum of the basic rate, the extra charge for local minutes beyond the included 300, and the charge for all long distance minutes. The expression can be written as:

Total Monthly Bill = Basic Rate + (Local Extra Charge x Extra Local Minutes) + (Long Distance Rate x Long Distance Minutes)

Where:

Basic Rate = $19.99Local Extra Charge = $0.10 per minuteExtra Local Minutes = x - 300 (only if x > 300)Long Distance Rate = $0.25 per minuteLong Distance Minutes = y

For x = 375 local minutes and y = 54 long distance minutes, the total monthly bill is calculated as follows:

Total Monthly Bill = $19.99 + ($0.10 x (375 - 300)) + ($0.25 x 54)

Total Monthly Bill = $19.99 + $7.50 + $13.50

Total Monthly Bill = $40.99

Conjectures can always be proven true.
True or False

Answers

if it's false then it can't be proven true

basically if you start with a crazy wrong conjecture, then it can't be proven true

a conjecture is a guess based on incomplete information
some examples are when you have some special cases and assume they are true for all cases


example:
this rectangle is 4 by 16
this square is 8 by 8
they have the same area
therfor I think that all squares have the same area as rectangles
(that's obviously false)
so you can't prove that true

The book Kathy is reading is 540 pages long. So far, she has read 405 pages. What percent of the book does she have left to read?

Answers

the book is 540 pgs.....she has read 405....that leaves (540 - 405) = 135 pgs left to read.

135 / 540 = 0.25 = 25% <== what she has left to read

Answer: b

Step-by-step explanation: i got it right

A cylindrical metal can is to have no lid. it is to have a volume of 8Ï in3. what height minimizes the amount of metal used?

Answers

To solve this problem let us say that,

h = height of the can

r = radius of the can

We try to minimize the amount of metal used which is the surface area (SA), and the equation for a cylinder is:

SA = 2πrh + πr^2

To get the minima, we take the derivative of this function and set it equal to 0. But first, the function is in two variables so we must eliminate one of them. We use the extra information given in the problem which is volume:

V = 8π = πr^2 h

 

Therefore,

h = 8/r^2

Plug this into the SA function to have it in terms of one variable only:

SA = 2πrh + πr^2

SA = 2πr(8/r^2) + πr^2

SA = 16π/r + πr^2

 

Taking the 1st derivative of the function:

0 = −16π r^−2 + 2πr

0 = −16π/r^2 + 2πr

16π/r^2 = 2πr

r^3 = 8

r = 2 in

 

By obtaining r, we calculate for h:

h = 8/r^2

h = 8/(2)^2

h = 8 / 4

h = 2 in               (ANSWER)

A box with a square base and open top must have a volume of 32,000 cm3. find the dimensions of the box that mini- mize the amount of material used.

Answers

alrighty


squaer base so length=width, nice


v=lwh
but in this case, l=w, so replace l with w
V=w²h

and volume is 32000
32000=w²h


the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW

alrighty

we gots
SA=W²+4HW and
32000=W²H

we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute

SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W

take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?

0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W

so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H

the box is 20cm height and the width and length are 40cm

A point where two or more rays or "arms" of an angle meet

Answers

 Hello there!

A point where two or more rays or arms of an angle meet is a vertex


I hope that helps!

Final answer:

The point where two or more rays meet in optics is known as the focal point, which is crucial in geometric optics. For a converging lens or mirror, it's where light rays converge, while for a diverging lens or mirror, it's where light rays appear to originate.

Explanation:

The point where two or more rays or 'arms' of an angle meet in the context of geometrical optics is known as the focal point. In terms of a converging lens or mirror, the focal point is where converging light rays intersect after passing through the lens or reflecting off the mirror surface. This is a fundamental concept in the study of geometrical optics, which deals with the ray aspect of light. A ray is a straight line that originates at a point and is used in geometric optics to represent the path along which light travels.

For a converging lens, which is also known as a convex lens, parallel light rays entering the lens will refract and converge at a single point on the opposite side of the lens. This single point is the focal point. Similarly, in concave mirrors, ray diagrams show the focal point as the point where reflected rays converge or appear to converge. The distance from the focal point to the mirror along the central axis is referred to as the focal length. Conversely, for a diverging lens or mirror, the focal point is the point from which diverging light rays appear to originate.

In which expression should the exponents be multiplied?
a. (5^3)-4
b. (1/3)^4*(1/3)^7
c. 3^7/3^15
d. 4^5*4^2

Answers

If we have the same base, we can do this:
(1/3)^4*(1/3)*7 = (1/3)^(4+7) = (1/3)^11
3^7/3^15 = (3^7)*(3*(-15)) = 3^(7 + (-15)) = 3^(-8) = 1/(3^8)
4^5*4^2 = 4^(5+2) = 4^7

Option b is the correct answer. Exponents should be multiplied in the expression (1/3)^4*(1/3)^7, resulting in (1/3)^11.

The expression where the exponents should be multiplied is Option b. (1/3)^4*(1/3)^7. This is because when you multiply two expressions that have the same base, you add their exponents. In this case, you have the base (1/3) raised to the 4th power and then to the 7th power, so you add the exponents 4 + 7, which equals 11. Therefore, (1/3)^4*(1/3)^7 simplifies to (1/3)^11.

Another case where you multiply exponents would be when raising a power to another power, like in (5^3)^4. Here the exponents 3 and 4 are multiplied, resulting in (5^12).

(6.04)The scatter plot shows the relationship between the number of hours spent jogging and the number of minutes spent stretching, by the students on a track team:
What is the y-intercept of the line of best fit and what does it represent?

1 minute; the number of minutes students stretch when they do not jog
1 hour; the number of hours students jog when they do not stretch
4 hours; the number of hours students jog when they do not stretch
4 minutes; the number of minutes students stretch when they do not jog

Answers

The y int is where the line crosses the y axis...it is (0,1)...or just 1

1 minute, the number of minutes students stretch when they do not jog
Your answer is A) 1 minute; the number of minutes students stretch when they do not jog

How many ways are there to place 5 basketball players on the court if you must place 2 guards, 2 forwards and a center, from a team of 12, consisting of 4 guards, 5 forwards and 3 centers?

Answers

Final answer:

There are 180 ways to place 5 basketball players on the court, selecting 2 guards, 2 forwards, and 1 center.

Explanation:

To determine the number of ways to place 5 basketball players on the court, we need to find the number of combinations of guards, forwards, and centers that can be selected from the available players. There are 4 guards, 5 forwards, and 3 centers in the team.

The number of ways to select 2 guards from 4 is C(4,2) = 6.

The number of ways to select 2 forwards from 5 is C(5,2) = 10.

The number of ways to select 1 center from 3 is C(3,1) = 3.

By the multiplication principle, the total number of ways to place the players on the court is 6 × 10 × 3 = 180.

Please Help!! Find the measure of angle 2. Image Attached

Answers

angle 2 = 180-111 = 69 degrees

every evening jenna empties her pockets and puts the changein a jar. at the end of the week she had 50 coins, all of them dimes and quarters. when she added them up, she had a totals of $10.25
d=number of dimes q=number of quarters
how many dimes did jenna have?

Answers

Jenna had fifteen dimes.

Which is a factor of 54xy + 45x + 18y + 15?

Answers

Upon slight rearrangement...

54xy+18y+45x+15  now factor 1st and 2nd pair of terms

18y(3x+1)+15(3x+1)  which is equal to

(18y+15)(3x+1)  and you can further factor the first binomial factor

3(6y+5)(3x+1)

The equation sec^2x-1=tan^2x is an identity true or false

Answers

Truee because that is what the webitse said with the exact same question , hope you don't need to show your work but the answer is true

A rectangular patio is 9 ft by 6 ft. When the length amd width are increased by the same amount, the area becomes 88 sq ft. Ginger is using the zero product property to solve the equation (6+x)(9+x)= 88. What do her solutions represent?

Answers

Final answer:

The solutions represent the additional length and width that need to be added to the original dimensions to achieve the desired area of 88 sq ft.

Explanation:

The equation is: (6+x)(9+x) = 88. Ginger is using the zero product property to solve for x. The solutions she finds represent the value of x that, when added to both the length and width of the original patio, will result in a patio with an area of 88 sq ft.



By solving the equation, Ginger will find the possible values of x that will make the area of the new patio equal to 88 sq ft. These values represent the additional length and width that need to be added to the original dimensions to achieve the desired area.



For example, if Ginger finds that x = 2, then the new patio dimensions would be 9+2 = 11 ft by 6+2 = 8 ft, resulting in an area of 11 * 8 = 88 sq ft.

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Check all that apply: If cos theta = 15/17 then:

A. Sec theta = 17/15

B. Tan theta = 8/15

C. Sin theta = 15/8

D. Csc theta = 17/15

Answers

The options (A) and (B) are correct.

What is trigonometric Ratios?

"Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle. It is with respect to any of its acute angles are known as the trigonometric ratios of that particular angle".

For the given situation,

Cos θ = 15/17

By using Pythagoras theorem,

We know Cos θ = [tex]\frac{base}{hypotenuse}[/tex]

Sine θ = [tex]\frac{perpendicular}{hypotenuse}[/tex]

tan θ = [tex]\frac{perpendicular}{base}[/tex]

By Pythagoras theorem, [tex]Hypotenuse^{2}= base^{2}+perpendicular^{2}[/tex]

⇒[tex]17^{2}=15^{2}+perpendicular^{2}[/tex]

⇒[tex]perpendicular^{2}= 289-225[/tex]

⇒[tex]perpendicular=\sqrt{64}[/tex]

⇒[tex]perpendicular=8[/tex]

Thus, Sec θ = 17/15

Tan θ = 8/15

Sine θ = 8/17

Cosec θ = 17/8.

Hence we can conclude that the options (A) and (B) are correct.

Learn more about trigonometric ratios here

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Answer:

tan and sec

Step-by-step explanation:

A amd B

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