Answer:
Option A - 10
Step-by-step explanation:
Given : There are 3 red chips and 2 blue chips. If they form a certain color pattern when arranged in a row, for example RBRRB.
To find : How many color patterns are possible?
Solution :
Total number of chips = 5
So, 5 chips can be arranged in 5! ways.
There are 3 red chips and 2 blue chips.
So, choosing 3 red chips in 3! ways
and choosing 2 blue chips in 2! ways.
As changing the places of similar chip will not create new pattern.
The total pattern is given by,
[tex]T=\frac{5!}{3!\times 2!}[/tex]
[tex]T=\frac{5\times 4\times 3!}{3!\times 2}[/tex]
[tex]T=10[/tex]
Therefore, color patterns are possible are 10.
Option A is correct.
A las 9 de la mañana,la temperatura en Valcorto era de -8 grados . A las 12 horas era dos grados mayor ,a las 15 horas tres grados mas que a las 12 ,y a las 21 horas nueve grados menos que a las 15 ¿que temperatura habia cada hora citada?
Answer:
[tex]T_{9hr}=-8 C[/tex]
[tex]T_{12hr}=-6 C[/tex]
[tex]T_{15hr}=-3 C[/tex]
[tex]T_{21hr}=-12 C[/tex]
Step-by-step explanation:
The initial temperature at 9 am:
[tex]T_{9hr}=-8 C[/tex]
At 12 hr is 2 degrees higher:
[tex]T_{12hr}=T_{9hr}+2 C=-6 C[/tex]
At 15 hr is 3 degrees higher than 12hr:
[tex]T_{15hr}=T_{12hr}+3 C=-3 C[/tex]
Finally, at 21 hr, is 9 degrees lower than 15 hr:
[tex]T_{21hr}=T_{15hr}-9 C=-12 C[/tex]
rectangular yard measuring 24ft by 29ft is bordered (and surrounded) by a fence. Inside, a walk that is 2ft wide goes all the way along the fence. Find the area of this walk. Be sure to include the correct unit in your answer.
Answer:
Area of the walk = 110 square feet
Step-by-step explanation:
The rectangular yard measuring 24ft by 29ft
Area of the rectangle = length times width
Area of the rectangular yard = 24 times 29=696 square feet
Length of side walk is 2 feet wide
Length of the rectangular yard with walk = 24+2= 26 ft
Width of the rectangular yard with walk = 29+2=31 ft
Area of the rectangular yard with walk = 26 times 31=806 square feet
Area of the walk = [tex]806-696=110 squarefeet[/tex]
the empire state building is 1250 feet tall. IF an object is thrown upward from the top of the building at an initial velocity of 38 feet per second, its height s seconds after it is thrown is given by the function h(s) = -16s^2 + 38s + 1250. round to the nearest hundreth
Answer:
Time for the object to get h(max) s = 1.1875 sec
h (max) = 1272.57 feet
Down time for the object to hit the ground = 4.25 sec
Step-by-step explanation:
The relation
h(s) = - 16*s² + 38* s + 1250 (1)
Is equivalent to the equation for vertical shot
Δh = V(i)*t - 1/2g*t² (in this case we don´t have independent term since the shot is from ground level. We can see in (1), the independent term is 1250 feet ( the height of the empire state building), the starting point of the movement.
The description of the movement is:
V(s) = V(i) - g*s ⇒ V(s) = 38 - 32*s
At h(max) V(s) = 0 38/32 = s
So the maximum height is at s = t = 1.1875 sec
The time for the object to pass for starting point is the same
t = 1.1875 sec
h(max) is
h(max) = - 16* (1.1875)² + 38 (1.1875) + 1250
h(max) = - 22,56 + 45.13 + 1250
h(max) = 1272.57 feet
Time for the object to hit the ground is
h(s) = - 1250 feet
-1250 = - 16 s² + 38*s + 1250
-16s² + 38s = 0
s ( -16s + 38 ) = 0
First solution for that second degree equation is x = 0 which we dismiss
then
( -16s + 38 ) = 0 ⇒ 16s = 38 s = 38/16
s = 2.375 sec and we have to add time between h (max) and to get to starting point ( 1. 1875 sec)
total time is = 2.375 + 1.875
Total time = 4.25 sec
What is the value of cos-1 (-√3/2
The value of cos-1 (-√3/2) represents the angle that has the cosine of -√3/2, and it is found in the second or third quadrant. The angles corresponding to these values in the unit circle are 120° or 240°.
Explanation:The value of cos-1 (-√3/2) refers to the angle whose cosine is -√3/2. This angle would be found in the second or third quadrant since cosines are negative in these quadrants. For the value of -√3/2, it corresponds to the angle 120° or 240° in the unit circle. Therefore, the value of cos-1 (-√3/2) is 120° or 240°.
Remember, inverse trigonometric functions deal with the range and the quadrant in which an angle lays. While working with inverse trigonometric functions, pay attention to the unit circle, and to the fact that cosine is negative in the second and third quadrants.
The value of cos-1 (-√3/2) is 150 degrees or 5π/6 radians.
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Some kangaroos can cover 30 feet in a single jump if a kangaroo counts jump like that 150 times in a row how much farther wound it need to go to cover a mile
Answer:
Distance farther the Kangaroos need to go to cover a mile = 780 feet
Step-by-step explanation:
Given:
Kangaroos cover 30 feet in a single jump.
Kangaroos can make such jumps 150 times in a row.
To find the distance farther it needs to go to cover a mile.
Solution:
Using unitary method to find distance covered by kangaroos in a row.
If in a single jump Kangaroos cover = 30 feet
So, in 150 jumps it will cover = [tex]30\ ft \times 150[/tex] = 4500 feet
We know 1 mile = 5280 feet
Thus, distance farther the Kangaroo needs to go to cover a mile will be = [tex]5280\ ft-4500\ ft[/tex] = 780 feet
Four milliliters of ink A is added to 10 milliliters of ink B, forming a mixture of inks. Ink A contains 10% blue pigment. Ink B contains an unknown percentage of blue pigment. The mixture of the two inks contains 35% blue pigment. What percentage of blue pigment is in ink B?
A. 45%
B. 49%
C. 60%
D. 75%
Answer:
The answer to your question is letter A
Step-by-step explanation:
Percent of blue pigment Milliliters
ink A 10% 4
ink B --- 10
Total volume 35% 14
Formula
Total percent x total volume = (percent ink A x A milliliters) +
(percent ink B x B milliliters)
Substitution
(0.35 x 14) = ( 0.1 x 4) + (B x 10)
Solve for B
4.9 = 0.4 + 10B
10B = 4.9 - 0.4
10B = 4.5
B = 4.5/10
B = 0.45 x 100
B = 45%
Remy, from the blog "Rapping with Remy," asked his readers, "If you had the chance, would you want to be famous?" Of the 2,200 readers who responded, 42% said no, and all were female. What does this show?
possible answers:
No meaningful conclusion is possible without knowing something more about the characteristics of Remy's readers.
The survey is meaningless because of undercoverage bias.
The survey would have been more meaningful if Remy had picked a random sample of the readers who responded.
the survey would have been more meaningful if Remy had used a control group.
This was a legitimate sample, drawn randomly from his readers, and is of adequate size to allow the conclusion that most of Remy's readers want to be famous.
Understanding the representativeness of samples in surveys is crucial for drawing meaningful conclusions. In these examples, the lack of information about the characteristics of Remy's readers and the undercoverage bias in the radio station survey make the conclusions unreliable.
Explanation:The question is about the representativeness of samples in surveys. In the case of Remy's blog survey, the fact that only female readers responded and that more information about their characteristics is needed suggests that no meaningful conclusion is possible without knowing something more about the characteristics of Remy's readers.
In the case of the local radio station survey, convenience sampling was used by only surveying people attending the concert events, which may not accurately represent the entire 20,000 listener population. Therefore, the survey is meaningless because of undercoverage bias.
What is the equation of the line with m = 6 that goes through the point (1, 4)?
A. y – 4 = 6(x + 1)
B. y – 4 = 6(x – 1)
C. y + 4 = 6(x – 1)
D. y + 4 = 6(x + 1)
Since it's a line we are talking about linear equation of a form
[tex]f(x)=mx+n[/tex]
where [tex]m[/tex] is slope and [tex]n[/tex] is y-intercept.
Our particular line has a form of
[tex]f(x)=6x+n[/tex]
So we are missing the y-intercept.
To find y-intercept [tex]n[/tex] we insert the coordinates of point [tex]P(x,f(x))\to P(1,4)[/tex] and solve for [tex]n[/tex]
[tex]
4=6\cdot1+n \\
n=-2
[/tex]
So the final form of the line is
[tex]y=6x-2[/tex]
Or as offered in the answers
[tex]y-4=6(x-1)[/tex]
The answer is B.
Hope this helps.
Pete wants to make turkey sandwiches for tow friends and himself.He wants each sandwich to contain 3.5 ounces of turkey.How many ounces of turkey does he need
Pete needs 10.5 ounces of turkey.
Step-by-step explanation:
Given,
Number of friends = 2
One for Pete.
Total sandwiches to be made = 2+1 = 3
Quantity of turkey in one sandwiches = 3.5 ounces
For finding the quantity of turkey for three sandwiches, we will multiply.
Turkey for 3 sandwiches = 3*3.5 = 10.5 ounces
Pete needs 10.5 ounces of turkey.
Keywords: multiplication, addition
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To determine whether there is a relationship between the type of school attended and verbal reasoning scores for Irish students, three samples with 25 students, in each group, were randomly selected from data used by Raferty and Hout (1985). One group of students attended secondary school, the second group of students attended vocational school, and the third group consisted of students who attended only primary school.
Here are the three sample standard deviations for the verbal reasoning scores for the three groups (secondary school, vocational school, and primary school only):
Based on this information, do the data meet the condition of equal population standard deviations for the use of the ANOVA?
A. Yes, because 14.18 − 11.71 < 2.
B. Yes, because 14.18/11.71 < 2.
C. No, because the standard deviations are not equal.
Answer:
B. Yes, because 14.18/11.71 < 2.
Step-by-step explanation:
When the ratio of the largest sample standard deviation to the smallest sample standard deviation is less than 2, the condition is said to be met.
A positive integer with exactly two different divisors greater than 1 must be(A) a prime(B) an even integer(C) a multiple of 3(D) the square of a prime(E) the square of an odd integer
Answer:
(D) the square of a prime
Step-by-step explanation:
You want to know the kind of number that will have exactly two distinct positive divisors other than 1.
DivisorsThe number of divisors a number will have can be found from its prime factorization. If that is described by ...
[tex]\displaystyle N=p_1^{e_1}\times p_2^{e_2}\times\dots=\prod\limits_n(p_i)^{e_i}\\ \\\text{\# of divisors of N}=\prod\limits_n (e_i+1)[/tex]
This count of divisors includes 1 and the number N. If there are 2 divisors other than 1, then we must have the product of all "bumped" exponents be 3. Since 3 is prime, its only factors are 1 and 3. That means there must be only one exponent, and its value must be 3-1 = 2.
That is, N = p², where p is a prime, has 2+1 = 3 divisors, including 1.
An integer with exactly 2 distinct divisors greater than 1 is the square of a prime, choice D.
Represent each of these relations on {1, 2, 3, 4} with a matrix (with the elements of this set listed in increasing order). a) {(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)} b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)} c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)} d) {(2, 4), (3, 1), (3, 2), (3, 4)}
The concept in the question is about representing relations as matrices. In the matrices, the rows and columns correspond to the numbers in the set {1, 2, 3, 4}. The positions in the matrices that are filled with 1s correspond to the numbers in the given relationships.
Explanation:The relations can be represented on the set {1, 2, 3, 4} with a matrix as follows:
a) For this relationship, a 4x4 matrix can be created. The rows and columns correspond to the numbers in the set {1, 2, 3, 4}. The elements of the set [tex]{(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)}[/tex] correspond to positions in the matrix that will be filled with 1s, while the rest will be filled with 0s.
b) A matrix for this relationship would look similar to the above matrix but with different elements in the set [tex]{(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}[/tex]. In this case, the position of 1s and 0s in the matrix changes.
c) The matrix corresponding to this relationship would have 1s in positions corresponding to the elements of the set [tex]{(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}.[/tex]
d) The last matrix would have 1s only at the positions corresponding to the relationship {(2, 4), (3, 1), (3, 2), (3, 4)}.
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On Monday morning, Susan bought 2.5 pounds of grapes at the supermarket. That day, Susan ate some grapes and had 1.75 pounds of grapes left. What is the percent decrease of pounds of grapes on Monday?
Answer:
Step-by-step explanation:
On Monday morning, Susan bought 2.5 pounds of grapes at the supermarket. That day, Susan ate some grapes and had 1.75 pounds of grapes left. This means that the amount of grapes that she ate would be 2.5 - 1.75 = 0.75
The percentage decrease of pounds of grapes on Monday would be the amount that she ate on Monday divided by the initial amount times 100. It becomes
0.75/2.5 × 100 = 30℅
If a lineman can install 12 insulators in 183/4 hours, how many insulators should he be able to install in 281/8 hours?
Answer: 9
Step-by-step explanation:
12 insulators = 183/4 hours
x = 281/8
x × 183/4 = 12 ×281/ 8
183x/4 = 6 × 281/4
183x / 4 = 1686 / 4
4 cancel out 4
183x = 1686
Divide bothside by 183
x = 1686/183
x= 9.21311
x = 9 approximately.
Answer:
$0.04 per foot
Step-by-step explanation:
Nitrites are often added to meat products as preservatives. In a study of the effect of these chemicals on bacteria, the rate of uptake of a radio-labeled amino acid was measured for a number of cultures of bacteria, some growing in a medium to which nitrites had been added. Here are the summary statistics from this study. Group n x s Nitrite 30 7880 1115 Control 30 8112 1250.
Carry out a test of the research hypothesis that nitrites decrease amino acid uptake at the 2% significance level.
Answer:
H0:[tex]\mu_{N}\geq \mu_{C}[/tex]
H1:[tex]\mu_{N} < \mu_{C}[/tex]
[tex]t=\frac{7880-8112}{\sqrt{\frac{1115^2}{30}+\frac{1250^2}{30}}}}=-0.759[/tex]
[tex]p_v =P(t_{(58)}<-0.759)=0.225[/tex]
So the p value is a very High value and using any significance level given [tex]\alpha=0.02[/tex] we see that [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the mean for the nitrite group is significantly lower than the mean for th control group .
Step-by-step explanation:
1) Data given and notation
[tex]\bar X_{N}=7880[/tex] represent the mean for the sample Nitrite
[tex]\bar X_{C}=8112[/tex] represent the mean for the sample control
[tex]s_{N}=115[/tex] represent the sample standard deviation for the sample Nitrite
[tex]s_{C}=1250[/tex] represent the sample standard deviation for the sample control
[tex]n_{N}=30[/tex] sample size for the group nitrite
[tex]n_{C}=30[/tex] sample size for the group control
t would represent the statistic (variable of interest)
[tex]\alpha=0.02[/tex] represent the significance level
Confidence =1-0.02=0.98 or 98%
2) Concepts and formulas to use
We need to conduct a hypothesis in order to check if the nitrites decrease amino acid uptake , the system of hypothesis would be:
H0:[tex]\mu_{N}\geq \mu_{C}[/tex]
H1:[tex]\mu_{N} < \mu_{C}[/tex]
If we analyze the size for the samples both are equal to 30, but we don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:
[tex]t=\frac{\bar X_{N}-\bar X_{C}}{\sqrt{\frac{s^2_{N}}{n_{N}}+\frac{s^2_{C}}{n_{C}}}}[/tex] (1)
t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.
3) Calculate the statistic
We can replace in formula (1) like this:
[tex]t=\frac{7880-8112}{\sqrt{\frac{1115^2}{30}+\frac{1250^2}{30}}}=-0.759[/tex]
4) Statistical decision
The first step is calculate the degrees of freedom, on this case:
[tex]df=n_{N}+n_{C}-2=30+30-2=58[/tex]
Since is a left tailed test the p value would be:
[tex]p_v =P(t_{(58)}<-0.759)=0.225[/tex]
So the p value is a very High value and using any significance level given [tex]\alpha=0.02[/tex] we see that [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the mean for the nitrite group is significantly lower than the mean for th control group .
KarlaPurchase a swimsuit on Amazon the original price of the coat was 75.50 she use the coupon code to receive a 25% discount the website applied a 10% service fee for the discount price Karla swimsuit Was less then original price by what percent
Answer:
Step-by-step explanation:
The initial price of the swimsuit that Karla purchased at Amazon was 75.5
she use the coupon code to receive a 25% discount. This means that the value if the discount would be
25/100 × 75.5 = 0.25× 75.5 = 18.86
Therefore, the discounted price of the swimsuit is 75.5 - 18.875 = 56.625
The website applied a 10% service fee for the discount price. This means that the value of the service fee would be
10/100 × 56.625 = 0.1 × 56.625 = 5.6625.
The amount that Karla pays for the swimsuit would be
56.625 + 5.6625 = 62.2875
The difference between the original price and the price that Karla paid would be 75.5 - 62.2875 = 13.2125
The percentage by which the amount that Karla paid was lesser than the original price would be
13.2125/ 75.5 × 100 = 17.5%
24. You use math in day-to-day routines when grocery shopping, going to the bank or mall, and while cooking. How do you imagine you will use math in your healthcare career?
Answer: in dispensing medications, in the use of measurement equipments and formulas for converting units, to obtain reliable data of patients overtime to be able to predict, and diagnose patients easily
Step-by-step explanation:
Maths is used in health care in the dispensing of medications they translate medical order into dosages, calculate dosage based on body weight, determine the amount of drugs to be dispensed. Maths also helps in the conversion of units e.g milligram to gram, Fahrenheit to degree Celsius etc.
It also help in the measurement of body temperature, pulse rate, breathing rate etc.
Among others uses, maths is also used to generate reliable data of patients overtime and help in quick diagnosis and treatment of patients.
ABCD is a parallelogram AC = 15, m∠ BAC = 22° , m∠DAC = 27° Find: AB and BC
Answer:
[tex]AB=9.02\ units[/tex]
[tex]BC=7.45\ units[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
Remember that in a parallelogram opposites sides are parallel and congruent, opposites angles are congruent and consecutive angles are supplementary
step 1
Find the measure of angle ACB
we have
[tex]m\angle BAC=22^o[/tex] ----> given problem
[tex]m\angle ACB=m\angle DAC[/tex] ----> by alternate interior angles
[tex]m\angle DAC=27^o[/tex] ----> given problem
so
[tex]m\angle ACB=27^o[/tex]
step 2
Find the measure of angle ABC
The sum of the interior angles in any triangle must be equal to 180 degrees
In the triangle ABC of the figure
[tex]m\angle BAC+m\angle ACB+m\angle ABC=180^o[/tex]
substitute the given values
[tex]22^o+27^o+m\angle ABC=180^o[/tex]
[tex]49^o+m\angle ABC=180^o[/tex]
[tex]m\angle ABC=180^o-49^o[/tex]
[tex]m\angle ABC=131^o[/tex]
step 3
Find the length side AB
In the triangle ABC
Applying the law of sines
[tex]\frac{AC}{sin(ABC)}=\frac{AB}{sin(ACB)}[/tex]
substitute the given values
[tex]\frac{15}{sin(131^o)}=\frac{AB}{sin(27^o)}[/tex]
[tex]AB=\frac{15}{sin(131^o)}(sin(27^o))[/tex]
[tex]AB=9.02\ units[/tex]
step 4
Find the length side BC
In the triangle ABC
Applying the law of sines
[tex]\frac{AC}{sin(ABC)}=\frac{BC}{sin(BAC)}[/tex]
substitute the given values
[tex]\frac{15}{sin(131^o)}=\frac{BC}{sin(22^o)}[/tex]
[tex]BC=\frac{15}{sin(131^o)}(sin(22^o))[/tex]
[tex]BC=7.45\ units[/tex]
To find the lengths of AB and BC in the parallelogram ABCD, one can use the sine and cosine trigonometric ratios along with the given lengths and angles of the parallelogram. AB is calculated using the sine of angle DAC and the length of AC, while BC is equal to AD, which can be found using the cosine of angle DAC and the length of AC.
Explanation:The student has a parallelogram ABCD with given measures and needs to find the lengths of sides AB and BC. To find side AB, we can use trigonometric ratios in the triangle ACD, as angle DAC is known and AC is the hypotenuse. For side BC, we could use the fact that opposite sides in a parallelogram are equal, thus BC will equal AD which is the adjacent side to angle DAC in triangle ACD.
For AB, which is the opposite side to angle DAC, we can use:
AB = AC × sin(angle DAC) = 15 × sin(27°).
The specific value can be computed with a calculator.
Since parallelogram ABCD has opposite sides equal:
BC = AD
Therefore, we can find AD using the trigonometric ratio involving the cosine of angle DAC:
AD = AC × cos(angle DAC) = 15 × cos(27°).
The computed value will be the length of side BC.
A group of 100 students took a quiz Their average score was 76 points If the average score of the boys is 80 and the average score of the girls is 70, how many girls participated in the quiz?
Answer:
40
Step-by-step explanation:
Let the number of boys participating in the quiz be b and the number of girls be g. Since the total number is 100, we have our first equation.
b + g = 100
The average score was 76 points. This means the total score was 76 * 100 = 7600
The average score for the boys was 80 meaning total scores for the boys was 80b while that of the girls was 70g
Hence, we have our second equation:
80b + 70g = 7600
Now let’s put the equations together and solve simultaneously to get g which is the number of girls:
b + g = 100
80b + 70g = 7,600
Let’s simply make a substitution. We can say b = 100 - g. Substituting this will yield:
80(100 - g) + 70g = 7,600
8000 - 80g + 70g = 7600
10g = 400
g = 400/10 = 40
Final answer:
By creating and solving two equations that represent the average scores and total number of students, it was determined that 40 girls participated in the quiz.
Explanation:
To solve this problem, we can create two equations using the information about the average scores of the boys and girls, and the overall average. Let's denote the number of girls as G and the number of boys as B. We are told that there are a total of 100 students, which means:
Equation 1: G + B = 100
We're also told the average scores for boys and girls separately, and the overall average score for the group. We can express this with the following equation:
Equation 2: (80B + 70G) / 100 = 76
Now we can solve these equations simultaneously. We already have the total number of students from Equation 1, so we can use that to express B in terms of G: B = 100 - G. Then we can substitute this into Equation 2:
(80(100 - G) + 70G) / 100 = 76
Expanding this, we get:
8000 - 80G + 70G = 7600
Combining like terms, we have:
-10G = -400
Dividing both sides by -10 gives us G = 40.
So 40 girls participated in the quiz.
Abc is an isosceles triangle with ba=bc d lies on ac.Abd is an isosceles triangle with ab=ad angle abd=72 show that triangle bcd is isosceles.You must give a reason for each working out.
Answer:
ADB=72˚. base angles in an isosceles triangle are equal
72+72=144 180-144=36 BAD=36 ˚Angles in a triangle =180˚
180-72=108˚ BDC=108˚ angles on a straight line=180˚
Step-by-step explanation:
only three marks for this one
By exploiting the properties of isosceles triangles and the sum of angles in a triangle, we deduce that triangle BCD is isosceles with BC = BD.
Explanation:The student is asking how to prove that triangle BCD is isosceles given that triangles ABC and ABD are also isosceles with AB = BC and AB = AD, respectively, and angle ABD = 72 degrees. We can begin by noting that the sum of the angles in any triangle is 180 degrees. Because triangle ABD is isosceles with AB = AD, the angles ABD and ADB are equal, and since angle ABD is 72 degrees, angle ADB is also 72 degrees. Therefore, angle BAD, the remaining angle in triangle ABD, must be 180 - 72 - 72 = 36 degrees.
Since triangle ABC is also isosceles with AB = BC, angles ABC and BAC are equal. Angle BAD is part of angle BAC, which means angle BAC is also 36 degrees (since they both include angle BAD). Consequently, angle ABC is 36 degrees. The base angles of an isosceles triangle are equal, so angle BCA must also be 36 degrees. Because ABC is isosceles with AB = BC, and we have determined that angles ABC and BCA are equal, we conclude that angles BCD and CBD must also be equal, making triangle BCD isosceles, with BC = BD.
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I WILL GIVE BRAINLIEST FOR THE CORRECT ANSWER AND POINTS!
Answer:
36.5
Step-by-step explanation:
s² = [∑(min value - median value)² + (max value - median value)²] / (N - 1)
s² = [(23 - 59.5)² + (96 - 59.5)²] / (3 - 1)
s² = 2664.5 / 2
s² = 1332.25
s = √1332.25
s = 36.5
The average score of 100 teenage boys playing a computer game was 80,000 with a population standard deviation of 20,000. What is the 95% confidence interval for the true mean score of all teenage boys?
The 95% confidence interval for the true mean score of all teenage boys is approximately 76,080 to 83,920.
To calculate the 95% confidence interval for the true mean score of all teenage boys, we'll use the formula for the confidence interval:
[tex]\[ \text{Confidence Interval} = \bar{x} \pm Z \left( \frac{\sigma}{\sqrt{n}} \right) \][/tex]
where:
- [tex]\(\bar{x}\)[/tex] is the sample mean,
- Z is the Z-score corresponding to the desired confidence level,
- [tex]\(\sigma\)[/tex] is the population standard deviation, and
- n is the sample size.
For a 95% confidence interval, the Z-score is approximately 1.96.
Given:
- Sample mean [tex](\(\bar{x}\))[/tex] = 80,000
- Population standard deviation (\(\sigma\)) = 20,000
- Sample size (n) = 100
[tex]\[ \text{Confidence Interval} = 80,000 \pm 1.96 \left( \frac{20,000}{\sqrt{100}} \right) \][/tex]
Calculate the standard error (SE):
[tex]\[ SE = \frac{\sigma}{\sqrt{n}} = \frac{20,000}{\sqrt{100}} = 2,000 \][/tex]
Now substitute the values into the formula:
[tex]\[ \text{Confidence Interval} = 80,000 \pm 1.96 \times 2,000 \][/tex]
[tex]\[ \text{Confidence Interval} = 80,000 \pm 3,920 \][/tex]
The 95% confidence interval is from 80,000 - 3,920 to 80,000 + 3,920.
Suppose a and b are the solutions to the quadratic equation 2x^2-3x-6=0. Find the value of (a+2)(b+2).
Answer:
(a+2)(b+2) = 4
Step-by-step explanation:
We are given the following quadratic equation:
[tex]2x^2-3x-6=0[/tex]
Let a a and b be the solution of the given quadratic equation.
Solving the equation:
[tex]2x^2-3x-6=0\\\text{Using the quadratic formula}\\\\x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\text{Comparing the equation to }ax^2 + bx + c = 0\\\text{We have}\\a = 2\\b = -3\\c = -6\\x = \dfrac{3\pm \sqrt{9-4(2)(-6)}}{4} = \dfrac{3\pm \sqrt{57}}{4}\\\\a = \dfrac{3+\sqrt{57}}{4}, b = \dfrac{3-\sqrt{57}}{4}[/tex]
We have to find the value of (a+2)(b+2).
Putting the values:
[tex](a+2)(b+2)\\\\=\bigg(\dfrac{3+\sqrt{57}}{4}+2\bigg)\bigg(\dfrac{3-\sqrt{57}}{4}+2\bigg)\\\\=\bigg(\dfrac{11+\sqrt{57}}{4}\bigg)\bigg(\dfrac{11-\sqrt{57}}{4}\bigg)\\\\=\dfrac{121-57}{156} = \dfrac{64}{16} = 4[/tex]
A wildlife management organization is interested in estimating the number of moose in a particular region. Organization employees divide the region into 10 sections and randomly select four sections to survey the number of moose present. What sampling method is being used? a. Cluster sampling b. Systematic sampling c. Judgment sampling d. Stratified random sampling
Answer: Why are they increasing the moose?
Step-by-step explanation: Well I’m assuming this is in Canada. therefore, this has to be D
one college states that the number of men, M, and the number of women, W, receiving bachelor degrees t years since 1980 can be modeled by the function M(t)=526-t and W(t)=474+2t, respectively. Let N be the total number of students receiving bachelor's degrees at the college t years since 1980. Write an expression for N(t)
Answer:
[tex]N(t) = 1000 +t[/tex]
Step-by-step explanation:
It is given that,
Number of Men receiving degree are = M(t) = 526-t
Number of women receiving degree are = W(t) = 74+2t
The total number of students receiving the degree is given by,
sum of both Men and Women receiving the degrees.
Thus, N(t) = M(t) + W(t)
N(t) = (526-t) + (474+2t)
N(t) = 1000 + t
Thus, the number of students receiving the degree is given by N(t) = 1000 + t .
Answer:
Step-by-step explanation:
The greatest common divisor of two positive integers less than $100$ is equal to $3$. Their least common multiple is twelve times one of the integers. What is the largest possible sum of the two integers?
Answer:
129
Step-by-step explanation:
Let a and b be two numbers.
We have been given that the greatest common divisor of two positive integers less than 100 is equal to 3. We can represent this information as [tex]GCD(a,b)=3[/tex].
Their least common multiple is twelve times one of the integers. We can represent this information as [tex]LCM(a,b)=12a[/tex].
Now, we will use property [tex]GCD(x,y)*LCM(x,y)=xy[/tex].
Upon substituting our given values, we will get:
[tex]3*12a=ab[/tex]
[tex]36a=ab[/tex]
Switch sides:
[tex]ab=36a[/tex]
[tex]\frac{ab}{a}=\frac{36a}{a}[/tex]
[tex]b=36[/tex]
Now, we need to find a number less than 100, which is co-prime with 12 after dividing by 3.
The greatest multiple of 3 less than 100 is 99, but it is not co-prime with 12 after dividing by 3.
Similarly 96 is also not co-prime with 12 after dividing by 3.
We know that greatest multiple of 3 (less than 100), which is co-prime with 12, is 93.
Let us add 36 and 93 to find the largest possible sum of the required two integers as:
[tex]36+93=129[/tex]
Therefore, the required largest possible sum of the two integers is 129.
At the movie theater child admission is 6000 and $.30 an adult mission is $9.60 on Wednesday 172 tickets were sold for a total sales of 1403 70 how many tickets were sold that day
Answer:
The number of child tickets sold was 75 and the number of adult tickets sold was 97
Step-by-step explanation:
The correct question is
At the movie theater child admission is $6.30 an adult admission is $9.60 on Wednesday 172 tickets were sold for a total sales of $1403.70 How many child tickets and adult tickets were sold that day?
Let
x ----> number of child tickets sold
y ----> number of adult tickets sold
we know that
[tex]x+y=172[/tex] ----> equation A
[tex]6.30x+9.60y=1,403.70[/tex] -----> equation B
Solve the system by graphing
Remember that the solution of the system is the intersection point both lines
Using a graphing tool
The intersection point is (75,97)
see the attached figure
therefore
The number of child tickets sold was 75 and the number of adult tickets sold was 97
To solve this problem, set up a system of equations based on the given information. Then use the substitution method to solve for the variables. 69 child tickets and 103 adult tickets were sold on that day.
Explanation:To solve this problem, we can set up a system of equations.
Let's define the number of child tickets sold as x and the number of adult tickets sold as y.
We know that the cost of a child ticket is $6.00 and the cost of an adult ticket is $9.60.
So, the total cost of all the child tickets is 6x and the total cost of all the adult tickets is 9.60y.
Given that a total of 172 tickets were sold for a total of $1403.70, we can set up the following equations:
6x + 9.60y = 1403.70 (equation 1)x + y = 172 (equation 2)Now we can solve this system of equations using any method we prefer. Let's use the substitution method.
Rearrange equation 2 to solve for x: x = 172 - ySubstitute this expression for x into equation 1: 6(172 - y) + 9.60y = 1403.70Simplify and solve for y: 1032 - 6y + 9.60y = 1403.70Combine like terms: 3.60y = 371.70Divide both sides by 3.60: y = 103Substitute this value for y back into equation 2 to find x: x + 103 = 172Subtract 103 from both sides: x = 69Therefore, 69 child tickets and 103 adult tickets were sold on that day.
The crude association between occupational exposure and lung cancer (outcome) among the study sample was 8.4. When data were stratified by alcohol intake, the associations were 2.2 (for non-drinkers) and 14.5 (for drinkers). Assume that all (crude, and stratified) measures of association were statistically significant. Alcohol use was (use 15% difference rule):
a. An effect modifier
b. A potential confounder
c. A random error
d. A confounder
Answer:
Option D
Step-by-step explanation:
This are variables that have relationship with the outcome and exposure that is the confounding effect of alcohol on cancer is the fact that an alcohol consumers are more likely to smoke and smokers are likely to have cancer.
Solve for x. The triangles in each pair are similar.
Answer:
Step-by-step explanation:
You need to pay very close attention to the triangle similarity statement. This says that triangle NML is similar to triangle NVU. But if you look at the way that triangle NVU is oriented in its appearance, it's laying on its side. We need to set it upright so that angle N is the vertex angle, angle V is the base angle on the left, and angle U is the base angle on the right. When we do that we see that sides NV and NM are corresponding and exist in a ratio to one another; likewise with sides VU and ML. Setting up the proportion:
[tex]\frac{NV}{NM}=\frac{VU}{ML}[/tex]
Filling in:
[tex]\frac{12}{36} =\frac{9}{9x}[/tex]
Cross multiply to get
324 = 108x
and x = 3
Stacey owns a lot that has 180 feet of front footage and contains 36,000 square feet. She purchases two lots adjacent to each side of his lot. These side lots are each 200 feet deep and contain 19,000 square feet. What is the total front footage of all three lots?
Step-by-step explanation:
Front footage of first lot = 180 ft
Area of each side lot = 19000 ft²
Depth of each side lot = 200 ft
We have
Area = Depth x Front footage
19000 = 200 x Front footage
Front footage = 95 ft
Total front footage = Front footage of first lot + 2 x Front footage of each side lot
Total front footage = 180 + 2 x 95
Total front footage = 180 + 190
Total front footage = 370 ft
The total front footage of all three lots is 370 ft