Coral bleaching that occurs because of the introduction of foreign substances is _______.
Unit 3 quiz / question 10 of 10 question 10 you are operating a pwc. what is most likely to create a blind spot that blocks other boats from seeing you?
A laser used to dazzle the audience at a rock concert emits blue light with a wavelength of 463 nm . calculate the frequency of the light.
The wavelength of light is given as 463 nm or can also be written as 463 x 10^-9 m. [wavelength = ʎ]
We know that the speed of light is 299 792 458 m / s or approximately 3 x 10^8 m / s. [speed of light = c]
Given the two values, we can calculate for the frequence (f) using the formula:
f = c / ʎ
Substituting the given values:
f = (3 x 10^8 m / s) / 463 x 10^-9 m
f = 6.48 x 10^14 / s = 6.48 x 10^14 s^-1
f = 6.48 x 10^14 Hz
Final answer:
The frequency of blue light with a wavelength of 463 nm is calculated using the speed of light and the formula for frequency, resulting in a frequency of 6.48 × 10¹⁴Hz.
Explanation:
To calculate the frequency of blue light emitted by a laser at a rock concert with a wavelength of 463 nm, we use the formula c = λf, where c is the speed of light (3.00 × 108 m/s), λ is the wavelength in meters, and f is the frequency in Hertz (Hz).
First, convert the wavelength from nanometers to meters: 463 nm = 463 × 10-9 meters.
Next, plug the values into the formula: f = c / λ = (3.00 × 10⁸ m/s) / (463 × [tex]10^-^9[/tex] m) = 6.48 × 10¹⁴ Hz.
Therefore, the frequency of the blue light is 6.48 × 10¹⁴Hz.
what exactly is the difference between a standing wave and destructive interference.
They seem to be the same thing apart from their outcomes.
Thank you for your time
The existence of quantized energy levels in an atom can be inferred from
The existence of quantized energy levels in an atom can be inferred from observations related to radiation, atomic spectra, and principles of quantum mechanics. For example, distinct lines in atomic spectra represent transitions between these energy levels, and Bohr's model suggests each orbit around the nucleus reflects a distinguished energy level.
Explanation:The existence of quantized energy levels in an atom can be inferred from the concept of radiation and atomic spectra. Atomic spectra are the electromagnetic emissions of individual atoms and molecules. They form in distinct lines, which from the concept of quantum mechanics, signify the transition of electrons between discrete energy levels, otherwise known as 'quantized' energy levels.
These energy levels are quantized, meaning they are represented by quantum numbers, which are integer values corresponding to particular energy levels, or orbits, of an electron in an atom. The energy levels are not continuous and an electron can only occupy these definite levels.
The Bohr model provides a picture of this, presenting the atom as a small, positively charged nucleus surrounded by electrons that travel in circular orbits around the nucleus, similar to planets revolving around the Sun. Each orbit corresponds to a particular energy level, and the electron can transition from one level to another by absorbing or emitting energy.
The energy of an electron in an atom is labeled with the principal quantum number (n), which varies as n = 1, 2, 3...
Therefore, the observations related to radiation, atomic spectra, and the principles of quantum mechanics can imply the existence of quantized energy levels in an atom.
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In a nuclear power plant, mechanical energy is created by turning a turbine from steam created by heating water from which of the following?
A)the burning of uranium
B)the fusion of uranium
C)the fission of uranium
Answer:
The answer is C)the fission of uranium.
Explanation:
The nuclear plant is an industrial installation that generates electrical energy from nuclear energy. Nuclear plants have reactors that are responsible for the fission of nuclear fuel atoms. such as uranium, thus transforming mechanical work into electrical energy.
A ray diagram shows that an object is placed between the focal point and the vertex of a convex mirror. What are the characteristics of the image produced by the object? inverted, smaller than object, real upright, smaller than object, virtual inverted, larger than object, real upright, larger than object, virtual
Answer:
B on EDGE2k21
Explanation:
trust me bih
how do you identify the number of valence electrons in an element using periodic table
Answer:
Sample Response: All elements in the same group of the periodic table have the same number of valence electrons. This made it possible to compare the valence of the alien elements to the valence of elements from our periodic table, and match the alien elements to the correct group. For example, our group 14 elements all have 4 valence electrons, so the alien element with 4 valence electrons had to be part of group 14 also.
Explanation:
If air resistance can be neglected, how does the acceleration of a ball that has been tossed straight upward compare with its acceleration if simply dropped?
If air resistance can be neglected, the acceleration will be the same for both the thrown ball and dropped ball which is 9.8 m/s² as only gravity is working on it.
What is air resistance?Air resistance can be defined as a force that is caused by air. The air strikes the front of an object, leading to decelerating its motion. The lesser the face area of a body, the lesser air striking the body, and the lesser the overall air resistance.
Air resistance opposes motion that occurs between air and another object. The object can exploit as it passes through the air because of air resistance. Gravity and air resistance are the only two forces of nature that shift on anything on Earth.
Air resistance force exerts in the opposite direction to an object moving in the air. Air resistance is a frictional force so the faster the body’s motion, the more will be air resistance.
In the absence of air resistance, only force due to gravity will act on an object and the gravitational acceleration will be the same for both upward and downward directions.
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Alcohol begins to affect your brain when
Alcohol affects the brain shortly after consumption, with BAC being a key factor in the extent of these effects, which include impaired motor skills and judgment. Chronic consumption can lead to tolerance and withdrawal, and during pregnancy, there's a risk of FASD. The liver metabolizes alcohol steadily, unaffected by external remedies like coffee.
Explanation:Alcohol begins to affect your brain shortly after consumption, with effects ranging from social disinhibition to impaired motor control and decision-making. The immediate effects of alcohol on the brain depend on the individual's blood alcohol concentration (BAC), which is influenced by age, sex, health condition, and the quantity of alcohol consumed. Acute alcohol ingestion can result in decreased reaction time, visual acuity, alertness, and behavioral control, leading to consequences such as lack of coordination, blurred vision, and impaired judgment. It is worth noting that chronic exposure to alcohol may cause adaptations in the brain's reward circuitry, increased tolerance, and potential withdrawal effects. Additionally, alcohol consumption during pregnancy can lead to fetal alcohol spectrum disorder (FASD) or fetal alcohol syndrome (FAS), with their respective long-term effects on the child.
Alcohol metabolism is a critical aspect of managing intoxication. The liver metabolizes alcohol at a rate of about 3.3 mmol/L (15 mg/dL) per hour, and no amount of coffee or a cold shower can speed up this process. Therefore, to avoid alcohol toxicity and its associated risks – such as road accidents and physiological disorders – it is essential to drink responsibly and allow sufficient time for the body to metabolize alcohol.
A wave with a short wavelength will also have a (2 points)
Select one:
a. high frequency and high energy.
b. high frequency and low energy.
c. low frequency and low energy.
d. low frequency and high energy.
If a 65-kg man undergoes a turning acceleration of 5 m/s2 during a running turn, what is the magnitude of force experienced by the foot due to the ground?
To turn while running, the foot must push off the ground, applying a cutting force while instantaneously supporting the weight of the body. This is a vector addition problem where we must account for the normal force on the foot (from the runner's weight) and the acceleration force. Since the weight of the foot is backing up is vertical and the turning force is horizontal, these two force vectors are perpendicular and will form a right triangle.
Only the magnitude matters, so we need not worry about the sign or angle direction.
Now, what's needed is the hypotenuse of a triangle with legs of
Fg = (65)(10) = 650 N and F = (65)(5) = 325 N.
This calculation can be approximated as √ (3002 + 7002) =
√ (90000+490000) = √ (580000) = √ (58 x 104) = √ (58) x 102 = 761
Answer:
Force, F = 715.11 newton
Explanation:
Given that,
Mass of the person, m = 65 kg
Acceleration of man during a running turn, [tex]a=5\ m/s^2[/tex]
We need to find the magnitude of force experienced by the foot due to the ground. It can be calculated using second law of motion as :
F = ma
[tex]F=65\ kg\times 5\ m/s^2[/tex]
F = 325 Newton
Here, the weight of the person and this force force a right angle triangle.
The wight of the person, W = mg
[tex]W=65\ kg\times 9.8\ m/s^2=637\ N[/tex]
So, the resultant for is, [tex]F_r=\sqrt{325^2+637^2}[/tex]
[tex]F_r=715.11\ N[/tex]
So, the f force experienced by the foot due to the ground is 715.11 newtons. Hence, this is the required solution.
If you lose __________, braking may cause the vehicle to steer left or right unpredictably.
Answer:
Steering control
Explanation:
If you lose Steering control , braking may cause the vehicle to steer left or right unpredictably. Steering is collection components and linkages that control the direction of wheel of vehicle on road. Once the steering control is lost , the driver is not able to guide the vehicle and on braking, the vehicle can move in any direction unpredictably.
Your friend just challenged you to a race through an obstacle course. You know in order to beat him, you must run 30 meters within 60 seconds in a southern direction. What does your average velocity need to be to win the race?
Answer:
velocity = 0.5 m/s Towards South
Explanation:
As we know that velocity is the ratio of displacement and time
so here it is given that object displaced by total displacement of d = 30 m
also we know that time taken is 60 seconds
now we know the formula as
[tex]v = \frac{displacement}{time}[/tex]
now plug in the values in it
[tex]v = \frac{30}{60}[/tex]
[tex]v = 0.5 m/s[/tex] Towards South
So the average velocity must be 0.5 m/s Towards South
Two particles are located on the x axis. particle 1 has a mass m and is at the origin. particle 2 has a mass 2m and is at x = +l. a third particle is placed between particles 1 and 2. where on the x axis should the third particle be located so that the magnitude of the gravitational force on both particle 1 and particle 2 doubles? express your answer in terms of l.
The solution would be like this for this specific problem:
The force on m is:
GMm / x^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] ->
1
The force on 2m is:
GM(2m) / (L - x)^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2]
-> 2
From (1), you’ll get M = 2mx^2 / L^2 and from
(2) you get M = m(L - x)^2 / L^2
Since the Ms are the same, then
2mx^2 / L^2 = m(L - x)^2 / L^2
2x^2 = (L - x)^2
xsqrt2 = L - x
x(1 + sqrt2) = L
x = L / (sqrt2 + 1) From here, we rationalize.
x = L(sqrt2 - 1) / (sqrt2 + 1)(sqrt2 - 1)
x = L(sqrt2 - 1) / (2 - 1)
x = L(sqrt2 - 1)
= 0.414L
Therefore, the third particle should be located the 0.414L x axis so that the magnitude of the gravitational force on both particle 1 and particle 2 doubles.
Using Newton's law of universal gravitation, we can set up equations to find the location of the third particle such that the gravitational force exerted on both particle 1 and particle 2 doubles. The third particle should be placed at the position solved from these equations, either closer to particle 1 or further away.
Explanation:The location of the third particle that could double the gravitational force on both particle 1 and 2 can be achieved by using Newton's law of universal gravitation. This law states that every point mass attracts every other point mass by a force acting along the line intersecting the two points. The force is proportional to the product of the two masses and inversely proportional to the square of the distance between them.
For particle 1 and the third particle, if we denote the mass of the third particle as m3 and its position as x3, the gravitational force F1 on particle 1 is given by F1 = G*m*m3/x3^2. Similarly, for particle 2 and the third particle, the gravitational force F2 on particle 2 is also given by F2 = G*2m*m3/(l-x3)^2.
According to the question, both the gravitational force on particle 1 and particle 2 doubles when the third particle is added. Therefore, we can set up the following equations: 2F1 = G*m*m3/x3^2 and 2F2 = G*2m*m3/(l-x3)^2. From the equations, we could solve for x3 to find the location of the third particle.
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A meteoroid is traveling east through the atmosphere at 18.3 km/s while descending at a rate of 11.5 km/s. what is its speed, in km/s?
The speed of the meteoroid is calculated by using the Pythagorean theorem and considering its horizontal and vertical speeds as vectors. Plugging in the given values, the meteoroid's speed is approx 21.72 km/s.
Explanation:To calculate the speed of the meteoroid, we can use the concept of vectors and Pythagorean theorem. The meteoroid has a horizontal speed (eastward movement) and a vertical speed (downward movement). The total speed is the magnitude of the resultant vector. This can be calculated using Pythagorean theorem as follows:
The Pythagorean theorem states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Speed = sqrt[(Horizontal speed)^2 + (Vertical speed)^2]
Plugging in the given values:
Speed = sqrt[(18.3 km/s)^2 + (11.5 km/s)^2]
After calculating, we found that the speed is approx 21.72 km/s.
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If the core of a supernova contains about one solar mass, the core will become a
Answer:
It will become a neutron star
Explanation:
For the solar mass of anything above 1.4, the mass will automatically become a neutron star. This is according to the Chandrasekhar limit. This limit determines that 1 solar mass will collapse to form a white dwarf of a solar mass above 1.4 .
describe an electromagnet and how it is used
An electromagnet is a type of magnet in which the magnetic field is produced by an electric current. The magnetic field disappears when the current is turned off. Electromagnets usually consist of insulated wire wound into a coil. A current through the wire creates a magnetic field which is concentrated in the hole in the center of the coil. The wire turns are often wound around a magnetic core made from a ferromagnetic or ferrimagnetic material such as iron; the magnetic core concentrates the magnetic flux and makes a more powerful magnet.
The main advantage of an electromagnet over a permanent magnet is that the magnetic field can be quickly changed by controlling the amount of electric current in the winding. However, unlike a permanent magnet that needs no power, an electromagnet requires a continuous supply of current to maintain the magnetic field.
Electromagnets are widely used as components of other electrical devices, such as motors, generators, relays, loudspeakers, hard disks, MRI machines, scientific instruments, and magnetic separation equipment. Electromagnets are also employed in industry for picking up and moving heavy iron objects such as scrap iron and steel.[2]
Electromagnets are temporary magnets powered by electric current with versatile applications in different fields.
**An electromagnet** is a piece of wire that generates a magnetic field when an electric current passes through it. Unlike permanent magnets, **electromagnets** can be turned on and off by controlling the flow of electricity. They are widely used in various applications such as electric motors, generators, MRI machines, and even in scrapyard cranes.
If a road does not have a bicycle lane, where must a bicyclist ride their bicycle?
Suppose you are asked to find the area of a rectangle that is 2.1cm wide by 5.6cm long. Your calculator answer would be 11.76cm^2. Now suppose you are asked to enter the answer to two significant figures.
A motorboat and a pwc are meeting head-on. which one is the stand-on vessel?
A motorboat and a PWC are meeting head-on, the stand-on vessel is generally the motorboat.
The motorboat is typically the stand-on vessel when a motorboat and a personal watercraft (PWC) collide head-on.
The vessel that has the right of way and must maintain its route and speed is referred to as the stand-on vessel. The PWC is the vessel that must surrender or give way.
The PWC should adjust its route or speed to safely pass behind or around the motorboat in order to avoid a collision.
It is crucial to remember that precise laws and guidelines could change depending on the jurisdiction and regional marine laws. It is usually advised to abide by the relevant laws and ordinances of the particular area or waterway.
Thus, the stand-on vessel is generally the motorboat.
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A 5.0 cm object is 6.0 cm from a convex lens, which has a focal length of 7.0 cm.
What is the distance of the image from the lens?
cm
What is the height of the image?
cm
Answer : The distance of the image from the lens is, -42 cm
The height of the image is, 35 cm
Solution :
First we have to calculate the image distance.
Formula used :
[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]
where,
f = focal length = 7 cm
p = object distance = 6 cm
q = image distance = ?
Now put all the given values in the above formula, we get the distance of the image from the lens.
[tex]\frac{1}{7cm}=\frac{1}{6cm}+\frac{1}{q}[/tex]
[tex]q=-42cm[/tex]
Therefore, the distance of the image from the lens is, 42 cm and the negative sign indicates that the image is virtual.
Now we have to calculate the height of the image.
Formula used :
[tex]\frac{h}{h'}=\frac{p}{q}[/tex]
where,
h = height of object = 5 cm
h' = height of image = ?
Now put all the given values in this formula, we get the height of the image.
[tex]\frac{5cm}{h'}=\frac{6cm}{-42cm}=-35cm[/tex]
Therefore, the height of the image is, 35 cm and the negative sign indicates that the image is inverted.
A. The distance of the image from the lens is –42 cm.
B. The height of the image is 35 cm
Data obtained from the question Height of object (Hₒ) = 5 cmObject distance (u) = 6 cmFocal length (f) = 7 cmImage distance (v) =? Height of image (Hᵢ) =? A. How to determine the image distanceThe image distance is defined as the distance of the image from the lens. Thus, it can be obtained as follow:
Object distance (u) = 6 cmFocal length (f) = 7 cmImage distance (v) =?1/v = 1/u – 1/f (convex lens
v = (uf) / (u –f)
v = (6 × 7) / (6 – 7)
v = 42 / – 1
v = –42 cm
B. How to determine the height of the image.The height of the image is the height of the image as displayed by the lens. It can be obtained as follow:
Height of object (Hₒ) = 5 cmObject distance (u) = 6 cmFocal length (f) = 7 cmImage distance (v) = –42 cmHeight of image (Hᵢ) =?v / u = Hᵢ / Hₒ
–42 / 6 = Hᵢ / 5
–7 = Hᵢ / 5
Cross multiply
Hᵢ = –7 × 5
Hᵢ = –35 cm
NOTE: The negative sign indicates that the image is a virtual image.
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The elements required for a fire to start are
a ball is tossed int the air and rises to a height of 12m. How long is the ball in the air?
If the force of gravity between a book of mass 0.50 kg and a calculator of 0.100 kg is 1.5 × 10-10 N, how far apart are they? (___/ 2)
If the distance between two masses is tripled, the gravitational force between them changes by a factor of
The gravitational force between them changes by a factor if, the distance between two masses is tripled, is 1 / 9.
What is gravitational force?In mechanics, the force of attraction that acts on all matter is known as gravity, also known as gravitation. It does not affect how daily stuff behaves internally because it is by far the weakest known force in nature. In contrast, it regulates the paths of objects in the solar system and elsewhere in the universe, as well as the architecture and evolution of stars, galaxies, and the entire universe, through its extensive and universal action.
Given:
If the distance between two masses is tripled,
Calculate the initial gravitational force as shown below,
Initial gravitational force = Gravitation constant × m₁ × m₂ / d²
Here, d is the distance between objects,
Final gravitational force = Gravitation constant × m₁ × m₂ / d²
Final gravitational force = Gravitation constant × m₁ × m₂ / (3d)²
Final gravitational force = Gravitation constant × m₁ × m₂ / 9d²
Thus, the gravitational force between them changes by a factor of 1 / 9.
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All vehicles are required to stop within how many feet of a railroad crossing when a train is approaching
What is the proper technique for anchoring?
A horizontal compass is placed 21 cm due south from a straight vertical wire carrying a 36 a current downward. in what direction does the compass needle point at this location? assume the horizontal component of the earth's field at this point is 0.45 â 10-4 t and the magnetic declination is 0°.
The needle of a compass will always lies along the magnetic
field lines of the earth.
A magnetic declination at a point on the earth’s surface
equal to zero implies that
the horizontal component of the earth’s magnetic field line
at that specific point lies along
the line of the north-south magnetic poles.
The presence of a
current-carrying wire creates an additional
magnetic field that combines with the earth’s magnetic field.
Since magnetic
fields are vector quantities, therefore the magnetic field of
the earth and the magnetic field of the vertical wire must be
combined vectorially.
Where:
B1 = magnetic field of the earth along the x-axis = 0.45 × 10 ⁻ ⁴ T
B2 = magnetic field due to the straight vertical wire along the y-axis
We can calculate for B2 using Amperes Law:
B2 = μ₀ i / [ 2 π R ]
B2 = [ 4π × 10 ⁻ ⁷ T • m / A ] ( 36 A ) / [ 2 π (0.21 m ) ]
B2 = 5.97 × 10 ⁻ ⁵ T = 0.60 × 10 ⁻ ⁴ T
The angle can be
calculated using tan function:
tan θ = y / x = B₂ / B₁ = 0.60 × 10 ⁻ ⁴ T / 0.45 × 10 ⁻ ⁴ T
tan θ = 1.326
θ = 53°
The compass needle points along the direction of 53° west of
north.
The compass needle near a current-carrying wire aligns northwest due to the combined influence of the Earth's northward magnetic field and the wire's westward magnetic field at that location.
A compass needle, which is a tiny bar magnet, aligns with the magnetic field it experiences. In this scenario, both the Earth's magnetic field and the magnetic field created by a vertical current-carrying wire influence the needle.
The magnetic field produced by a straight current-carrying wire is given by the right-hand rule: point your thumb in the direction of the current (downward) and curl your fingers around the wire.
Your fingers show the direction of the magnetic field; moving in circles around the wire.
At the position of the compass (21 cm south of the wire), the wire's magnetic field will circulate clockwise when viewed from above.Thus, directly south of the wire, the magnetic component from the wire is directed towards the west.The Earth's magnetic field at this location points northward with a horizontal component of 0.45 × 10⁻⁴T.The resultant magnetic field at the compass position is the vector sum of the Earth's northward field and the wire's westward field.Therefore, the compass needle will align with this resultant field, pointing in a direction northwest.
A charge Q generates an electric field of strength E at a distance d away. Determine the electric field strength at d and 2d, respectively:
The electric field strength at a distance 2d from a charge Q is one-fourth the electric field strength at a distance d, due to the inverse square nature of the electric field with respect to distance.
Explanation:The question pertains to the concept of the electric field created by point charges in physics. To determine the electric field strength E at a distance d and at a distance 2d from a charge Q, we use Coulomb's law, which relates the electric field E to the charge Q and the distance r from the charge as E = kQ/r², where k is Coulomb's constant (approximately 8.99 × 10⁹ Nm²/C²).
For the charge Q generating a field strength E at a distance d, the electric field at distance d is simply E. However, at a distance 2d, since the distance from the charge is doubled, the electric field strength is reduced by a factor of four (since it's inversely proportional to the square of the distance). Therefore, the electric field strength at 2d is E/4.
Example Calculation: If the original distance is 2.00 × 10⁻² m and charge is 5.00 × 10⁻¹ C, the electric field at distance d can be calculated using the formula provided. If E is known initially at distance d, to find the field at 2d, simply divide that E by 4.
Final answer:
The electric field strength at a distance 2d from a charge Q is one-fourth the electric field strength at a distance d, according to the equation E = kQ/r², where E is electric field strength, k is Coulomb's constant, Q is the charge, and r is the distance.
Explanation:
The question deals with determining the electric field strength at distances d and 2d from a charge Q. The electric field strength created by a point charge is given by the equation E = kQ/r², where k is Coulomb's constant, Q is the charge, and r is the distance from the charge.
At a distance d, the electric field strength is E. To find the electric field strength at 2d, we simply plug in the new distance into the equation, which results in E = kQ/(2d)². Because 2d is simply twice the original distance, the denominator becomes four times as large, resulting in an electric field strength at 2d that is ¼ of what it was at d. Therefore, the electric field strength at 2d will be E/4.