What's 9080 each number in expanded notation

Answers

Answer 1
expanded notation is basically writing out the value of each number added together, so the answer is 9000+000+80+0, if you want to include the blank hundreds and ones places, but otherwise its 9000+80

Related Questions

if you roll a normal dice 120 times. How many odd numbers would you expect to get

Answers

1,3,5 out of 1,2,3,4,5,6.
This means there's a 50% chance of an odd number, so 120/2 = 60

Answer:

60 odd numbers

Step-by-step explanation:

A normal dice has 6 different sides numbered from 1 to 6, each side has the same probability of appearing when you roll the dice, i.e., in the long run each number will appear 1/6 of the times. We have three different odd numbers in a normal dice each will appear 1/6 of the times in the long run. Therefore, in the long run we hope to get 3/6 = 1/2 of the times an odd number and rolling the dice 120 times will produce about 120(1/2) = 60 odd numbers.

In the triangle below, what ratio is sin θ?

Answers

Bringing to mind SOHCAHTOA, we remember that the sine is the opposite divided by the hypotenuse.
Thus, our answer is [tex]$\frac{36}{39}=\boxed{\frac{12}{13}}$[/tex].

Answer:  The required ratio is [tex]\dfrac{12}{13}.[/tex]

Step-by-step explanation:  In the given triangle, we are to find the ratio of sinθ.

We know that

in a right-angled triangle, the ratio sine of an angle is given by the length of the perpendicular divided by the length of the hypotenuse.

For the given right-angled triangle, we get

[tex]\sin\theta=\dfrac{perpendicular}{hypotenuse}\\\\\\\Rightarrow \sin\theta=\dfrac{36}{39}\\\\\\\Rightarrow \sin\theta=\dfrac{12}{13}.[/tex]

Thus, the required ratio is [tex]\dfrac{12}{13}.[/tex]

Determine whether a triangle can be formed with the given side lengths. If so, use Heron's formula to find the area of the triangle. a = 240 b = 123 c = 207

Answers

Triangle inequality rule states that the sum of eachpair of sides must be greater than the third sides.
 240 + 123 > 207 true
240 + 207 > 123 true
123 + 207 > 240 true

A = √(s(s-a)(s-b)(s-c))
s is the semi-perimeter (a + b + c)/2
s = (240 + 123 + 207)/2
s = 285
A = √(285*(285-249)(285-123)(285-207))
A = 12,730 units^2

Find the possible value or values of n in the quadratic equation 2n^2-7n+6=0

Answers

Using the quadratic formula:
n = [-b +- sq root (b^2 -4*a*c)] / 2a
n = [--7 +- sq root (49 -4*2*6)] / 4
n = [--7 +- sq root (49 -48)] / 4
n = [--7 +- sq root (1)] / 4
n1 = (7 + 1) / 4
n1 = 2

n2 = (7 -1) / 4
n2 = 1.5


How do scientists communicate the results of investigations? A. by publishing articles in scientific journals B. by giving talks at scientific conferences C. by exchanging e-mails D. all of the above

Answers

A) by publishing articles in scientific journals-
because science progresses by them sharing their progress and results
A) by publishing articles in scientific journals
because science progresses by them sharing their progress and results, hope this helps.

What is the value of x 20 35 60 70

Answers

x+40 =3x (vertical angles)
2x = 40
x = 20

answer  is A. 20 (first choice)
TRS and VRW are vertical angles, therefore they're congruent

x + 40 = 3x
40 = 2x
20 = x

x is 20

What number must you add to complete the square x^2+12x=-5
A 12
B 36
C 144
D 6

Answers

The general form of a quadratic equation is,

                         Ax² + Bx + C = 0

A, B, and C are all numerical coefficients of the terms in the equation. 

In order to complete the square, we divide all numerical coefficients by 2 and A. Then, square the value of B/2A. Performing this operation for this item,

                         n = (B/2A)²

Substituting the known values,

                         n = (12/2(1))² = 36

Thus, the missing number in this item is 36 and the final expression becomes,

                    x² + 12x + 36 = -5 + 36

Answer: B. 36

Step-by-step explanation: Trust me!

Which of the following are pairs of congruent segments?
Check all that apply.

Answers

A. BC and PO
C. AB and AP
E. IJ and LM
According to how close the segments are relative to the center, corners, ad each other, I believe the answer is A, C and E.

For the ordered pair, give three other ordered pairs with θ between −360° and 360° that name the same point. (3, 135°)

Answers

Final answer:

Three other ordered pairs with θ between −360° and 360° that name the same point as (3, 135°) are (−243, −45°), (−177, −15°), and (315, 495°).

Explanation:

The ordered pairs (−243, −45°), (−177, −15°) and (315, 495°) all name the same point as (3, 135°) with θ between −360° and 360°.

To find these ordered pairs, you can add or subtract 360° to the given angle of 135° while keeping the x-coordinate constant at 3.

For example, you could subtract 360° from 135° to get −225° and combine it with the x-coordinate of 3 to get the ordered pair (3, −225°).

Rewrite the equation in vertex form and then give the vertex of the quadratic equation

Answers

hello :

: f(x) = a(x-h)²+k is the equation in vertex form  of the quadratic equation
when  the vertex is ( h , k)

You are helping a partner in your group with their problem. What mistake did they make solving the system?
3x+y-9
-2x+y=4

Students work when solving the second equation for y:
Y=2x+4
-2x+(2x+4)=4
-2x+2x+4=4
4=4

The students response is there are indefinitely many solutions and this is not correct. Explain the mistake.

Answers

The answer is supposed to be that there is no solution

Identify the volume and surface area of the sphere

Answers

volume = 4/3 x PI x r^3

 in terms of pi. multiply r^3 x 4/3 = 18432PI

surface area = 4pir^2

in terms of pi multiply r^2 x 4 = 2304PI

What is the solution to the system that is created by the equation y=-x+6 and the graph shown below?

Answers

the graph graphed is y=1/2x

so
y=1/2x and y=-x+6
y=y so
1/2x=-x+6
times 2 both sides
x=-2x+12
add 2x both sides
3x=12
x=4

sub back
y=1/2x
y=1/2(4)
y=2

(4,2) is the solution
1st let/s find the equation of the graph shown. It has te form of y₁ =mx since it oases by the origin. Moreover we notice that the slope m = rise/run = 1/2. hence the equation IS y₁ = (1/2)x.
To find the solution of y₁ = 1/2 x and y= -x + 6, let's y=y₁

-x + 6 = 1/2 x ↔ -2x +12 = x ↔ -3x= -12  and x = 4. For x = 4 , y =2.

And the solution is the intersection point between y and y₁ which is nothing but the solution or te coordinate of this point that is (4,2)

The function y=-2+5sin(pi/12(x-2)), what is the minimum value?

Answers

Answer:

-7

Step-by-step explanation:

bla bla bla 20 characters

Answer:

-7

Step-by-step explanation:

We are given that   a function

[tex]y=-2+5 sin(\frac{\pi}{12}(x-2))[/tex]

We have to find the minimum value of y.

We know that range of sin x is [-1,1].

[tex]-1\leq sin(\frac{\pi}{12}(x-2))\leq 1[/tex]

[tex]-5\leq 5sin(\frac{\pi}{12}(x-2))\leq 5[/tex]

[tex]-5-2\leq -2+5sin(\frac{\pi}{12}(x-2))\leq 5-2[/tex]

[tex]-7\leq -2+5sin(\frac{\pi}{12}(x-2))\leq 3[/tex]

[tex]-7\leq y\leq 3[/tex]

Maximum value of y=3

Minimum value of y=-7

Hence, the minimum value of given function =-7

BC is tangent to circle A at B and to circle D at C. What is AD to the nearest tenth? Look at image attached.

Answers

A tangent line to a circle is perpendicular to the radius drawn to the tangent point   ⇒
AB ⊥ BC and CD ⊥ BC  ⇒ ABCD is a right trapezoid. 

You can find the AD using formula:

[tex]AD= \sqrt{BC^2+(AB-CD)^2} \\ \\ AD= \sqrt{19^2+(10-7)^2} = \sqrt{361+9}= \sqrt{370} \approx 19.2[/tex]

Answer:

1. 19.2

Step-by-step explanation:    

Please find the attachment.

Since we know that radius is perpendicular to tangent of a circle. So AB will be perpendicular to BC at c and DC is perpendicular to CB at C.

Now we will construct a perpendicular line to radius AB at point E from the center of our small circle. Since we have two right angles at point B and C so we will also have right angles at point E and D as well.    

Length of CD is is 7 so length of BE will be 7 as well and length of EA will be 10-7=3. Length of DE will be equal to length BC that is 19.

Now we have formed a right triangle and now we will use Pythagoras theorem to find the length of AD.  

[tex](AD)^{2}=(DE)^{2}+(EA)^{2}[/tex]    

Upon substituting our values in above formula we will get,

[tex](AD)^{2}=(19)^{2}+(3)^{2}[/tex]

[tex](AD)^{2}=361+9[/tex]

[tex](AD)^{2}=370[/tex]

Upon taking square root of both sides of our equation we will get,

[tex]AD=\sqrt{370}[/tex]  

[tex]AD=19.2353840616713448\approx 19.2[/tex]

Therefore, the length of AD will be 19.2 and 1st option is the correct choice.

A=1/2(a+b)h solve for h

Answers

A=1/2(a+b)h ↔ A= [(a+b).h]/2

Cross multiplication:→2A = (a+b).h.

Divide both sides by (a+b):

2A/(a+b) =h

Cross multiply then divide

The proof that ΔQPT ≅ ΔQRT is shown. Given: SP ≅ SR Prove: ΔQPT ≅ ΔQRT What is the missing reason in the proof? Statements Reasons 1. SP ≅ SR 1. given 2. ST ⊥ PR 2. converse of the perpendicular bisector theorem 3. PT ≅ RT 3. ? 4. QT ⊥ PR 4. ST and QT name the same line. 5. QP ≅ QR 5. perpendicular bisector theorem 6. ΔQPT ≅ ΔQRT 6. HL theorem definition of perpendicular bisector definition of congruence reflexive property substitution property

Answers

Answer:

A. definition of perpendicular bisector

Step-by-step explanation:

I JUST TOOK THE TEST!!!!!!

Answer:

The correct option is a) perpendicular bisector definition.

Step-by-step explanation:

Given :

Triangle QPT is similar to triangle QRT.

[tex]\rm SP \cong SR[/tex]

To find : Why [tex]\rm PT \cong RT[/tex]

Solution :

According to perpendicular bisector definition -

Perpendicular Bisector is a line or a segment perpendicular to a segment that passes through the midpoint of the segment. Any point on the perpendicular bisector is equidistant from the endpoints of the line segment.

Therefore, [tex]\rm PT \cong RT[/tex]

Hence option a) is correct.

For more information, refer the link given below

https://brainly.com/question/24753075?referrer=searchResults

What is the solution to the following system of equations? X-2y=2, x-2y=-2

Answers

x + 2y = 2
x - 2y = -2
-------------add
2x = 0
x = 0

x + 2y = 2
0 + 2y = 2
2y = 2
y = 2/2
y = 1

solution is (0,1)
Final answer:

The given system of equations, x - 2y = 2 and x - 2y = -2, are parallel lines and do not intersect, thus there is no common solution to the system.

Explanation:

In mathematics, to find the solution to a system of equations, we generally try to find the values of variables that satisfy all the equations in the system. When looking at the given equations: x - 2y = 2 and x - 2y = -2, we can see that there is something strange. These two equations are equivalent to each other, meaning they represent the same line. This is due to the fact that both equations have the same coefficients for the x and y variables (1 and -2 respectively). So, if two lines are equivalent, they are essentially the same line. This means there are infinitely many solutions which satisfy this system of equations, since all points on the line satisfy both equations. However, if two lines have the same coefficients but different constants (the numbers without the variables), as in our case, then they are parallel and do not intersect, indicating that there's no solution for the system of equations. Therefore, this system of equations has no solution.

Learn more about System of Equations here:

https://brainly.com/question/35467992

#SPJ2


Find the midpoint of C and E. Simplify completely.



1. (–4,–3)
2. (0,–3)
3. (–4,–1)
4. (0,–1)
5. none of these

Answers

C=(-4,-4)

E = (4,-2)

-4 +4 = 0/2 =0

-4+-2 = -6/2 = -3

(0,-3)

What are all the possible 3 digit number combinations 0-9?

Answers

that would be 10 x 10 x 10  = 1000

Which of the following is a simpler form of the expression sin (theta)sec(theta)÷ cos(theta)tan(theta)

Answers

Answer: [tex]sec \theta[/tex].


Step-by-step explanation: Given expression : [tex]\frac{sin \theta \ sec \theta }{cos \theta \ tan \theta} .[/tex]

We know,

[tex]sec \theta = \frac{1}{cos \theta}[/tex]

[tex]tan \theta = \frac{sin \theta}{cos \theta}[/tex]

Substituting those values in given expression, we get

[tex]\frac{sin \theta \ sec \theta }{cos \theta \ tan \theta} .[/tex] =[tex]\frac{sin \theta\ \frac{1}{cos \theta} } {cos \theta\ \frac{sin \theta}{cos \theta} }[/tex]

= [tex]\frac{sin \theta \ cos \theta}{cos \theta \ cos \theta \ sin \theta}[/tex]

Crossing out [tex]sin \theta \ cos \theta[/tex] from top and bottom, we get

=[tex]\frac{1}{cos \theta }[/tex]

= [tex]sec \theta[/tex].


Answer:

The simplified form of the given expression [tex]\frac{\sin\theta \cdot \sec\theta}{\cos\theta\cdot \tan\theta}[/tex] is  [tex]\sec\theta[/tex]

Step-by-step explanation:

Given: Expression [tex]\frac{\sin\theta \cdot \sec\theta}{\cos\theta\cdot \tan\theta}[/tex]

We have to writ the given expression in simplified form.

Consider , The given expression [tex]\frac{\sin\theta \cdot \sec\theta}{\cos\theta\cdot \tan\theta}[/tex]

Since, we know,

[tex]\sec\theta=\frac{1}{\cos\theta}[/tex]

and  [tex]\tan\theta=\frac{\sin\theta}{\cos\theta}[/tex]

Substitute, we have,

[tex]\frac{\sin\theta \cdot \sec\theta}{\cos\theta\cdot \tan\theta}=\frac{\sin\theta \cdot\frac{1}{\cos\theta}} {\cos\theta\cdot \frac{\sin\theta}{\cos\theta} }[/tex]

Simplify, we have,

[tex]=\frac{\frac{1}{\cos\theta}} {\cos\theta\cdot \frac{1}{\cos\theta} }[/tex]

Simplify further, we get,

[tex]=\frac{1}{\cos\theta}=\sec\theta[/tex]

Thus, The simplified form of the given expression [tex]\frac{\sin\theta \cdot \sec\theta}{\cos\theta\cdot \tan\theta}[/tex] is  [tex]\sec\theta[/tex]

Find the length of arc xpy with a radius of 12m. leave in terms of pi./Users/alymcclellan/Desktop/Screen Shot 2017-07-31 at 10.25.17 PM.png

Answers

If you have the measure of the central angle, you use the formula 2pi r where r is the radius by the fraction value of the arc length

(08.06)The following data show the height, in inches, of 11 different garden gnomes:
2 9 1 23 3 7 10 2 10 9 7
After removing the outlier, what does the mean absolute deviation of this data set represent?
On average, the height of a garden gnome varies 3.2 inches from the mean of 7 inches.
On average, the height of a garden gnome varies 3.6 inches from the mean of 6 inches.
On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.
On average, the height of a garden gnome varies 3.6 inches from the mean of 7 inches.

Answers

Answer:

The correct statement is:

On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.

Step-by-step explanation:

We are given a data of 11 gardens as:

2   9    1    23    3    7    10    2    10    9     7

Now on removing the outlier i.e. 23 (since it is the very large value as compared to other data points) the entries are as follows:

x         |x-x'|        

2          4              

9          3              

1           5              

3          3              

7           1                

10         4              

2           4              

10          4              

9           3              

7            1              

Now mean of the data is denoted by x' and is calculated as:

[tex]x'=\dfrac{2+9+1+3+7+10+2+10+9+7}{10}\\\\x'=\dfrac{60}{10}\\\\x'=6[/tex]

Hence, Mean(x')=6

Now,

∑ |x-x'|=32

Now mean of the absolute deviation is:

[tex]\dfrac{32}{10}=3.2[/tex]

This means that , On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.

Answer: Please don’t judge me but I agree with the other guy, it’s (C.
Credits to him ♥️

The following set of coordinates most specifically represents which figure?

(−5, 6), (−1, 8), (3, 6), (−1, 4)

Answers

I drew it roughly  

All 4 sides are = sqrt20
Looks like a rhombus

The correct answer is C: Rhombus. This is how you find your answer: desmos.com because you just plant in the ordered pair into the program and it plots out the shape for you. The only thing you need to know is your shapes and you should be set.

Will give brainliest to correct and best explained answer.

Answers

see picture for steps and answer

Regression and modeling with functions

Answers

I used scatter plot graph in the insert graph function of excel and added a trend line that shows the equation of the line of best fit and the r. 

The line that can be applied in this function is linear with an equation of y = 3800.6x - 5223.6 and the regression is r² = 0.8925. The y intercept represents when the starting point of a line starts. It is a strong correlation since the value of r² that is equal to 0.8925 is close to 1. We can solve the value of the investment after 6 years using the equation above.

y = 3800.6x - 5223.6
y = 3800.6(6) - 5223.6
y = 17,580

If a wheel with a radius of 70 inches spins at a rate of 600 revolutions per minute, find the approximate linear velocity in miles per hour. use pi= 3.14

Answers

The linear velocity will be the tangent velocity of the points in the extreme of the wheel.

Tangent velocity = angular velocity * radius

angular velocity = 2π * frequency

=> angular velocity 2*3.14*600 rad/min = 3,768 rad/min

tangent velocity = 70 in * 3768 / min = 263,760 in/min

Convert to m/s =>

263,760 in/min * 2.54 cm / in * 1m / 100cm * 1min/60s = 111.7 m/s

Answer: velocity = 111.7 m/s

Find f'(x) for f(x) = −7x2 + 4x − 10.

Answers

The answer is D, none of these

angie andKenny play online video games angie buys 1 software package and 3 months of game play. Kenny buys 1 software package and 4 months of game play. each software package costs $20. if there total cost is $117 what is the cost of one month game play

Answers

Angie buys 1 software package and 3 months of game play
Kenny buys 1 software package and 4 months of game play
price of each software package = $20
total cost = $117
cost of one month game play = ?
let y is the cost of one month play
Angie buys 3 months game play and paid $20 = 20 + 3y
Kenny buys 4 months game play and paid $20 = 20 + 4y
total cost of both is $117
So the equation becomes,
(20 + 3y) + (20 + 4y) = 117
7y + 40 = 117
7y = 117 - 40
7y = 77
dividing with 7 on both sides, we get
y = 11
so, $11 is the cost of one month game play

Difference between algebra 1 and pre-algebra

Answers

 Pre algebra basically lay the foundation for what you'll learn in algebra 1. 

Answer:

Step-by-step explanation:

The prefix Pre stands for before and algebra is math so pre algebra is informing you about what you will be learning before it actually happens.

Algebra is math for ninth graders that if you fail makes you have to take it until you pass it.

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