Answer:
Step-by-step explanation:
I think its 823 ppm?
I'm not sure
What is the sum of the polynomials? (6x + 7 + x2) + (2x2 - 3)
Answer:
3x^2+6x+4 is the answer :D
The sum of the polynomials (6x + 7 + x²) + (2x² - 3) is 3x² + 6x +4 after adding the like terms.
What is polynomial?Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.
[tex]\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n[/tex]
We have given polynomials:
= (6x + 7 + x²) + (2x² - 3)
To add the polynomials, we must add the like terms:
= 3x² + 6x +4
Thus, the sum of the polynomials (6x + 7 + x²) + (2x² - 3) is 3x² + 6x +4 after adding the like terms.
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The measurement of 2 and justification
M<2=105. They must add up to 180.
A grocer wishes to blend two different coffee brands in order to make a blend of 400 pounds to sell at $3.00 a pound. If he uses a brand of coffee worth $2.70 a pound with another brand worth $3.20 a pound, how many pounds of each does he use?
Step-by-step explanation:
Let's say x is the amount of $2.70/lb coffee and y is the amount of $3.20/lb coffee.
The total amount is:
x + y = 400
The total worth is:
2.70x + 3.20y = 3.00×400
2.7x + 3.2y = 1200
Solving the system of equations through substitution:
x = 400 - y
2.7 (400 - y) + 3.2y = 1200
1080 - 2.7y + 3.2y = 1200
0.5y = 120
y = 240
x = 160
The grocer uses 160 pounds of the $2.70/lb coffee and 240 pounds of the $3.20/lb coffee.
By solving a system of equations, we will see that they used 240 pounds of the $3.20 coffee and 160 pounds of the $2.70 coffee.
How to find the system of equations?First, we need to define the variables, we can use:
x = pounds of the $2.70 coffee used.y = pounds of the $3.20 coffee used.We know that they make 400 pounds of the mixture, then:
x + y = 400
We also know that the price of the mixture is $3.00 per pound, then we will have that:
x*$2.70 + y*$3.20 = 400*$3.00
So the system of equations is:
x + y = 400
x*$2.70 + y*$3.20 = 400*$3.00
To solve this, we isolate one of the variables in one of the equations. For example, I will isolate x on the first equation:
x = 400 - y
Now we can replace that on the other equation to get:
(400 - y)*$2.70 + y*$3.20 = 400*$3.00
And solve this for y.
400*$2.70 - y*$2.70 + y*$3.20 = 400*$3.00
y*$0.50 = 400*$3.00 - 400*$2.70 = 400*$0.30
y = ( 400*$0.30)/$0.50 = 240
Then we have:
x = 400 - y = 400 - 240 = 160
This means that they used 240 pounds of the $3.20 coffee and 160 pounds of the $2.70 coffee.
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How much interest does a $482 investment earn at 5% over 3 years?
Answer: $72.30
Step-by-step explanation:
[tex]I=P*r*t[/tex]
P is the principal amount, $482.00.
r is the interest rate, 5% per year, or in decimal form, 5/100=0.05.
t is the time involved, 3 years
The answer you're looking for is $72.30. To find this answer multiply $482 by 0.05 (five percent). From there you'll get 24.1, then multiply that by 3 (three years), and you'll get $72.30/ Hope that helps! :)
20 points!!! And Brainliest if possible!!! Use triangle JKL and triangle MPN to determine whether Don's claim is true or false.
Which of the following should Don use to prove the triangles are similar?
SSS
SAS
AAS
АА
Answer:
AA
Step-by-step explanation:
we know that
The AA postulate states that two triangles are similar if they have two corresponding angles that are congruent
In the triangle JKL find the measure of angle L
Remember that in a triangle the sum of the interior angles must be equal to 180 degrees
so
∠J+∠K+∠L=180°
substitute the given values
105°+50°+∠L=180°
∠L=180°-155°=25°
Compare the measure of two corresponding angles of triangles JKL and MPN
∠J=∠M=105°
∠L=∠N=25°
therefore
The triangles JKL and MPN are similar by AA similarity postulate
What is the equation for f-1(x)? Help needed 10 points math 3!!!
ANSWER
A.
[tex] {f}^{ - 1} (x) = 4x - 3[/tex]
EXPLANATION
Given
[tex]f(x) = \frac{x + 3}{4} [/tex]
Let
[tex]y= \frac{x + 3}{4} [/tex]
Interchange x and y
[tex]x= \frac{y + 3}{4} [/tex]
Solve for y,
[tex]4x = y + 3[/tex]
y=4x-3
This implies that,
[tex] {f}^{ - 1} (x) = 4x - 3[/tex]
What are the solutions of the following system?
X+y = 25
| 2x+y= -5
(0,-5) and (-5,5)
(0,-5) and (5, -15)
(0, -5) and (-4, 3)
(0, -5) and (4, -13)
Final answer:
The solutions of the given system can be found by solving the equations simultaneously using the method of substitution. The solution is (x, y) = (-30, 55).
Explanation:
The solutions of the given system of equations can be found by solving it simultaneously. We have the following equations:
X+y = 25
| 2x+y= -5
To solve this system, we can use the method of substitution or elimination. Let's use the method of substitution:
From equation 1, we can express y in terms of x as: y = 25 - xSubstitute this value of y into equation 2: 2x + (25 - x) = -5Simplify the equation: x + 25 = -5Solve for x: x = -30Substitute this value of x back into equation 1 to find y: y = 25 - (-30) = 55Therefore, the solution to the system is (x, y) = (-30, 55).
Sam solved the proportion
3 = 5, but she has some mistakes in her solution.
Read her steps carefully, and then answer the questions.
Step 1: (x + 5)1 = 4(x + 2)
Step 2: x + 5 = 4x + 8
Step 3: 5 = 3x + 8
Step 4:
3= 3x
Step 5: -1=1
Mill
Part A: In which step did Sam make her first mistake?
Part B: What is Sam's first mistake?
Select one answer for Part A, and select one answer for Part B.
Answer:
A. Step One
B. She multiplied straight across in the proportion instead of diagonally
Step-by-step explanation:
Answer:
A. Step One
B. She multiplied straight across in the proportion instead of diagonally
solve the equation 6+1/5q=10
Answer:
q = 20
Step-by-step explanation:
1/5q = 4
q = 20
w+x=z make x the subject of the formula
Answer:
x = z - w
Step-by-step explanation:
Given
w + x = z ( isolate x by subtracting w from both sides )
x = z - w
Answer:
x = z - w
Step-by-step explanation:
Take w to the other side and subtract with z to make x the subject
What should be done to x^2 + 15x in order to create a perfect square?
[tex]\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2 \\\\[-0.35em] ~\dotfill[/tex]
[tex]\bf x^2+15x+\boxed{?}^2\implies \stackrel{\textit{we know the middle term is}}{2\sqrt{x^2}\cdot \sqrt{\boxed{?}^2}\implies 2x\boxed{?}}\qquad then\qquad 2x\boxed{?}=15x \\\\\\ \boxed{?}=\cfrac{15x}{2x}\implies \boxed{?}=\cfrac{15}{2}\qquad \impliedby \textit{we should add that much \underline{squared}} \\\\[-0.35em] ~\dotfill\\\\ x^2+15x+\left( \cfrac{15}{2} \right)^2\implies \left(x+ \cfrac{15}{2} \right)^2[/tex]
find each sum of difference. (6x^2+3x+1)-(2x^2-4x+5)
Subtract the like terms:
6x^2 - 2x^2 = 4x^2
3x - -4x = 3x+4x = 7x
1 - 5 = -4
Now combine them to get the final answer:
4x^2 + 7x - 4
Find the value of x if m<4 = 2x + 20 and m<8 = 3x - 5. Use that info to calculate the exact measure of each angle.
Since m<4 and m<8 both add up to 180 degrees. Combine 2x + 20 and 3x - 5 and set it equal to 180. By subtracting 15 to the other side and dividing five to the other side you get x=33. Plug 33 back into the angle measurement separate equations to find degree angle measurement. Your welcome.
39 POINTS!! ALGEBRA. PLEASE HELP, I AM FAILING AND THIS IS DUE IN AN HOUR.
Answer:
Question 10: [tex]f(x)=1/2x-1[/tex] Question 13: [tex]f(-2)=-1[/tex] Question 11: [tex]f(8)=60[/tex]
Step-by-step explanation:
For Question 10:
The functionis in the form of [tex]f(x)[/tex]. We know the slope is [tex]\frac{1}{2}[/tex] (rise 1 run 2)and the y intercept is -1 (where the line goes through the y axis). We can then put the function is slope intercept form ([tex]y=mx+b[/tex]) and we would have [tex]f(x)=1/2x-1[/tex].
For Question 13:
To evaluate the function[tex]f(x)=\frac{3}{2} x-4[/tex] for [tex]f(-2)[/tex] we need to plug -2 into the function as x. [tex]f(-2)=\frac{3}{-2} (-2)-4[/tex]. [tex]\frac{3}{-2}[/tex] times -2 would equal 3 because the negatives cancle out. 3-4 equals -1 so the solution is [tex]f(-2)=-1[/tex].
For question 11:
Same as question 13. plug 8 into x in [tex]f(x)=x^2-4[/tex]. This would be [tex]f(8)=(8)^2-4[/tex]. 8 squared is 64 and 64-4 is 60. Therefore [tex]f(8)=60[/tex].
48j 5 k 2 ÷ (-3j 3 k)
where are the signs between the 5 and 48j, and k and 2? is at multiplication? cause you use parentheses only for that.
If it is multiplication... then 3j * 3k = 9jk
48j * 5 = 240j * k =240jk * 2 = 480jk / 9jk = 53.3333333333jk
The measure of an angle is 78° less than the measure of its complement. What is the measure of the angle?
84°
51°
6°
12°
The measure of the angle is 6°
A complementary angle consists of two angles who's sum is 90 degrees. Since there are two we know this for sure:
1st angle: x (unknown value)
2nd angle: x-78 (78 less then its complement)
total: 90
If we put the equation together we get: x+x-78= 90
x+x-78+78=90+78
2x=168
2x/2=168/2
x=84
Now we know that x = 84, know we gonna find the 2nd angle:
1st: x=84
2nd: 84-78 = 6
total: 84+6=90
The price of a computer was decreased by 30% to £147. What was the price before the decrease?
Answer:
£210
Step-by-step explanation:
A decrease of 30% represents 70% of the original cost.
100% represents the original cost
Divide the price by 70 to find 1% then multiply by 100 for original cost
original cost = [tex]\frac{147}{70}[/tex] × 100 = 2.1 × 100 = £210
Answer:
210
Step-by-step explanation:
let original price =x
x×70÷100=147
x=147×100÷70=210
which figure shows two congruent triangles
Hello there!
The answer is the first option.
Remember that congruent = same size and same shape, and this is the only option that has both of those things. In the second and forth options, the sizes are different making those options not correct. In the 3rd option, the shape is slightly different since one triangle is not as stretched out as the other.
I hope this was helpful and have a great day!
Since the two sides and one angle in figure 1 are the same as a result they are congruent.
What is the congruent triangle?Congruent triangles are those that are exactly the same size and shape. Congruent is represented by the symbol ≅ When the three sides and three angles of one triangle match the dimensions of the three sides and three angles of another triangle, they are said to be congruent.
While the similarity law for triangles is defined as the law to prove that two triangles have the same shape, it is not compulsory to have the same size. The ratio of the corresponding sides is in the same proportions and the corresponding angles are congruent.
Thus, the two sides and one angle in figure 1 are the same as a result they are congruent.
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The polynomial 24x3 − 54x2 + 44x − 99 is factored by grouping. 24x3 − 54x2 + 44x − 99 24x3 + 44x − 54x2 − 99 4x(____) − 9(____) What is the common factor that is missing from both sets of parentheses?
Answer: [tex]6x^2+11[/tex]
Step-by-step explanation:
Given the polynomial of degree 3:
[tex]24x^3 - 54x^2 + 44x -99[/tex]
You can observe make two groups or two terms each:
[tex](24x^3 + 44x) - (54x^2 + 99)[/tex]
The Greatest Common Factor (GCF), is the highest number that divides into two or more numbers without leaving remainder.
You can observe that the GCF of both set are factored out ([tex]4x[/tex] and [tex]9[/tex]), then, you can find the common factor that is missing from both sets of parentheses with this procedure:
[tex](\frac{24x^3}{4x}+\frac{44x}{4x})-(\frac{54x^2}{9}+\frac{99}{9})=(6x^2+11)-(6x^2+11)[/tex]
You can observe that the common factor that is missing from both sets of parentheses is:
[tex]6x^2+11[/tex]
Which of the following expressions is not equivalent to -4.5x-8
A. (8)(-4.5)
B. 8x4.5
C. -8x -4.5
D. (4.5)(8)
ANSWER
A. (8)(-4.5)
EXPLANATION
The given expression is
[tex] - 4.5 \times - 8[/tex]
We evaluate this to obtain:
[tex]- 4.5 \times - 8 = 36[/tex]
For option A
[tex](8) \times - 4.5 = - 36[/tex]
For option B
[tex]8 \times 4.5 = 36[/tex]
For option C,
[tex] - 8 \times - 4.5 = 36[/tex]
For option D
[tex](4.5)(8) = 36[/tex]
The odd one is option A.
The correct answer is A.
A because it would become negative while the rest become positive.
Please help!! WILL MARKK!
Answer:
c = 25
Step-by-step explanation:
Since the triangle is right use Pythagoras' identity to find c
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
c² = 7² + 24² = 49 + 576 = 625
Take the square root of both sides
c = [tex]\sqrt{625}[/tex] = 25
Answer:
C=25
Step-by-step explanation:
Square both 24 and 7,Then add them together.
576+49=C
625=C
Square root 625
C=25
Given that p is an integer, q = -12 and the quotient of
p
q
is -3, find p.
A) -36
B) -4
C) 4
D) 36
Answer: D
Step-by-step explanation:
plz help to do it of math
A leap year consists of 366 days.
52 weeks + 2 days.
These 2 days can be: (mon,tue),(tue,wed),(wed,thu),(thu,fri),(fri,sat)(sat,sun)(sun,mon)
Thus, the total number of cases = 7.
The number of cases in which we get Friday = 2(Thu, Fri)(Fri, Sat).
Therefore the required probability = 2/7.
Find the local and global extrema for the graph of ƒ(x) = x3 – 6x2.
Answer:
Global extrema: none. Local extrema: (0, 0) and (4, -32)
Step-by-step explanation:
ƒ(x) = x3 – 6x2 should be written as ƒ(x) = x^3 – 6x^2. Use " ^ " to denote exponentiation, please.
One way to answer this problem would be to make a careful graph of ƒ(x) = x^3 – 6x^2. Notice that this graph begins in Quadrant III and ends in Quadrant I; this is one outcome of its being an ODD function. The graph will increase, reach a peak (a local max), decrease, reach a valley (a local min) and then grow from then on.
Another way is to use calculus. You don't say what course you're in, so I can't be sure that calculus would make sense to you.
Find the first derivative of ƒ(x) = x^3 – 6x^2. It is f '(x) = 3x^2 - 12x. Set this derivative = to 0 and find the roots. Hint: find the roots of 3x^2(x - 4). They are x = 0 and x = 4. At x = , y = f(0) = 0. Thus, the local max is
(0, 0). At x = +4, y = f(4) = 64 - 6(16) = -32. Thus, the local min is at (4, -32 ).
This graph rises without bound as x goes to ∞, and decreases without bound as x goes to -∞. Thus, there is neither a global max nor a global min.
Name the polynomial based on its degree and number of terms
X to the 2nd power +2-4x
Answer:
Second degree trinomial.
Step-by-step explanation:
Please help and show work
Answer:
Coordinates of A': will NOT be the same
Coordinates of C': will NOT be the same
Perimeter of ABC: will be the same
Area of A'B'C': will be the same
Measure of ∠B: will be the same
Slope of A'C': will be the same
Step-by-step explanation:
We have a triangle ABC that will be translated (moved) 2 units down, 3 units to the right.
Since the triangle is moved, then the coordinates of every summit (A, B and C) will be affected. So,
Coordinates of A': will NOT be the same
Coordinates of C': will NOT be the same
However, since the triangle is only moved, not transformed in any way, not scaled up/down for example the following will remain the same:
Perimeter of ABC: will be the same
Area of A'B'C': will be the same
Measure of ∠B: will be the same
Since the triangle is only translated, not rotated or reflected the following will remain the same:
Slope of A'C': will be the same
Given f(x) = 6x + 9 and g(x) = X^4, choose
the expression for (fºg)(x).
Answer:
(fºg)(x) = [tex]6x^{4}+9[/tex]
Step-by-step explanation:
We have been given the following two functions;
f(x) = 6x + 9
g(x) = X^4,
We are then required to determine the expression for (fºg)(x). (fºg)(x) denotes a composite function f[g(x)] which is obtained by
substitute g(x) in place of x in f(x)
(fºg)(x) = 6[g(x)] + 9
(fºg)(x) = 6X^4 + 9
What value of c makes the equation true? Assume x>0 and y>0 3√x^3/cy^4=x/4y(3√y) c = 12 c = 16 c = 81 c = 64
The value of c=12 will makes the equation true. for the given expression.
what is the value?Here in the question we have expression:
[tex]\dfrac{3\sqrt{x^3}}{cy^4}}=\dfrac{x}{4y^3\sqrt{y}}[/tex]
By solving the above equation we will get:
[tex]12\sqrt{x}=c\sqrt{y}[/tex]
So value of c=12 will makes the equation true. for the given expression.
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The correct value of [tex]\( c \)[/tex] that makes the equation true is [tex]\( c = 64 \)[/tex].
To find the value of [tex]\( c \)[/tex], we start by simplifying the given equation:
[tex]\[ 3\sqrt{\frac{x^3}{cy^4}} = \frac{x}{4y}(3\sqrt{y}) \][/tex]
First, we simplify the left side of the equation by applying the cube root to both the numerator and the denominator:
[tex]\[ \frac{3\sqrt{x^3}}{3\sqrt{cy^4}} = \frac{x}{4y}(3\sqrt{y}) \][/tex]
The cube root of [tex]\( x^3 \)[/tex] is [tex]\( x \)[/tex] , and the cube root of [tex]\( y^4 \)[/tex] is [tex]\( y \)[/tex] times the cube root of [tex]\( y \)[/tex], which is [tex]\( y \cdot y^{1/3} \)[/tex]. Simplifying further, we get:
[tex]\[ \frac{x}{3\sqrt{c} \cdot y} = \frac{x}{4y}(3\sqrt{y}) \][/tex]
Now, we simplify the right side of the equation:
[tex]\[ \frac{x}{3\sqrt{c} \cdot y} = \frac{x \cdot 3\sqrt{y}}{4y} \][/tex]
Since [tex]\( x \)[/tex] and [tex]\( y \)[/tex] are positive, we can multiply both sides by [tex]\( 4y \)[/tex] to eliminate the denominators:
[tex]\[ \frac{4yx}{3\sqrt{c} \cdot y} = x \cdot 3\sqrt{y} \][/tex]
Simplifying, we get:
[tex]\[ \frac{4x}{3\sqrt{c}} = 3x\sqrt{y} \][/tex]
Now, we can divide both sides by [tex]\( x \)[/tex] since [tex]\( x > 0 \)[/tex]:
[tex]\[ \frac{4}{3\sqrt{c}} = 3\sqrt{y} \][/tex]
Next, we square both sides to eliminate the square root:
[tex]\[ \left(\frac{4}{3\sqrt{c}}\right)^2 = (3\sqrt{y})^2 \][/tex]
[tex]\[ \frac{16}{9c} = 9y \][/tex]
Since [tex]\( y > 0 \)[/tex], we can multiply both sides by [tex]\( 9c \)[/tex] to get rid of the denominator:
[tex]\[ 16 = 81cy \][/tex]
Now, we divide both sides by [tex]\( y \)[/tex]:
[tex]\[ \frac{16}{y} = 81c \][/tex]
Finally, we multiply both sides by [tex]\( y \)[/tex] to solve for [tex]\( c \)[/tex]:
[tex]\[ 16 = 81c \][/tex]
[tex]\[ c = \frac{16}{81} \][/tex]
[tex]\[ c = \left(\frac{2^4}{3^4}\right) \][/tex]
[tex]\[ c = \left(\frac{2}{3}\right)^4 \][/tex]
[tex]\[ c = \left(\frac{3}{2}\right)^{-4} \][/tex]
[tex]\[ c = 64 \][/tex]
Therefore, the value of [tex]\( c \)[/tex] that makes the equation true is [tex]\( c = 64 \)[/tex].
is y=4/5 proportional
Just by itself? No it is not.
How can you justify that the diagonals of a rhombus bisect opposite interior angles?
Answer:
the opposite sides are of equal length; - the diagonals bisect each other; - the opposite angles are congruent; - the sum of any two consecutive angles is equal to 180 . Rhombis (plural of rhombus) have additional properties. Theorem 1. In a rhombus, the diagonals are the angle bisectors.
Step-by-step explanation:
The diagonals of a rhombus bisect opposite interior angles because they create congruent triangles that have equal corresponding angles.
Explanation:The question addresses a geometry concept about the properties of a rhombus. To justify that the diagonals of a rhombus bisect opposite interior angles, we can consider the definition of a rhombus as a special type of parallelogram where all four sides are of equal length. Additionally, we know that in a parallelogram, opposite sides are parallel. By drawing the diagonals of a rhombus, we create congruent triangles because of the properties of parallelograms and the fact that all sides of a rhombus are equal. Each diagonal will bisect the angle from which it is drawn because in these congruent triangles, the corresponding angles are equal. This means that the diagonals bisect each other and they bisect the opposite interior angles into equal parts.