Which expression is equal to 2√ -32 ? 8i√2 −8√2 8√2i −8i√2





the first one is the answer

Answers

Answer 1
The square root of (a * b) is equal to (the square root of a) * (the square root of b) -32 equals 32 * -1; therefore, the square root of -32 equals the square root of 32 times the square root of -1. 32 equals 16 * 2; the square root of 32 equals ? 16 * ?2 equals 4* ?2 The square root of -1 is i. Therefore (2? -32) equals 2 * 4 * i * ?2 = 8i?2
Answer 2

Final answer:

The expression 2√ -32 is equal to 8i√2

Explanation:

To find an expression equal to 2√ -32, we need to recall that the square root of a negative number involves an imaginary unit i. The square root of -1 is defined as i. Thus, we can rewrite the expression as:

2√ -32 = 2√(-1 × 32) = 2√(-1)√(32) = 2i√(16 × 2) = 2i × 4√2 = 8i√2.

which is found by using the property that the square root of -1 is the imaginary unit i.

This demonstrates that the correct expression equivalent to the original one is 8i√2.


Related Questions

A customer ordered fourteen zingers. zingers are placed in packages of​ four, three, or one. in how many different ways can this order be​ filled?

Answers

Answer:

The number of different ways this order can be filled is:

                              13 ways.

Step-by-step explanation:

A customer ordered fourteen zingers.

zingers are placed in packages of​ four, three, or one.

Case-1

If the number of packages of four are: 3

Then 4×3=12 zingers.

a)

So, there will be zero packet of 3.

and 2 packs of 1.

Since, 12+2×1=14

Case-2

If the number of packages of four are: 2

i.e. 4×2= 8 zingers.

a)

If number of packages of 3 are: 2

i.e. 3×2=6

then number of package of 1 have to be 0.

b)

If number of packages of 3 are: 1

i.e. 3×1=3 zingers

Number of packages of 1 zinger will be: 3

i.e. 8+3+3=14

c)

If number of packages of 3 are: 0

Then number of packets of 1 will be:  6

Case-3

If the number of packages of four are: 1

a)

If number of packages of 3 are: 3

i.e. 3×3=9 zingers.

Hence, number of packets of 1 have to be: 1

b)

If number of packages of 3 are: 2

i.e. 3×2=6 zingers

Then number of packets of 1 have to be: 4

c)

If number of packages of 3 are: 1

i.e. 3×1=3 zingers

Then number of packets of 1 have to be: 7

d)

If number of packages of 3 are: 0

i.e. 3×0=0 zingers

Then number of packets of 1 have to be: 10

Case-4

If the number of packages of four are: 0

a)

If number of packages of 3 are: 4

i.e. 3×4=12 zingers

Then number of packets of 1 have to be: 2

b)

If number of packages of 3 are: 3

i.e. 3×3=9 zingers

Then number of packets of 1 have to be: 5

c)

If number of packages of 3 are: 2

i.e. 3×2=6 zingers

Then number of packets of 1 have to be: 8

d)

If number of packages of 3 are: 1

i.e. 3×1=3 zingers

Then number of packets of 1 have to be: 11

e)

If number of packages of 3 are: 0

i.e. 3×0=0 zingers

Then number of packets of 1 have to be: 14

There are total 13 ways of doing so.

( 1 from case-1

3 from case-2

4 from case-3

and 5 from case-4

i.e.  1+3+4+5=13 ways )

Final answer:

The order can be filled in 5 different ways by using packages of 4, 3, or 1 zingers.

Explanation:

To find the number of different ways the order can be filled, we can use the concept of permutations and combinations. Since zingers can be placed in packages of 4, 3, or 1, we need to find all the possible combinations of these packages that add up to 14.

For packages of 4, we can have 1 package of 4 and 2 packages of 5, for a total of 2 combinations.For packages of 3, we can have 1 package of 3 and 3 packages of 5, for a total of 2 combinations.For packages of 1, we can have 7 packages of 1, for a total of 1 combination.

Therefore, the total number of different ways the order can be filled is 2 + 2 + 1 = 5.

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A soccer player who is 27 feet from a goal attempted to kick the ball in into the goal. the flight of the ball is modeled by a parabola. the ball reached a maximum height of 10 feet when it was 15 feet from the soccer player. the goal has a height of 8 feet. will the soccer ball land in the goal?

Answers

Answer:

The ball will land inside the goal.

Step-by-step explanation:

Given : The flight of the ball is modeled by a parabola.

To find : Will the soccer ball land in the goal?

Solution :

Let the equation of the parabola be,

[tex]y=a(x-h)^2+k[/tex]

Where, (h,k) are the vertex of the parabola,

According to question,

A soccer player who is 27 feet from a goal.

Let A be the point where player stand i.e, (27,0)

The height of the goal is 8 feet.

Let B be the point of height of goal i.e, (0,8)

The ball reached a maximum height of 10 feet when it was 15 feet from the soccer player.

The distance from goal to the distance 15 feet away from the player is

27-15=12 feet

Let C be the point with maximum height i.e, (12,10)

C is the vertex of the parabola and A is the point on the parabola.

Then, The equation of parabola is

[tex]y=a(x-12)^2+10[/tex]

Point A satisfy the equation,

[tex]0=a(27-12)^2+10[/tex]

[tex]0=a(15)^2+10[/tex]

[tex]a=-\frac{10}{225}[/tex]

Substitute back in equation,

[tex]y=-\frac{10}{225}(x-12)^2+10[/tex]

Now, we find the y-intercept of the equation i.e, x=0,

[tex]y=-\frac{10}{225}(0-12)^2+10[/tex]

[tex]y=-\frac{10}{225}(144)+10[/tex]

[tex]y=3.6[/tex]

If the y-intercept is greater than 8 then the ball will land outside the goal.

If the y-intercept is less than 8 then the ball will land inside the goal.

As 3.6<8

Therefore, The ball will land inside the goal.

Refer the attached figure below.

Final answer:

The soccer ball will not land in the goal due to its maximum height being above the height of the goal.

Explanation:

To determine if the soccer ball will land in the goal, we need to analyze its flight path. From the given information, we know that the ball reached a maximum height of 10 feet when it was 15 feet from the soccer player. This indicates that the ball's flight path is modeled by a downward-opening parabola.

Since the soccer player is 27 feet from the goal, we can consider the ball's horizontal distance from the player to the goal as the x-coordinate, and its height above the ground as the y-coordinate.

Based on the given information, the soccer ball will not land in the goal. The ball's maximum height is 10 feet, but the goal has a height of 8 feet. This means that at any point along its flight path, the ball's height will be above the height of the goal.

The real numbers between 1 and 4 , inclusive

Answers

The real numbers would be every number between 1 and 4, excluding those irrational numbers, such as the square root of 2. 

The real numbers between 1 and 4, inclusive, are all the numbers that lie on the interval [1, 4]. In interval notation, this can be represented as [1, 4].

In set-builder notation, the set of real numbers between 1 and 4, inclusive, can be written as:

{x | 1 ≤ x ≤ 4}

This set includes all real numbers greater than or equal to 1 and less than or equal to 4. It includes the numbers 1 and 4 as well. Some examples of numbers in this set are 1, 2, 3, 4, 1.5, 2.718 (approximation of Euler's number), etc.

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the slope of the line passing through the points (-6,3)and(-6,39) is

Answers

Hmm, the slope is undefined. But like what exactly are you looking for as an answer?

The slope of the line passing through points is undefined.

What is slope of a line?

The slope or gradient of a line is a number that describes both the direction X and Y and the steepness of the line. It is the ratio of the vertical change to the horizontal change between any two distinct points on a line.

For the given situation,

The line passing through points (x1, y1) is (-6, 3) and (x2,y2) is (-6, 39)

The formula of slope of line is

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

⇒ [tex]m=\frac{39-3}{-6-(-6)}[/tex]

⇒ [tex]m=\frac{39-3}{-6+6}[/tex]

⇒ [tex]m=\frac{39-3}{0}[/tex]

⇒ [tex]m=\infty[/tex]

Since x1 = x2, there is no horizontal change. The line passes as a straight line.

Hence we can conclude that the slope of the line passing through points is undefined.

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A recipe calls for 12 ounces of flour, but your scale shows only pounds. The recipe requires __________ pounds of flour. Enter your answer as the decimal number that correctly fills in the blank in the previous sentence. If necessary, round to the nearest hundredth, like this: 42.56 Hint: 1 pound=16 ounces 67 pts

Answers

.75 because 12 ounces of flour is 3/4 of a pound there are 16 ounces in a pound which makes it so the answer to your question is <(.75)>

Julie started solving the equation 3x=4+2(3−x). which is a correct next step?

Answers

Hi there! You'll need PEMDAS for this equation.

First, use the distributive property of multiplication.

2(3 - x) = 6 - 2x

Now, add like terms.

4 + 6 - 2x = 10 - 2x

Okay, now put all like terms on each side of the equation.

3x + 2x = 10

5x = 10

Now divide!

5x/5 = 10/5

x = 2

There you go :)

Answer:

Distribute 2 inside the parenthesis

Step-by-step explanation:

Julie started solving the equation

3x=4+2(3−x)

To simplify any expression we use order of opeation PEMDAS

Always start simplifying the parenthesis

To remove parenthesis we apply distributive property

Distribute 2 inside th4e parenthesis

3x=4+2(3−x)

3x=4+6-2x

So next step is distributing 2 inside the parenthesis

3x=4+6-2x

Harriet earns the same amount of money each day. Her gross pay at the end of 7 work days is 35h + 56 dollars. Which expression represents her gross pay each day?

Answers

Her gross pay would be 5h+8

Answer:

Daily Payment = 5h+8

Step-by-step explanation:

Here we are given that in seven days the amount Harriet earned is given as

35h+56

It is also given that the amount earned each day is same.

We have to determine the amount earned each day. Total number of days is 7 . Hence in order to find the daily earning we divide the total earning by 7

Daily earning =

[tex]E=\frac{35h+56}{7}\\E=\frac{7(5h+8)}{7}\\E=5h+8[/tex]

Hence answer is 5h+8

Find the common ratio for the following sequence

27,9,3,1

Answers

With each step the value gets divided by 3

so the common ratio r=1/3

Answer:

The common ratio is  [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

Given sequence,

27, 9, 3, 1

Since,

[tex]\frac{9}{27}=\frac{3}{9}=\frac{1}{3}[/tex]

Hence, in the given sequence the ratio of a term to its previous term is [tex]\frac{1}{3}[/tex]

Therefore, we can say that,

The common ratio of the given sequence is [tex]\frac{1}{3}[/tex]

What what are the rules for addition and subtraction with numbers in scientific notation?

Answers

Addition and Subtraction in Scientific Notation. A number written in scientific notation is written as the product of a number between 1 and 10 and a number that is a power of 10. That is, it is written as a quantity whose coefficient is between 1 and 10 and whose base is 10.

A fabric store sells two types of ribbon. One customer buys 3 rolls of the lace ribbon and 2 rolls of the satin ribbon and has a total of 120 yards of ribbon. Another customer buys 2 rolls of the lace ribbon and 4 rolls of the satin ribbon and has a total of 160 yards of ribbon. How many yards are on one roll of lace ribbon and one roll of satin ribbon?

Answers

Let L be the number of yards on a roll of lace ribbon. Let S be the number of yards on a roll of satin ribbon. We can set up two equations. equation 1: 3L + 2S = 120 yards equation 2: 2L + 4S = 160 yards We can multiply (equation 1) by 2 and subtract (equation 2). equation 1: 6L + 4S = 240 yards equation 2: 2L + 4S = 160 yards 4L = 80 yards L = 20 yards equation 1: 3L + 2S = 120 yards 3(20 yards) + 2S = 120 yards 2S = 60 yards S = 30 yards There are 20 yards on a roll of lace ribbon. There are 30 yards on a roll of satin ribbon.

Answer:

20 and 30. that's your answer.

Step-by-step explanation:

x + y = 0 x - y = 8 What is the solution of the system shown?

A; (-8, 12)
B; (8, -12)
C; (8, 12)

Answers

it is the second one
The Answer is B.....

Two bags had 100 kilograms of sugar each. after taking out 3 times as much sugar from bag one than bag two, bag one had half as much sugar left as bag two. how much sugar is left in each bag?

Answers

According to the given statement, we can get the equation:

50 - 3x = 1/2 (50-x)

where x = amount removed from bag two, 3x removed from bag one

 

Then we multiply both sides by 2 (to eliminate the ½)

 

100-6x= 50-x

Add 6x to both sides

100= 50-5x

Then subtract 50 from both sides

50=5x

Lastly, divide by 5

10=x

 

Therefore 10 kg of sugar was removed from bag 2

 

further, 3x= 30, so 30 kg of sugar was removed from bag 1.

 

50-30=20 kg remaining in bag 1.

50-10=40 kg remaining in bag 2.

Answer:

40 kg in the first bag, 80 in the second

Step-by-step explanation:

Sari has a bag containing 6 half dollars. What is the mass of half dollars in Sari's bag when half dollars weighs 11.34 grams?

Answers

mass of one half dollars = 11.34g
therefore mass of six half dollars = 6*11.34g
                                                       =68.04g
 Ans : mass of 6 half dollars = 68.04g

Jacob is ordering custom T-shirts for his soccer team. Long-sleeved shirts cost $15 each and short-sleeved shirts cost $10 each. Jacob can spend at most $250 and he wants to order at least 20 shirts.

Let x represent the number of long-sleeved shirts. Let y represent the number of short-sleeved shirts.

Which inequalities are among the constraints for this situation?

Select each correct answer.

⋅ 15x + 10y ≥ 20

⋅ x + y ≤ 250

⋅ x + y ≥ 20

⋅ 15x + 10y ≥ 250

⋅ 15x + 10y ≤ 250

⋅ x + y ≤ 20


Answers

x + y ≥ 20 ( total number of shirts at least 20)

15x + 10y ≤ 250 ( total amount spent no more than $250)

These are the answers.

3. x + y ≥ 20 

5. 15x + 10y ≤ 250 

Hope this helps and have a wonderful day!

Which statement is true with respect to the Euclidean approach to geometry?

Answers

I think point, line and plane are defined terms... this statement is true with respect to the Euclidean geometry.

Answer:

I would think the answer is "axioms are used to prove theorems"

Step-by-step explanation:



An equation that is true for all real numbers for which both sides are defined is called​ a(n)

Answers

It called identity. Identity equations are conditions that are genuine regardless of what esteem is connected to for the variable. On the off chance that you rearrange a personality condition. 
An identity is a balance that remains constant paying little respect to the qualities decided for its variables.They are utilized as a part of streamlining or reworking polynomial math articulations. By definition, the two sides of a character are tradable, so we can supplant one with the other whenever.
Final answer:

An equation that is true for all real numbers for which the operations are defined is called an identity. It is always true no matter the values of its variables. An example is sin²(x) + cos²(x) = 1

Explanation:

An equation that is true for all real numbers for which both sides are defined is called an identity. An identity equation is always true, no matter what values are substituted for its variables. For example, the equation sin²(x) + cos²(x) = 1 is an identity because it is valid for all real numbers x.

Identity equations commonly appear in branches of math such as algebra and trigonometry.

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A has $32 more than B, and B has five times as much money as C. If C has d dollars, how much does A have? Answer:

Answers

A = B+32

B = 5C

A = 5C+32

C has d dollars so replace d for c

A = 5d+32

Which number(s) below belong to the solution set of the inequality?
Check all that apply. x/8<10
A.80
B.96
C.64
D.40
E.32
F.88

Answers

Multiply both sides by 8 (to undo the division of 8)

x/8 < 10
8(x/8) < 8*10
x < 80

So any number less than 80 will make the original inequality true. This applies to choices: C, D, E which are the final answers. These values are all less than 80. 

---------------------------------

Alternatively we can plug in each value into the inequality to check them

Choice A
x/8 < 10
80/8 < 10
10 < 10
false; choice A is eliminated
-------
Choice B
x/8 < 10
96/8 < 10
12 < 10
false; choice B is eliminated
-------
Choice C
x/8 < 10
64/8 < 10
8 < 10
true; choice C is one of the answers
-------
Choice D
x/8 < 10
40/8 < 10
5 < 10
true; D is another one of the answers
-------
Choice E
x/8 < 10
32/8 < 10
4 < 10
true; choice E is another solution
-------
Choice F
x/8 < 10
88/8 < 10
11 < 10
false; choice F is eliminated

---------------------------------

Whichever method you end up using, the final answers are C, D, E

99 points!!!
Factor each expression completely.
1. x^2-5x-24
2. 13x^2-52
3. Find the equation of a line through (-6, 3) and parallel to 3x-9y=14
4. Solve (5x+4)(3x-7)=0; {rational numbers}

Answers

try to factor the greatest common factor out of each then if you have
1x²+bx+c, then find what 2 numbers (let's call them r and w) mutliply to get c and add to get b
it will factor to (x+w)(x+r)

and differnce of 2 perfect squares: a²-b²=(a-b)(a+b)

and paralell lines have same slope

and if xy=0 then assume x and/or y=0




so

1.
what 2 numbers multiply to get -24 and add to get -5
-8 and 3
(x-8)(x+3)


2.
factor out 13 from each
13(x²-4)
differnce of 2 perfect squares
13(x²-2²)=13(x-2)(x+2)


3.
a nice hack is for ax+by=c, a paralell line will be ax+by=z where the values of a and b are the same for both equations

so 3x-9y=14
a paralell line will be
3x-9y=c
find c
subsitute the point (-6,3)
x=-6 and y=3
subsitute
3(-6)-9(3)=c
-18-27=c
-45=c
the equation is 3x-9y=-45


4.
for so since those  2 things multiply to get 0, set them both equal to 0 and solve

5x+4=0
minus 4 both sides
5x=-4
divide by 5 both sides
x=-4/5

3x-7=0
add 7 both sides
3x=7
divide by 3 both sides
x=7/3

solutions are x=-4/5 and 7/3







1. (x-8)(x+3)
2. 13(x-2)(x+2)
3. 3x-9y=-45 (or simplified would be x-3y=-15)
4. x=-4/5 and 7/3
#1

[tex] \sf \: {x}^{2} - 5x - 24 \\ \sf \: {x}^{2} + 3x - 8x - 24 \\ \sf \: x \times (x + 3) - 8(x + 3) \\ \sf \: (x - 8) \times (x + 3)[/tex]

Therefore the factors are: (x-8) & (x+3)

[tex]\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}[/tex]

#2

[tex] \tt \: {13x}^{2} - 52 \\ \tt13( {x}^{2} - 4) \\ \tt13(x - 2) \times (x + 2)[/tex]

Therefore the factors are: 13(x-2) & (x+2)

[tex]\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}[/tex]

#3

To find this we will use the standard form of equation i.e. ax+by+c=0We will substitute the given values of x and y and solve the equation for c

x = -6y = 3

Substitute the values into 3x-9y=14

[tex] \bf 3( - 6) - 9(3) = c[/tex]

[tex] \bf \: - 3 \times 6 - 9 \times 3 = c[/tex]

[tex] \bf \: 3( - 6 - 9) = c[/tex]

[tex] \bf \: 3( - 15) = c[/tex]

[tex] \bf \: - 45 = c[/tex]

[tex] \boxed{ \bf \: c = - 45}[/tex]

So, the equation parallel to 3x-9y=14 is: 3x-9y=-45

[tex]\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}[/tex]

[tex] \rm \: (5x + 4)(3x - 7) = 0[/tex]

[tex] \rm \: 5x + 4 = 0 \\ \rm \: 3x - 7 = 0[/tex]

[tex] \rm \: 5x = - 4 \\ \rm 3x = 7[/tex]

[tex] \rm \: x_{1} = - \frac{4}{5} , x_{2} = \frac{7}{3} [/tex]

The values of x1 and x2 are: -4/5 & 7/3

Write log3 6 as a logarithm of base 2

a. log base 2 of 3 over log base 2 of 6

b. log base 2 of 6 over log base 2 of 3

c. log base 3 of 2 over log base 6 of 2

d. log base 6 of 2 over log base 3 of 2

Answers

you should end with B as the correct answer  but be careful not to mix it up with D 

Final answer:

The expression log3 6 can be converted to a logarithm of base 2 using the change of base formula, which results in log2 6 / log2 3. So the correct option is b.

Explanation:

The student asked how to express log3 6 as a logarithm with a base of 2. To perform this conversion, we can use the change of base formula, which states that logab = logcb / logca for any positive numbers a, b, and c, where a and c are not equal to 1. In this formula, 'c' can be any base, but in our case, we will use base 2 since that's what the question requires.

So, by applying the change of base formula, we can write:

log₃6 = log₂6 / log₂3

Therefore, the correct option that represents log3 6 as a logarithm of base 2 is:

(b) log₂6 / log₂3

How do i solve this for x

Answers

c) The 2 triangles are similar , then we can write:

5x/45 = 20/36 . Cross multiplication:

5x*36 = 45*20
180x = 900   and x = 900/180 , x = 5 (and 5x = 25)

d) Remember the proportionality theorem (or Thales')
You can write the following proportion:
GH/HJ = KL/LM
8/6 = 10/x . Cross multiplication:

8x = 60 and x = 60/8 , x = 7.5

Attempting to use the regression equation to make predictions beyond the range of the data is called​ _______.

Answers

Extrapolating. Extrapolating is making inferences that beyond the data range. In contrast to this, interpolating is using the data set to make estimates as to what would happen in the data range.

Can anyone help me please? I would really appreciate it! Thank you :D

Answers

Hello,
Here is the proof in the picture jointed.


Solve the quadratic equation by completing the square. x^2+6x-6=0 First, choose the appropriate form and fill in the blanks with the correct numbers. Then, solve the equation. If there is more than one solution, separate them with commas.

Answers

[tex] x^{2} +6x - 6=0 [/tex]
[tex] x^{2} +6x =6 [/tex]  ⁽[tex] \frac{6}{2}^{2} [/tex]⁾
[tex] x^{2}+6x+9 =15[/tex] [tex] (3)^{2}
[tex] \sqrt{(x-3)^{2} } = \sqrt{15} [/tex]
[tex]x-3 = \frac{+}{-} 3.872983346 [/tex]
[tex]x= 3 \frac{+}{-} 3.872983346 [/tex]
[tex]x= 6.872983346[/tex]  or [tex]x= -.872983346[/tex]

One side of a triangle is 4 inches longer than the side that is the base of the triangle. the third side is 6 inches longer than the base. of the perimeter is 34 inches​, find the length of each side.

Answers

First make an equation

B= base

B + b+4 + b+6=34

Combine like terms

3b+10=34

Isolate the variable

3b=24

Solve for b

B=8

Now we know that b = 8 so we can add 6 and 4 to it,
We get;

8, 12, 14 as the lengths

Final answer:

The base of the triangle is 8 inches, one side is 12 inches (base + 4), and the other side is 14 inches (base + 6). Hence, the side lengths of the triangle are 8 inches, 12 inches, and 14 inches, with a total perimeter of 34 inches.

Explanation:

The question describes a triangle with sides of varying lengths relative to what is defined as the base of the triangle. To find the length of each side, we'll use algebra and the fact that the perimeter of the triangle is given as 34 inches.

Let's denote the base as b. According to the problem, one side is 4 inches longer than the base, which would be b + 4 inches. The third side is 6 inches longer than the base, which would be b + 6 inches. The perimeter of a triangle is the sum of all its sides, so we have:

b + (b + 4) + (b + 6) = 34

Combining like terms, we get:

3b + 10 = 34

Subtracting 10 from both sides gives us:

3b = 24

Dividing by 3 gives us the length of the base:

b = 8 inches

Now, we can find the lengths of the other two sides:

b + 4 inches is 12 inches and b + 6 inches is 14 inches.

So, the lengths of the sides of the triangle are 8 inches, 12 inches, and 14 inches.

It takes 1.25 seconds for light to travel from the moon to the earth how many miles away is the moon

Answers

232,500 miles i believe
The speed of light is 186,000 miles/sec. d = 186,000 * 1.25d = 232,500 The moon is 232,500 miles from the earth

Classify each number as a Natural number, Whole Number, Integer, Rational Number, or Irrational. (Write all that apply)

a)-40 b)5 c) -14/11 d)√34     e) -√16

Answers

Natural numbers are: 1, 2, 3, 4, 5, 6, 7, .... although some authors include 0.

Whole numbers are: 0, 1, 2, 3, 4, 5, 6, 7, ....

Integer numbers include negatives: ...-5, - 4, - 3, - 2 , - 1, 0, 1, 2, 3, 4, 5, ...

Rational numbers are: the ratio of two integers. They include the integers.

Irrational number are ilimited decimals without periodicity.

a) - 40: integer and rational (all integers are rational too)

b) 5: natural, whole, integer and rational.

c) -14/11: rational

d) √34: irrational. It is 5.83095189...

e) - √16: √16 = 4 => - √16 = - 4 => integer and rational


What you s 50 percent of 2.98

Answers

Answer:

1.49

Step-by-step explanation:

50% of 2.98 is 1.49

The measure of ∠BQS is 78°.
What is m∠NQS?
Enter your answer in the box.
​m∠NQS​ = ?°

Answers

∠BQS = 78
This angle is the whole thing.

∠BQN = 48

This means that ∠BQN + ∠NQS = ∠BQS.

48 + x = 78
Subtract 48 from both sides.
x = 30

∠NQS = 30.

The required measure of angle ∠NQS = 30°.


Given that,
The measure of ∠QBS is 78°. What is m∠NQS is to be determined?

What is the angle?

The angle can be defined as the one line inclined over another line.

What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements.

Here,
∠NQS + ∠BQN = ∠BQS
∠NQS + 48 = 78
∠NQS = 78 - 48
∠NQS = 30

Thus, the required a measure of angle ∠NQS = 30°.

Learn more about Angles here:
https://brainly.com/question/13954458

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A mountain climber ascends 800 feet per hour from his original position. After 6 hours, his final position is 11,600 feet above sea level. Find the climber's position.

Answers

To find the beginning position, we need to know how many feet the climber has ascended in the 6-hour time frame. At the rate of 800 feet per hour, this would total to 4,800 feet in 6 hours (800 * 6). Subtracting this amount from the final position would give the elevation at the beginning of the ascent: (11600 - 4800) = 6,800 feet above sea level to begin.
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