Which method will correctly determine whether the forces on an object are balanced or unbalanced?
Add the forces in the horizontal direction to the forces in the vertical direction.
Add the forces in the horizontal and vertical directions separately.
Subtract the forces in the horizontal direction from the forces in the vertical direction.
Subtract the forces in the vertical direction from the forces in the horizontal direction.

Answers

Answer 1
Add the forces in the horizontal direction to the forces in the vertical direction.

Related Questions

An airplane accelerates down a run-way at 3.20 m/s 2 for 32.8 s until is finally lifts off the ground. determine the distance traveled before take-off.

Answers

Distance = 1/2 (a) (t^2)

= 1/2 (3.2) (32.8)^2

= (1.6) x (1,075.84)

= 1,721 meters (rounded)

A student throws a set of keys vertically upward to his fraternity brother, who is in a window 4.00 m above. the brother’s outstretched hand catches the keys 1.50 s later. (a) with what initial velocity were the keys thrown? (b) what was the velocity of the keys just before they were caught?

Answers

a) 10.0 m/s b) -4.7 m/s The formula for distance under constant acceleration is d = 0.5AT^2 The formula for distance with a specified velocity is d = VT So the distance the keys travel with an initial velocity and under constant acceleration by gravity is d = VT - 0.5AT^2 The acceleration due to gravity is 9.8 m/s^2 and the time T is 1.50 s, and finally, the distance traveled is 4.00 m. So substitute those values into the equation and solve for V d = VT - 0.5AT^2 4.00m = 1.50s * V - 0.5 * 9.8 m/s^2 * (1.5s)^2 Do the multiplications 4.00m = 1.50s * V - 4.9m/s^2 * 2.25 s^2 Cancel the s^2 terms 4.00m = 1.50s * V - 4.9m * 2.25 Do the multiplication 4.00m = 1.50s * V - 11.025m Add 11.025m to both sides 15.025m = 1.50s * V Divide both sides by 1.50s 10.01667 m/s = V Since we have 3 significant figures in the data, round results to 3 significant figures. V = 10.0 m/s So the keys were initially thrown upwards with a velocity of 10.0 m/s Since it took 1.50 seconds from launch to catch, the velocity of the keys will decrease by 9.8 m/s^2 times the time. So V = 10.0 m/s - 1.50s * 9.8 m/s^2 V = 10.0 m/s - 14.7 m/s V = -4.7 m/s So at the time the keys were caught, they were moving downward at a velocity of 4.7 m/s


60 POINTS ANSWER CORRECTLY
Which statement best describes charge A and charge B in this diagram?

A ) The signs on charges A and B are opposite. The amount of charge on A is greater than that on B.

B ) The signs on charges A and B are opposite. The amount of charge on A is less than that on B.

C ) The signs on charges A and B are the same. The amount of charge on A is greater than that on B.

D ) The signs on charges A and B are the same. The amount of charge on A is less than that on B.

Answers

Your answer will be A The signs on charges A and B are opposite. The amount of charge on A is greater than that on B.

The answer is A The amount of charge on A is greater than that on B.

When you stand at rest on a bathroom scale, how does your weight compare with the support force by the scale?

Answers

It is equal. The force downward is supported by the scale spring and the scale spring pushes back on you as much as you are pushing back on it, and that is how it reads your weight.
Final answer:

When you stand at rest on a bathroom scale, your weight and the scale's support force are equal but opposite in direction, according to Newton's Third Law. Your weight, which is the force of gravity acting on your mass, presses down on the scale, and the scale pushes back up with equal force. This balance means that you are not accelerating, and the scale correctly reflects your actual weight.

Explanation:

The question you're asking is really about the principles of Physics, particularly those involving forces and weight. When you stand at rest on a bathroom scale, your weight and the support force by the scale are equal in magnitude but opposite in direction. This is due to Newton's Third Law, which states that for every action, there is an equal and opposite reaction. Simply put, your body presses down on the scale (action), and the scale pushes back with equal force (reaction).

The weight we refer to here is actually the force of gravity acting on your mass. It's worth noting that this force would change if the force of gravity changes, for instance, if you were to stand on a scale on the moon. However, when you're standing on a scale on Earth, your weight and the scale's support force are balanced, meaning you are not accelerating and the reading on the scale reflects your actual weight.

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What forces below earth's surface shape landforms?

Answers

The tectonic plates below earths surface shape earths landforms

What is the longest wavelength of radiation that possesses the necessary energy to break the bond 941?

Answers

Energy is calculated by molecule dividing energy by mole by Avogadro's number (6.022*10^23) 941kJ=9.41*10^5 J so energy by molecule E= 9.41*10^5/6.022*10^23=1.563*10^-18 J Wavelength (w) given by E=hc/w where, E = energy h = planks constant (6.6262 x 10-34 J·s) c = speed of light (3 x 10^8 m/s ) So, w= hc/E = (6.6262*10^-34)*(3*10^8) /1.563*10^-18 = 127.2 Nm Longest wavelength of radiation =127.2 Nm

Celina has a water sample that’s contaminated with salt and microorganisms. Which method should she use to purify the water? distillation filtration osmosis reverse osmosis

Answers

reverse osmosis. I know this because in my home, i have R.O. water which means reverse osmosis. It is water that has been filtered. 

Answer:

The answer is reverse osmosis!

Explanation:

I chose this on a test and got it right


Which of the following is an organic compound?

Answers

The answer is D if im correct

Answer:

D

Explanation:

In order to be classified as an organic compound, the compound must contain carbon. Of the options available, only option D includes a sample that contains carbon.

Organic compounds often contain C, H, and O atoms, such as ethanol, CH₃OH.

A negatively charged rubber rod can pick up small, neutrally charged pieces of paper by a process called

Answers

Final answer:

A negatively charged rubber rod can pick up small, neutrally charged pieces of paper through polarization, causing a redistribution of charges within the paper. This induces a dipole moment, leading to attraction despite the paper's overall neutral charge.

Explanation:

A negatively charged rubber rod can pick up small, neutrally charged pieces of paper by a process called polarization. This phenomenon occurs because the negatively charged rod causes a redistribution of charges within the neutral paper, inducing a dipole moment. The paper, though overall neutral, has its charges slightly shifted: the side closer to the rod becomes positively charged due to the attraction of electrons towards the rod, and the far side becomes more negatively charged. The closer, positively charged side of the paper is then attracted more strongly to the negatively charged rod than the repulsion experienced by the more distant, negatively charged side, resulting in the net attraction of the paper to the rod. This effect is not limited to rubber rods and paper; it can be demonstrated with various insulators and small objects. The key to this attraction is the electrostatic force and the principle that opposite charges attract. The rubber rod, after being charged (usually by friction with another material like fur), exhibits this charge inducing behavior due to the presence of excess electrons. Some molecules, like water, are naturally polar and show greater polarization effects than molecules with naturally uniform charge distributions when in the presence of charged objects. Thus, the same principle applies to the attraction of neutrally charged objects that have polar molecules.

what is the difference between ram express and tradesman

Answers

Differences appear to be largely cosmetic. The Tradesman is a basic model, while the Express is slightly more “tricked out” on the interior.

HELP ASAP!! DUE TOMORROW!! WILL MARK AS BRAINLIEST IF ANSWERED NOW!!

Answers

Sorry, I’m only completely sure about 3 and 5.

3.) D. All of the above
5.) Blood type, though only class evidence, can help to lower the list of suspects as not everyone has the same blood type.
1 - B
2 - A 
i think they may be right
but sorry this is all i could do hope this helped

Explain how the position of the moon relates to the occurrence of high tides and low tides?

Answers

The closer the moon is to earth, the greater the moon’s gravity pulls on earth causing high tides. Low tides occur between two high tides.

There are 2 high tides and 2 low tides on most days. 

A high tide occurs near the point directly "under" the moon AND at the point on the opposite side of the earth.. 

Low tide occurs near the time when the moon is near the horizon. 


A more detailed answer:

The high and low tide are caused by the gravitational forces between the earth and the moon. However, the source of the real effect takes some explaining to grasp. The incorrect way of thinking is that the moon attracts all the water to itself, therefore causing a high tide on the side of earth close to the moon, and a low tide on the side far from the moon. However, if this was the case, there would be a high tide once per day. But there are TWO high tides a day. The reason is, the part of the earth both AWAY from the moon, and CLOSE to the moon BOTH get high tides... 

This is because the earth and the moon rotate around each other, each pulling the other towards itself. The moon attracts every piece of matter on earth. Since gravity is inversely proportional to the square of the distance, this force is greater on the side of the earth closer to the moon, and lesser on the side of the earth further from the moon. Since the earth is quite a rigid object, this difference in forces fails to deform the earth (much). However, it succeeds quite well in deforming the oceans -- which are not as rigid. Since the waters on the moon side are attracted more strongly than average, they tend to bulge TOWARDS the moon, hence causing a high tide. The waters on the opposite side of the moon, since they are attracted less strongly than average, tend to 'lag behind' the rigid earth, and bulge AWAY from the moon, which in this case, is also AWAY from the earth, again, causing a high tide. Low tide occurs at about right angles to the moon, where the force on the waters match the average pull of the moon on the earth closely. 

Which force puts an object into free fall?

Answers

Answer:

Gravity

Explanation:

When we say that object is in free fall then it always means that the object will move under the influence of gravitational force only

So here we can say that

under free fall condition the force on the object is given as

[tex]F = mg[/tex]

so the acceleration of free fall is always constant and given as

[tex]a = \frac{F}{m}[/tex]

[tex]a = \frac{mg}{m}[/tex]

[tex]a = g[/tex]

so correct answer is

Gravity

Select the statement that best describes how the forces relate. (2 points)
Select one:
a. All forces begin equally and become varied. The object on which they are acting and the distance to that object determines the amount of force.
b. Weak nuclear and magnetic forces are different because magnetic forces are associated with unmoving charges, and weak nuclear forces are associated with moving charges.
c. All forces are related to the mass of the object on which they are acting. The larger the mass, the weaker the forces become.
d. Magnetic and electrical forces are similar because they are both related to the interactions between charged particles.

Answers

"D. Magnetic and electrical forces are similar because they are both related to the interactions between charged particles" best describes how the forces relate.
your answer would be d

The height of an average adult person is closest to

Answers

6 foot I hope I helped

The global average height for an adult male is 171 centimeters (5 feet 7 inches) and the average height for an adult female is 159 centimeters (5 feet 2 inches).

What is the average height?

It is important to note that these are just averages and there will be a range of heights within each country. For example, in the United States, the shortest 10% of men are less than 163 cm (5 ft 4 in) tall and the tallest 10% of men are more than 185 cm (6 ft 1 in) tall. The same is true for women.

The average height of an adult person has been increasing over time due to a number of factors, including improved nutrition and better healthcare.

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Bob is pulling a 30 kg filing cabinet with a force of 200 n, but the filing cabinet refuses to move. the coefficient of static friction between the filing cabinet and the floor is 0.80. what is the magnitude of the friction force on the filing cabinet?

Answers

Final answer:

The magnitude of the friction force opposing the filing cabinet is 200 N, equal to the applied force, since it does not exceed the maximum static frictional force of 235.2 N calculated using the coefficient of static friction and the normal force.

Explanation:

The magnitude of the friction force on the filing cabinet can be determined by using the coefficient of static friction and the normal force acting on the cabinet. Since the cabinet is not moving, the static frictional force will be equal to the force applied until it reaches its maximum value, which can be calculated as μs N, where μs is the coefficient of static friction and N is the normal force. The normal force is equal to the weight of the cabinet (mass times the acceleration due to gravity, g). For a 30 kg filing cabinet, the normal force N is equal to 30 kg × 9.8 m/s², which equals 294 N. Hence, the maximum static frictional force is 0.80 × 294 N = 235.2 N. Since the cabinet does not move when a 200 N force is applied, the frictional force opposing it is also 200 N, which is less than the maximum static friction of 235.2 N.

Final answer:

The friction force on the filing cabinet is 200 N, which is the same as the applied force and within the maximum static friction value given by the coefficient of static friction multiplied by the normal force.

Explanation:

The magnitude of the friction force on the filing cabinet can be found by using the coefficient of static friction and the normal force. The normal force is equal to the weight of the cabinet, which is the mass (30 kg) multiplied by the acceleration due to gravity (9.8 m/s²). This gives a normal force of (30 kg)(9.8 m/s²) = 294 N. The maximum static friction force can be calculated with the formula fs(max) = μs N, where μs is the coefficient of static friction and N is the normal force. Since the cabinet doesn't move, the static friction force must equal the applied force up to its maximum value, which is determined by the coefficient of static friction (0.80).

Therefore, the maximum static friction force that can act on the filing cabinet is fs(max) = (0.80)(294 N) = 235.2 N. Since 200 N is being applied to move the cabinet, and it does not move, the friction force acting on the cabinet is 200 N, which is the same as the applied force and less than the maximum static friction force.

A ball is tossed straight up with an initial velocity of 13.6 m/s. A) how high will it go? B) how long is the ball in the air?

Answers

A: 9.4248 m B: 2.773 s A ball tossed in to the air at 13.6m/s will experience a constant acceleration due to gravity of 9.81m/s^2. It will reach a 0 velocity at 13.6m/s^2 / 9.81m/s^2 = 1.386 s from the time it was thrown. It will fall to the ground another 1.386 seconds giving a total time in the air of 2*13.6m/s^2 / 9.81m/s^2 = 2.773 s To calculate the maximum height of the ball we use the fact that acceleration is constant. Between being thrown and reaching the maximum height the velocity constantly accelerates from 13.6m/s to 0 which gives an average velocity of 13.6m/s / 2 = 6.8m/s Now that we know average velocity and the time, the distance can be calculated. 1.386s * 6.8m/s = 9.4248m

Calculate the kinetic energy in joules of a 1500 kg automobile moving at 19 m/s

Answers

using
KE = ½mv² = ½×1500×19×19 = 270750 joules

In at least 150 words, discuss how Chang's use of personification, metaphor, or connotation express one his themes in "Garden of My Childhood." Use details from the poem to support your response.

Answers

Poet Kuangchi Chang did not remain in China long enough to be "re-educated." Following the Communist takeover he fled to the United States. His poem "Garden of My Childhood" describes China before the revolution as a peaceful, idyllic garden with a violent horde rapidly approaching. A vine, the wind, and the sea are each personified, and each beckons for him to run. It is not until "eons later," when he is "worlds away," that his "running is all done," and he finds himself at his destination: another garden, just like the one he had left behind.

Answer:

Poet Kuangchi Chang did not remain in China long enough to be "re-educated." Following the Communist takeover he fled to the United States. His poem "Garden of My Childhood" describes China before the revolution as a peaceful, idyllic garden with a violent horde rapidly approaching. A vine, the wind, and the sea are each personified, and each beckons for him to run. It is not until "eons later," when he is "worlds away," that his "running is all done," and he finds himself at his destination: another garden, just like the one he had left behind.

What is the least possible initial kinetic energy in the oxygen atom could have and still excite the cesium atom?

Answers

Final answer:

The minimum kinetic energy needed to excite a cesium atom by a collision with an oxygen atom can be calculated using the conservation of energy principle.

Explanation:

The minimum amount of kinetic energy a particle must have to excite another particle can be calculated using the conservation of energy principle and the equation for kinetic energy. In this case, we are considering the collision between an oxygen atom (O) and a cesium atom (Cs). The formula for calculating the minimum kinetic energy is:

K.E. = (2 * activation energy) + ionization energy

The activation energy is the minimum energy required to initiate the reaction, and the ionization energy is the energy required to remove an electron from an atom. To calculate the specific values for this equation, we need to know the activation energy and the ionization energy of the cesium atom.

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Using the periodic table of the elements, how many valence electrons would helium have?
A. 0
B. 1
C. 2
D. 8

Answers

Helium only has 2 electrons. So the answer is C. 2

If the 37.0-n force continues, the box accelerates at 0.52 m/s2 . what is the coefficient of kinetic friction?

Answers

Final answer:

The coefficient of kinetic friction is approximately 0.176.

Explanation:

To calculate the coefficient of kinetic friction, we need to use the formula:

frictional force = coefficient of kinetic friction × normal force

We also know that the frictional force is equal to the product of mass and acceleration:

frictional force = mass × acceleration

By equating the two expressions for frictional force, we can solve for the coefficient of kinetic friction:

coefficient of kinetic friction = (mass × acceleration) / (mass × gravity)

Plugging in the given values, we have:

coefficient of kinetic friction = (30 kg × 0.52 m/s²) / (30 kg × 9.8 m/s²)

coefficient of kinetic friction ≈ 0.176

Final answer:

The coefficient of kinetic friction is approximately 0.176. To determine this, we can use the formula: frictional force = coefficient of kinetic friction × normal force.

Explanation:

To calculate the coefficient of kinetic friction, we need to use the formula:

Frictional force = coefficient of kinetic friction × normal force

We also know that the frictional force is equal to the product of mass and acceleration:

Frictional force = mass × acceleration

By equating the two expressions for frictional force, we can solve for the coefficient of kinetic friction:

Coefficient of kinetic friction = (mass × acceleration) / (mass × gravity)

Plugging in the given values, we have:

Coefficient of kinetic friction = (30 kg × 0.52 m/s²) / (30 kg × 9.8 m/s²)

Coefficient of kinetic friction ≈ 0.176

Assume that the moon is hit by about 25 million micrometeorite impacts each day, and that these impacts strike randomly around the moon's surface. also assume that after a footprint is hit by 20 micrometeorites it is erased. (a) roughly (order of magnitude) how long do we expect it would take, in years, for one of the footprints left by the apollo astronauts to be completely erased?

Answers

The time required for the footprint left by the Apollo astronaut to be erased is [tex]\fbox{\begin\\1010\,{\text{million}}\,{\text{yr}}\end{minispace}}[/tex].

Further explanation:

Some astronauts went to the moon to know about the moon. They walk on the surface of moon that’s why their footprints left there. It took time to erase the footprints.

Given:

The number of micrometeorites hitting the moon in one day is [tex]25 \times {10^6}[/tex].

The area of footprint is [tex]0.03\,{{\text{m}}^{\text{2}}}[/tex].

The surface area of moon is [tex]3.79 \times {10^{19}}\,{{\text{m}}^{\text{2}}}[/tex].

Concept used:

When footprints hit the surface of moon it got impacted.

The expression for the number of micrometeorites hitting the surface area of footprints in one day is given as.

[tex]\fbox{\begin\\n = \dfrac{N}{{{A_{{\text{moon}}}}}}{A_{{\text{footprint}}}}\end{minispace}}[/tex]                                   …… (1)

Here, [tex]N[/tex] is the number of micrometeorites hitting the moon in one day, [tex]{A_{{\text{moon}}}}[/tex] is the surface area of moon and [tex]{A_{{\text{footprint}}}}[/tex] is the surface area of footprint.

The expression for the time to receive impacts on footprints.

[tex]\fbox{\begin\\T = \dfrac{{20}}{n}\end{minispace}}[/tex]                                                                                 …… (2)

Substitute [tex]25 \times {10^6}[/tex] for [tex]N[/tex], [tex]0.03\, {{\text{m}}^{\text{2}}}[/tex] for [tex]{A_{{\text{footprint}}}}[/tex] and in equation (1).

[tex]\begin{aligned}n &= \frac{{\left( {25 \times {{10}^6}} \right)}}{{\left( {3.79 \times {{10}^{19}}\,{{\text{m}}^{\text{2}}}}\right)}}\left({0.03\,{{\text{m}}^{\text{2}}}\right)\\&=1.979\times{10^{-8}}\\\end{aligned}[/tex]

This means that the footprints receive [tex]1.979 \times {10^{ - 8}}[/tex] number of micrometeorites or impacts per day.

[tex]20[/tex] Impacts are required to erase the footprint in one day.

The expression for the time required to erase the footprints is given in equation (2).

Substitute [tex]1.979 \times {10^{ - 8}}[/tex]for [tex]n[/tex] in equation (2).

[tex]\begin{aligned}T &= \frac{{20}}{{\left( {1.979 \times {{10}^{-8}}}\right)}}\\&=1.010\times{10^9}\,{\text{days}}\\\end{aligned}[/tex]

Thus, it can be given in million years as [tex]\fbox{1010\,{\text{million}}\,{\text{yr}}}[/tex].

Learn more:

1.  Motion of ball under gravity https://brainly.com/question/10934170.

2.  Examples of wind and solar energy https://brainly.com/question/1062501.

3. Conservation of momentum https://brainly.com/question/9575487.

Answer Details:

Grade: College

Subject: Physics

Chapter: Astronomy  

Keywords:

Moon, meteorites, footprints, impact, surface area, 20 impacts, micrometeorites, 25 million  micrometeorites, 1010 million year,1.010*10^9 days .

a push or pull exerted on an object

Answers

Force-a push or pull exerted on an object.
Final answer:

The phrase 'a push or pull exerted on an object' defines the concept of force in Physics. This interaction can change the motion of an object. Force is quantified by Newton's Second Law of Motion.

Explanation:

The phrase 'a push or pull exerted on an object' is a basic definition of the concept of force in physics. Force represents any interaction that, when unopposed, will change the motion of an object. For example, if you push a stationary car, assuming the car is on a level surface and ignoring friction, the car would start to move - you have exerted a force on it. Conversely, if you pull a moving car to a stop, you have also exerted a force.

In more technical terms, a push or a pull on an object is described quantitatively by Newton's Second Law of Motion: Force equals mass times acceleration (F = ma). Here, the force (the push or pull) results in an acceleration of the object, which is directly proportional to the force and inversely proportional to the object's mass.

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What is the wavelength of an infrared wave with a frequency of 4.2 x1014 Hz?

Answers

using
π = c/f
where c = velocity of EM waves in vacuum = 3×10^8 ms-¹
f = 4.2×10^14
π = 3/4.2 ×10^(8-14)
π = 0.714 ×10 ^-6
π = 7.14×10^-5 m

The wavelength of an infrared wave with a given frequency is 7.14 x 10⁻⁵ m.

What is frequency?

Frequency is the number of cycles per second moved by the wave.

The frequency and wavelength is related as

λ = c/f

where c = velocity of sound wave in vacuum = 3×10⁸ m/s

Given is the frequency of the infrared wave f = 4.2×10^14, then wavelength will be

λ = 3 x10⁸ / 4.2 x 1

λ = 7.14 x 10⁻⁵ m

Thus, the wavelength  of an infrared wave with a given frequency is 7.14 x 10⁻⁵ m

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A car drives horizontally off the edge of a cliff that is 40.8 m high. the police at the scene of the accident note that the point of impact is 121 m from the base of the cliff. how fast was the car traveling when it drove off the cliff?

Answers

Fall time machine:
t = √ (2*H/g) = √ (2*40.8 / 9,8) ≈ 2.9 s
Horizontal movement:
S = V₀*t
Speed:
V₀ = S / t = 121 / 2.9 ≈ 41.7 m/s         or  150 km/h

Final answer:

To calculate the speed of the car when it drove off the cliff, we used projectile motion equations to solve for the time it took to hit the ground and then found the horizontal velocity with this time and the given horizontal distance.

Explanation:

To determine the speed at which the car was traveling when it went off the cliff, we can use the kinematic equations for projectile motion. Given that the car falls from a height of 40.8 m and lands 121 m away from the base of the cliff, we can first calculate the time it took for the car to hit the ground using the equation for vertical motion under constant acceleration due to gravity (g = 9.8 m/s²). The vertical motion is independent of the horizontal motion, so:

y = ½ gt², where y is the vertical displacement and t is the time.

Using this equation, we solve for t:

40.8 m = ½ (9.8 m/s²) t²

t = √((2 * 40.8 m) / 9.8 m/s²)

After calculating the time, t, we can then use the horizontal distance travelled and the time of flight to find the horizontal velocity (v):

x = v * t, where x is the horizontal displacement.

Now we substitute the previously calculated time t in the equation to find the horizontal velocity (which is also the initial velocity since there is no horizontal acceleration):

v = x / t

v = 121 m / t

This gives us the car's speed as it left the cliff.

The base unit for mass in the SI system is the?
gram
kilogram
slug

Answers

The right answer is Kilogram.
I hope can help you.

A man weighs 1190 n on earth. what would he weigh on jupiter, where the free-fall acceleration is 25.9 m/s 2 ? the acceleration of gravity is 9.8 m/s 2 . answer in units of n.

Answers

The weight on Jupiter of a man if man weighs 1190 N on earth. Where the free-fall acceleration is 25.9 m / s² is 3144.26 N.

What is acceleration?

Acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration of all other motions.

Given:

The weight of the man, F = 1190 N,

The acceleration, a = 25.9 m / s²,

Calculate the mass of the man by the formula given below,

[tex]F = ma[/tex]

1190 = m × 9.8 m / s²

m = 121.4 kg

Calculate the weight of a man on Jupiter by the formula given below,

[tex]F = ma[/tex]

F = 121.4 × 25.9

F = 3144.26 N

Therefore, the weight on Jupiter of a man if man weighs 1190 n on earth. Where the free-fall acceleration is 25.9 m / s² is 3144.26 N.

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How to find the acceleration of a 20 kg block, going down and to the left (Ф= 37°)
connected, by a pulley, to a 10 kg block accelerating up ?

Theres no friction at all and the pulley is light

Answers

You need to start by considering what forces are on the 20kg block. The 20kg block will have a tension force as well as a gravitational force that are antiparallel to each other. There is also a normal force, but we will not need to consider this since friction is negligible. The equation will be: [tex]m_1a_1 = T - m_1g\cos\phi[/tex], where [tex]m_1 = 20kg[/tex]. From this equation, you can find the expression for acceleration ([tex]a_1[/tex]) by dividing by the mass.

1) mechanical
2) electrical
3) thermal
4) light
5) chemical

In the system, __________ energy from the sunlight causes the solar panel to create __________ energy which flows into the incandescent light bulb. In the light bulb, the ________ energy is transformed into two different types of energy: _________ energy and _________ energy.

Answers

I am pretty sure about these answers.Thermal goes in the 4th blank.
Mechanical goes in the 2nd blank.
Electrical goes in the 3rd blank.
I think chemical goes in the 1st blank and light goes in the 5th blank
Hope this helps
Final answer:

The solar panel absorbs light energy and converts it into electrical energy. When this electrical energy reaches the incandescent light bulb, it is then transformed into thermal energy and light energy.

Explanation:

In the system, light energy from the sunlight causes the solar panel to create electrical energy which flows into the incandescent light bulb. In the light bulb, the electrical energy is transformed into two different types of energy: thermal energy and light energy.

Firstly, the solar panel absorbs light energy, also known as solar energy, and through a process called photovoltaic effect, it transforms this energy into electrical energy. This electrical energy then travels into the incandescent light bulb. Within the bulb, this electric energy is converted into thermal (heat) energy - this is the reason why light bulbs can get very hot. The heat then produces light energy, which is what we ultimately see and perceive as the functioning of a light bulb.

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