write and solve an problem that illustrates the use of the find a pattern strategy. ​

Answer: [tex]\bold{C)\quad y=2sin(x+\dfrac{3\pi}{4})}[/tex]

Step-by-step explanation:

A sin graph is a cosine graph shifted to the left [tex]\dfrac{\pi}{2}[/tex] units.

[tex]y=2cos(x + \dfrac{\pi}{4})\qquad \implies y=2sin(x+\dfrac{\pi}{4}+\dfrac{\pi}{2})\\\\\\.\qquad \qquad \qquad \qquad \quad \implies \large\boxed{y=2sin(x+\dfrac{3\pi}{4})}[/tex]

Answer:

x-7>-15

Step-by-step explanation:

The difference is subtraction.

Greater than is >.

For this case, we must write the expression given algebraically:

The difference of x and 7 can be written as:

[tex]x-7[/tex]

That difference is greater than -15, so the opening of the inequality sign must be on the differencing side, that is:

[tex](x-7)> - 15[/tex]

ANswer:

[tex](x-7)> - 15[/tex]

14$ because you subtract 8 - 36 = 28 then divide 28 by 2 and get 14

36 - 8 = 28 divided by 2 equals 14

Answer:

The value of x is [tex]186\°[/tex]

Step-by-step explanation:

Part 27) we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses

In this problem

[tex]90\°=\frac{1}{2}[x\°-6\°][/tex]

Solve for x

[tex]180\°=[x\°-6\°][/tex]

[tex]x=180\°+6\°=186\°[/tex]

Answer:

Multiply $12.40 times 40. Remember to use a dollar sign in your answer.

Step-by-step explanation:

Answer:

The height of the cone is [tex]4\ in[/tex]

Step-by-step explanation:

step 1

Find the volume of the cylinder

The volume of the cylinder is equal to

[tex]V=\pi (r)^{2}(h)[/tex]

substitute the values

[tex]V=\pi (2)^{2}(3)=12\pi\ in^{3}[/tex]

step 2

Find the height of the cone

The volume of the cone is equal to

[tex]V=(1/3)\pi (r)^{2}(h)[/tex]

Remember that the volume of the cone is equal to the volume of the cylinder

substitute the given values and solve for h

[tex]12\pi=(1/3)\pi (3)^{2}(h)[/tex]

Simplify

[tex]36=9(h)[/tex]

[tex]h=36/9=4\ in[/tex]

Answer:

a=2

h=8

k=-72

Step-by-step explanation:

[tex]y = 2 {x}^{2} - 32x + 56 \\ = 2( {x}^{2} - 16x + 28) \\ = 2( {x}^{2} - 2 \times 8 x + 64 - 36) \\ = 2 {(x - 8)}^{2} - 72 \\ then \: the \: minimum \: is \: - 72 \: and \\ \: the \: x - coordinate \: of \: minimum \: is \: 8.[/tex]

The rewritten equation is 2(x-8)^2 - 100, and the x-coordinate of the minimum is 8.

A quadratic equation is a second-degree algebraic equation in x. The conventional form of the quadratic equation is ax^2 + bx + c = 0, with a and b as coefficients, x as the variable, and c as the constant component.

y = 2x^2 - 32x + 56

y = 2(x^2 - 16x + 28)

y = 2((x^2 - 16x + 64) - 36)

y = 2((x - 8)^2 - 36)

y = 2(x - 8)^2 - 72

The equation when converted in the form  y = a(x - h)^2 + k will look like  y = 2(x - 8)^2 - 72.

The minimum value of this function is y = -72 and the x-coordinate of the minimum is x = 8.

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im not sure but it could be (-2,0) :/

Answer:

(2,0)

The answer is obvious

Answer:

904.36

Step-by-step explanation:

If the radius is 6 and the height is 8 then the answer would be 904.32

This is because the volume formula for a cylinder is pi times radius sqaured times height so if the radius is 6 and the height is 8 then you would do 3.14 times 36 times 8 which would get you 904.36. Also using the formula I just gave you if the diameter is 6 then you would just half it to make the radius. Maybe if I am wrong about which is which for the height being 8 and the radius or diameter being 6 then you could just switch it around in the formula

Answer: ≈904.78

Step-by-step explanation:

V=πr2h=π·62·8≈904.77868

The statements that correctly describe the association between variables A and B are "positive association," "negative association," "nonlinear association," "no association," and "linear association."

Positive Association: Variables A and B have a positive association when an increase in the value of variable A corresponds to an increase in the value of variable B. In other words, as A increases, B also tends to increase, and vice versa. This relationship implies a positive correlation between the two variables.

Negative Association: A negative association between variables A and B occurs when an increase in the value of variable A corresponds to a decrease in the value of variable B, and vice versa. Here, as A increases, B tends to decrease, and vice versa. This relationship signifies a negative correlation between the two variables.

Nonlinear Association: Variables A and B exhibit a nonlinear association when the relationship between them cannot be adequately represented by a straight line. Instead, their connection follows a more complex pattern, such as a curve or some irregular shape. Nonlinear associations can still be positive or negative, but they do not follow a simple linear relationship.

No Association: When there is no association between variables A and B, changes in one variable do not correspond to any predictable changes in the other. In this case, the values of A and B are independent of each other, and there is no correlation between them.

Linear Association: Variables A and B have a linear association when their relationship can be approximated by a straight line. In a linear association, a change in one variable is proportionally reflected in the other variable. This is the simplest form of association and is characterized by a constant rate of change between the variables.

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I am pretty sure 52 degrees

Answer:

the answer is D

Step-by-step explanation:

because the measurements for CAD is 92

Answer:

The center point will be on (-5,3) and the second point will be on (-4,3)

Step-by-step explanation:

25/60 is repeating decimal

hope it helps you!!!!!!!!!

For this case we have that if the box is cubed, then the volume is given by:

[tex]V = l ^ 3[/tex]

Where:

l: It's the side of the cube

We have to:

[tex]l ^ 3 = 2244\\l = \sqrt [3] {2244}\\l = 13,09204886[/tex]

So, l is the side of the box. The surface area of a cube is given by:

[tex]SA = 6l ^ 2\\SA = 6 * (13.09204886) ^ 2\\SA = 1028.41046012[/tex]

Rounding off we have that the surface area of the cube is:

[tex]1028.4 \ in ^ 2[/tex]

Answer:

[tex]1028.4 \ in ^ 2[/tex]

Answer:

1/5

Step-by-step explanation:

we know that

5/10 of the shirts are blue

3/10 of the shirts are green

so

To find how much more of the shirts are blue than green, subtract the fraction of the shirts that are green from the fraction of the shirts that are blue

5/10-3/10=2/10

Simplify

2/10=1/5

do u have the answer

Answer:

13.33%

Step-by-step explanation:

First we need to find the total number of marbles

4 blue marbles+ 3 green marbles+ 7 red marbles+ 1 yellow marble= 15

The probability of a red marble = number of red marbles over the total marbles

P(red) = red/total = 7/15

We keep the marble.  There are now 6 red marbles

4 blue marbles+ 3 green marbles+ 6 red marbles+ 1 yellow marble= 14

We have 14 marbles in the bag

The probability of a blue marble = number of blue marbles over the total marbles

P(blue) = blue/total = 4/14 = 2/7

Then we multiply the probabilities together

P(red,blue0 = 7/15 * 2/7 = 2/15 =.13333333 = 13.33%

Final answer:

The probability of selecting a red marble and then a blue marble from the bag is about 13.33%.Hence, the answer is B.

Explanation:

The probability of selecting a red marble and then a blue marble from a bag that originally contains 4 blue marbles, 3 green marbles, 7 red marbles, and 1 yellow marble involves calculating the probability of two independent events.

First, the probability of selecting a red marble is the number of red marbles over the total number of marbles, so P(Red first draw) = 7/(4+3+7+1) = 7/15.

After selecting a red marble, there is one less marble in the bag, so the new total is 14, and still 4 blue marbles. The probability of then selecting a blue marble is the number of blue marbles over the new total, so P(Blue second draw) = 4/14 = 2/7.

To find the combined probability of both events happening in sequence (red then blue), we multiply the individual probabilities: P(Red then Blue) = P(Red first draw) * P(Blue second draw) = (7/15) * (2/7) = 2/15. Converting this to a percentage gives us approximately 13.33%.

3/10-2/5-3/4 would be least to greatest.

Hope this helps!

Answer:

Graph C on edge

Step-by-step explanation:

I Just did the Assignment

The second graph is the graph of logarithmic function

Logarithmic functions are the inverses of exponential functions. The logarithmic function [tex]y=1og_ax[/tex]is defined to be equivalent to the exponential equation [tex]x=a^y[/tex].

The logarithmic function is similar in shape to the square root function. To graph a logarithmic function it is better to convert the equation to its exponential form.

The second graph is the graph of logarithmic function

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ANSWER

The water arc is 50 ft above the water approximately 42ft and 158ft from the north shore.

EXPLANATION

The water arc is modeled by the function:

[tex]y = - 0.006 {x}^{2} + 1.2x + 10[/tex]

We write this function in vertex form:

[tex]y = - 0.006 ({x}^{2} - 200x )+ 10[/tex]

[tex]y = - 0.006 ({x}^{2} - 200x + ( - 100)^{2} ) - - 0.006( - 100)^{2} + 10[/tex]

[tex]y = - 0.006 ( x- 100)^{2} ) + 60+ 10[/tex]

[tex]y = - 0.006 ( x- 100)^{2} ) +70[/tex]

The vertex of this function is at

(100,70).

This means that the water arc reached a height of 50ft.

We put y=50 and solve for x.

[tex]- 0.006 ( x- 100)^{2}+70 = 50[/tex]

[tex]- 0.006 ( x- 100)^{2} = - 20[/tex]

[tex]( x- 100)^{2} = \frac{10000}{3} [/tex]

[tex]x = 100 \pm \frac{100 \sqrt{3} }{3} [/tex]

x=42.3 or x=157.7

Hence the water arc is 50 ft above the water approximately 42ft and 158ft from the north shore.

The water arc does reach a height of 50 feet, and it is about 42.27 feet and 157.73 feet from the north shore when it is 50 feet above the water.

1.Set up the equation:

[tex]\[ -0.006x^2 + 1.2x + 10 = 50 \][/tex]

2. Simplify the equation:

Subtract 50 from both sides:

[tex]\[ -0.006x^2 + 1.2x + 10 - 50 = 0 \] \[ -0.006x^2 + 1.2x - 40 = 0 \][/tex]

3. Solve the quadratic equation:

We can use the quadratic formula

[tex]\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = -0.006 \), \( b = 1.2 \), and \( c = -40 \).[/tex]

[tex]\[ a = -0.006, \quad b = 1.2, \quad c = -40 \][/tex]

[tex]\[ \Delta = b^2 - 4ac \] \[ \Delta = 1.2^2 - 4(-0.006)(-40) \] \[ \Delta = 1.44 - 0.96 \] \[ \Delta = 0.48 \][/tex]

[tex]\[ x = \frac{-b \pm \sqrt{\Delta}}{2a} \] \[ x = \frac{-1.2 \pm \sqrt{0.48}}{2(-0.006)} \][/tex]

Calculate the square root of 0.48:

[tex]\[ \sqrt{0.48} \approx 0.6928 \][/tex]

  Now, find the two values of x:

[tex]\[ x_1 = \frac{-1.2 + 0.6928}{-0.012} = \frac{-0.5072}{-0.012} \approx 42.27 \] \[ x_2 = \frac{-1.2 - 0.6928}{-0.012} = \frac{-1.8928}{-0.012} \approx 157.73 \][/tex]

Therefore, the water arc reaches a height of 50 feet at approximately [tex]\( x = 42.27 \) feet and \( x = 157.73 \)[/tex] feet from the north shore.

Answer:

It is 0

Step-by-step explanation:

Unlike the positive side of the number line which increases its value as it goes up in numbers, the negative side of a number line increases its value as it goes goes down in numbers as the more closer a negative number is to the positive side of infinity, the greater value it has. In this instance, zero is the greater number than -6 and all other negative numbers.

Answer:

2 + (-6) ÷ 4 ⋅ 4

Step-by-step explanation:

Given in the question an expression,

2 + (3 - 9) ÷ 4 ⋅ 4

First step to solve this problem is to solve the arithmetic which is inside the brackets.

Anything in parentheses always come first when solving a problem.

Answer:

-3y-8 1/2

Step-by-step explanation:

1/4y-13/4y=-12/4y=-3y

1.5+2-12=-8.5 or 8 1/2

Answer:

-17y+13/4y

use m.a.t.h.w.a.y

Step-by-step explanation:

Answer:

Should be (-21/4) (2/3) = -42/12 = -21/6

So answer is  

Esmerelda did not use the reciprocal of the divisor.

Step-by-step explanation:

Answer: Esmeralda added the numerators.

Esmeralda added the denominators.

Esmeralda did not use the reciprocal of the divisor.

Answer:

Graph in the first quadrant because x and y are nonnegative.

Shade the half-plane that does not include the origin since (0, 0) does not satisfy the inequality.

Draw a horizontal line at y = 2 for 2 dogs.

Solutions lie on or below the part of the horizontal line that is in the shaded region.

Step-by-step explanation:

Answer:more than 3

Step-by-step explanation:

i jus did it

1.) x>2

2.)x≤3

3.)x<4

4.)x≥5

Hope this helps:)

The value of x is B. 8.

Answer:

The statement -11 is greater than -3, so it was colder in Milwaukee is true.

Answer:

-11 is greater than -3, so it was colder in Milwaukee.

Step-by-step explanation:

Answer 1 (-11 is greater than -3, so it was colder in Chicago) is incorrect because it was -3 in Chicago, not -11.

Answer 2 (-3 is greater than -11, so it was colder in Chicago) is incorrect because -3 is not greater than -11.

Answer 3 is correct because -11 is greater than -3 and the cities are labeled correctly.

Answer 4 (-3 is greater than -11, so it was colder in Milwaukee) is incorrect because -3 is not greater than -11. Milwaukee was also -11, not -3.

I hope this helps!

First picture = x ≤ 7

Second picture = y = [tex]\frac{x}{3}[/tex] - 1

Third picture = graph d

Hope this helps you

bl.... like... boy love......?

Josef's error will be Josef confused the range and the interquartile range.

The interquartile range is a measurement of a data set's "middle fifty." A range is a measurement of where a set's beginning and end are located.

Given that:-

From the given statement we can conclude that Josef confused the range and the interquartile range.

Therefore Josef's error will be Josef confused the range and the interquartile range.

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