What is the enthalpy change (in kj) for burning 18.0 g of methyl alcohol?

Answers

Answer 1

Final answer:

To calculate the enthalpy change for burning 18.0 g of methyl alcohol, use stoichiometry and the balanced chemical equation for the combustion of methyl alcohol. Convert the mass of methyl alcohol to moles and then use the mole ratio from the balanced equation to determine the moles of products. Finally, multiply the moles of products by the enthalpy change per mole to find the enthalpy change in kilojoules.

Explanation:

The enthalpy change for burning 18.0 g of methyl alcohol can be calculated using stoichiometry. First, convert the mass of methyl alcohol to moles by dividing by its molar mass. Then, use the balanced chemical equation for the combustion of methyl alcohol to determine the ratio of moles of methyl alcohol to moles of products. Finally, multiply the moles of methyl alcohol by the enthalpy change per mole to find the enthalpy change in kilojoules.

For example, the balanced equation for the combustion of methyl alcohol is: 2CH3OH + 3O2 -> 2CO2 + 4H2O

The enthalpy change for this reaction is -726 kJ per mole of methyl alcohol. Therefore, to find the enthalpy change for burning 18.0 g of methyl alcohol, you would follow these steps:

Calculate the number of moles of methyl alcohol.Use the mole ratio from the balanced equation to determine the number of moles of products.Multiply the moles of products by the enthalpy change per mole to find the enthalpy change in kilojoules.


Related Questions

Determine the element of lowest atomic number that contains ten total p electrons in the ground state.

Answers

Final answer:

The first element that has exactly ten p electrons is Neon. However, the first element to have 10 p-electrons in the ground state (including core electrons) is Silicon.

Explanation:

The element of lowest atomic number that has exactly ten p electrons is neon. This is because the periodic table allows us to understand the electron configuration of elements. In the case of Neon (atomic number 10), it fills the 1s, 2s, and 2p orbitals; the 1s and 2s orbitals can hold two electrons each while the 2p can hold six, all for a total of 10 electrons, with the last six being p electrons.

However, if we're seeking the first element to have 10 p electrons in its ground state (including those beyond the Neon atom), the element would be Silicon (atomic number 14). Its electron configuration is [Ne]3s²3p², meaning it has 10 total p-electrons in the ground state: six from the Neon core and four more in the next energy level.

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Given that the solubility product for la(io3)3 is 1.0 x 10-11, what is the concentration of la3+ in a saturated solution of lanthanum iodate answer

Answers

Final answer:

The concentration of La3+ in a saturated solution of La(IO3)3 can be found by setting up and solving a solubility product (Ksp) expression, using the given Ksp value and assuming [La3+] = x and [IO3-] = 3x based on the dissolution stoichiometry of La(IO3)3.

Explanation:

The question relates to the solubility product of lanthanum iodate, denoted by the compound formula La(IO3)3. The solubility product (Ksp) expression is [La3+][IO3-]3 = Ksp. As the dissolution stoichiometry of La(IO3)3 shows that for each formula unit that dissolves, one La3+ ion and three IO3- ions are produced, it can be assumed that [La3+] = x and [IO3-] = 3x. Solving for x in the Ksp expression using these assumptions and the given Ksp value of 1.0 x 10-11 will yield the concentration of La3+ in a saturated solution of lanthanum iodate.

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